similar to: subsetting character vector into groups of numerics

Displaying 20 results from an estimated 20000 matches similar to: "subsetting character vector into groups of numerics"

2010 Jan 10
0
ordering of additional columns in forest plot in meta package
Hi, I am trying to add additional columns to a forest plot using the meta package. The study information and subgroup analysis plotting is handled properly. For this output the data is ordered first by subgroup label (rnd.subgroup1 in the example) and second decreasing size of totals ('n' in the example). The proper ordering of this data is confirmed by the color coding (black and red in
2002 Jul 29
2
How do we omit the coastline using map?
I've been able to do most things I'd like to using the map package, but I can't figure out how to fill a region without drawing a black outline. I can draw the outline in a specified colour, but as soon as I set fill to TRUE, I get a black outline in addition. My map has a lot of activity on the coastline so I don't want a black line obscuring what I do there. A pale colour to
2002 Apr 24
2
Changing the colour in boxplots using bwplot()
I've managed to find how to change trellis.settings$box.rectangle$col and trellis.settings$box.umbrella$col but I can't figure out how to change the colour of the point used to indicate outliers. There doesn't seem to be a general colour. What am I overlooking? best -- ************************************************************* ___ Patrick Connolly {~._.~}
2002 Sep 18
2
More on list to data frame (was: Re: List to Data Frame
Hi, Now suppose I have just one list called FOO, which has 25 objects, e.g.: [[1]] 1 2 3 4 5 [[2]] 6 7 8 9 10 . . . And I want to do something like: FRED <- data.frame(cbind(unlist(FOO[[1]]), unlist(FOO[[2]]), # ... for all 25 subsets )) Is it possible to do this, without doing unlist(FOO[[i]]) 25
2004 Nov 18
4
Re: changing (core) function argument defaults?
&gt;From: Patrick Connolly &lt;p.connolly@hortresearch.co.nz&gt; &gt;To: &quot;RenE J.V. Bertin&quot; &lt;rjvbertin@hotmail.com&gt; &gt;Subject: Re: [R] changing (core) function argument defaults? &gt;Date: Thu, 18 Nov 2004 11:43:10 +1300 &gt; &gt;On Wed, 20-Oct-2004 at 07:48PM +0200, RenE J.V. Bertin wrote: &gt; &gt;|&gt; Hello,
2004 Nov 18
4
Re: changing (core) function argument defaults?
&gt;From: Patrick Connolly &lt;p.connolly@hortresearch.co.nz&gt; &gt;To: &quot;RenE J.V. Bertin&quot; &lt;rjvbertin@hotmail.com&gt; &gt;Subject: Re: [R] changing (core) function argument defaults? &gt;Date: Thu, 18 Nov 2004 11:43:10 +1300 &gt; &gt;On Wed, 20-Oct-2004 at 07:48PM +0200, RenE J.V. Bertin wrote: &gt; &gt;|&gt; Hello,
2003 Apr 22
2
How do I get 10^4 to become 10000?
