similar to: overlaying plots

Dear R users, I'm having trouble using aggregate() and would greatly appreciate your advice. I am using R 1.5.1 on Windows 2000. I want to call my function in the following way extract.data(x=dat[, "Age", "Year"]) where extract.data() uses aggregate() to count the number of cases for each combination of "Age" and "Year". I've defined

Dear R-guRus: I have a problem with the format of my data in R. Let's say I have a HUGE text table which consists of columns of numerical data, separated by tabs, but in some places rows of text (error messages, etc) are inserted in between rows of numerical data. Because the data file is so huge and because I have thousands of these files, it's unpractical to try and go thru these

Dear R-guRus: I have 2 questions 1) I have 2 variables, e.g. x<-5; y<-"Char" How do I create a new variable which would have both these values in a string (e.g. "5Char", or "5 Char", etc ) ?? 2) if i have an array x[1:100], and I do x[x==345.123], how do I get position j in the array of those x[j] which are equal to 345.123 ? Thank you very much, Vlad.

Subject: Eliminate repeated components from a vector X-Mailer: VM 7.00 under 21.4 (patch 6) "Common Lisp" XEmacs Lucid Reply-To: fjmolina at lbl.gov FCC: /home/f/.xemacs/mail/sent Does anyone know how I can eliminate repeated elements from a vector?

Dear All: I'd like to know how to sort and then index a vector of floats by several levels in R. For example >x<-rnorm(100) > MyLevels<-quantile(x,probs=c(0,.5,1)) > MyLevels 0% 50% 100% -2.11978442 -0.03770613 2.00186397 next i want to replace each x[i] in x by 1,2,3 or 4 depending on which quantile that x[i] falls. How do I do that in a

I hope you could help me with this. I have a dataframe with 5 columns, the first column determining the X values, and the rest four determining four separate Y vectors. How can I plot them on the same graph, overlaying each other? Thanks. Elena Zheleva

Hi I'm observing a huge difference in the performance speed of R on Windows and Unix, even though I know that my Unix machine is much more powerful than my Win machine. In particular, any character processing task is very time consuming on Unix. strptime(x,"%H:%M:%S") is about 10 times slower on Unix for vector x of the length of ~ 500. read.table() also is very slow. is there

Dear R users I use R (1.3.0) Windows version usually with connection to Excel sheets via RODBC Version: 0.8-2. Everything is OK until I use mixed data types (numeric and character) in one column. In that case I will get a particular column of data frame with NA's. Example vzorek lpas apas NA 51.240 20.26 NA 51.340 20.42 NA 49.770 22.05 RB 12 49.840 19.30 RB 12 49.880

Hallo all just a small question I did not find an answer in help pages. Is it possible to use identify() after plotting with plot.POSIX to label points and/or to find out some points? Thanks a lot. Best regards Petr Pikal petr.pikal at precheza.cz p.pik at volny.cz

Dear R users I searched some sources but i did not find an answer.Please give me some hint to following problem. I would like to compute a summary statistic for some vector for different factor levels. I know I can use tapply or aggregate but I do not know if there is a way how to use function with several (two) variable input (like weighted.mean). I wrote a simple a function for factor

Hello all: I have a column of times in format x "16:30:00" "16:30:03" "16:59:00" etc which I need to convert into time variables and do some operations on. I do the command y<-strptime(x,"%H:%M:%S"). This executes almost istantly (for a column x of length 1000 in Windows, but in Unix, where I run my production jobs, this takes over 4 minutes. I

Hello, I have a question about image command. When you draw a image plot, and let's say we use gray scale. then how can I generate a little bar next to the plot which shows the grey levels and the values which corresponds to the grey level? ( it doesn't matter whether I am using grey level or not. It could be just any colors...) The only way that I can do right now is overlaying

Dear users, is anybody of you aware of a R command to perform laplace transform or even its inversion? Thank you very much. Luca

Greetings, Does anyone know how to get an id number in the little header above each individual plot within a trellis plot? The default seems to be to print the word id and add a line indicating on a linear scale where the current id sits. Thanks in advance for any help you can send, Suzette ================================= Suzette Blanchard, Ph.D. Research Scientist Frontier Science

My computer is a pentium 4 running at 2.4 GHz. My R is 1.7.1 I have written a program in R that calls C++. The program spends most of the time in C++ ( > 90% ). R basically deals with output and input. How slower can this be compared with the program I would get from rewriting everything in C++? Thank you.

I'm trying to overlay a density plot on a previously plotted histogram. However, i need to use the same axis as of the 1st(histogram) plot to plot the second. My second plot is creating its own axis and causing my plot to extend the entire histogram instead of getting a subplot on a portion of the histogram. I tried 'fig' and 'new' parameters with no luck. Thanks in advance.

Hi, I am running a loop to plot multiple plots. In s-plus, it shows multiple pages in the graphic window to allow checking on each plot. but in R, the next plot always overwrite the previous one, so i can only have the last plot produced, is there a way to have multiple pages in the graphic window just like S-plus does? Thanks

Dear all I try to persuade if statement in my function to work as I want (but I am not very successful:( My question is why my function with if statement is evaluated correctly in case of atomic variables and incorrectly in case of vector variables. Here is an example: #function with if statement fff <- function(otac,sklon) { test <- (otac *