Of course, that's as trivial as it gets on the command line, but I can't work out how to get a column of numbers that are entered as "10^5" from its 'character' format into a numeric one? I feel a bit embarrassed asking such a simple question. Too much Easter.... Thanks -- Patrick Connolly HortResearch Mt Albert Auckland New Zealand Ph: +64-9 815 4200 x 7188
2011 Oct 10
1
Multiple imputation on subgroups
Dear R-users, I want to multiple impute missing scores, but only for a few subgroups in my data (variable 'subgroups': only impute for subgroups 2 and 3). Does anyone knows how to do this in MICE? This is my script for the multiple imputation: imp <- mice(data, m=20, predictorMatrix=pred, post=post, method=c("", "", "", "",
2002 Apr 18
2
Background in lattice plots using dotplot()
platform i586-pc-linux-gnu arch i586 os linux-gnu system i586, linux-gnu status major 1 minor 4.1 year 2002 month 01 day 30 language R I can't seem to get rid of the slightly green background when I use dotplot(). It shows on the screen in the
2003 Apr 22
4
Default value for title in postscript function
I like the fact that the postscript function enables the possbiility of a more useful title than before. However, I'd prefer the default to be the file name. It's very simple for me to make my own postscript function that does just that simply by setting title = file. I always use onefile = TRUE, so it always works (so far). However, I'm a little reluctant to do that in case some
2003 Apr 22
4
Default value for title in postscript function
I like the fact that the postscript function enables the possbiility of a more useful title than before. However, I'd prefer the default to be the file name. It's very simple for me to make my own postscript function that does just that simply by setting title = file. I always use onefile = TRUE, so it always works (so far). However, I'm a little reluctant to do that in case some
2003 Nov 24
2
1.8.1 and subsetting dataframes
I've encountered something that didn't arise using earlier versions of R (Linux). A dataframe is created and new columns added to it by doing calculations using apply with various functions on some of the original columns. It's somewhat too involved to give a toy example that's reproducible. However, the resulting phenemonon can be characterised by the following: Browse[1]>
2003 May 05
1
Matrix manipulation
I have a square matrix wherein a '*' indicates an HSD between the levels indicated by row name and column name. The '.' is simply marking the diagonal. A blank indicates the same group A B C D E F G H I J K L M N A . B . C * * . D * * . E * * * . F * * * .
2005 Nov 06
1
kinship package example data
I've been looking at the kinship package which looks as though it might be appropriate for my purposes. What I can't find is any reference to the data that is used in the example code. A dataframe called d10 with column names, upn, dadid, momid, sex and affect is required. One can get an idea of what sort of values should be in most columns from the description in the pedigree function,
2004 Dec 21
4
Removing trailing spaces
Some years ago when I used S-PLUS, I seem to remember, there was a discussion about a simple method of removing trailing spaces from vector elements. I'd be fairly sure the same would work in R, but I can't find any mention of anything like it in the R archives or with help.search(). There are ways I could do it with substring(), but I seem to remember there was something more elegant.
2002 Oct 09
1
grid graphics and par settings
I see that adj is not a graphical parameter that can be used in a key list to use with lattice functions. Is that because it's not yet implemented in gpar? If so, it could also explain why it's not available in grid.text. Is there a work around? Centering looks silly on my plot. best -- Patrick Connolly HortResearch Mt Albert Auckland New Zealand Ph: +64-9 815 4200 x 7188
2002 Aug 12
1
Level sets of factors are different (panel.superpose)
I investigated why I was getting this error message... Error in Ops.factor(groups[subscripts], vals[1]) : Level sets of factors are different which led me to putting a browser in panel.superpose: Called from: panel.superpose(x, y, subscripts, ...) Browse[1]> vals vals [1] 1 2 3 Levels: 1 2 3 Browse[1]> groups[subscripts] groups[subscripts] [1] 1 2 3 1 2 1 2 3 1 2 3 1 2 3 Levels: 1 2
2002 Oct 04
1
Does the perl language have an equivalent to browser?
I'm asking on this list because the question will be more easily understood than on a Perl list. Lots of talented people using R also know how to use Perl, so it's easier to ask them. Running a Perl script with the -d switch can do some pretty neat things, but as far as I can tell, every line has to be done individually. Is there a way to specify where to stop in the way browser() does
2002 Apr 28
2
dropterm() in MASS
To compare two different models, I've compared the result of using dropterm() on both. Single term deletions Model: growth ~ days + I(days^0.5) Df Sum of Sq RSS AIC <none> 2.8750 -0.2290 days 1 4.8594 7.7344 4.6984 I(days^0.5) 1 0.0234 2.8984 -2.1722 AND Single term deletions Model: growth ~ days + I(days^2) Df Sum
2003 Sep 01
2
help for performing regressions based on combination of predictors
Dear All, I would like to perform linear regressions based on Y and all of the combinations of the five predictors, i.e.,(y,x1,x2),(y,x1,x3),....,(y,x1,x2,x4,x5),....,(y,x1,x2,x3,x4,x5). Is there any quick way to do it instead of repeat performing regressions for 31 times? Or, is there any method to manipulate the dataset into the 31 combinations? Thanks for your help!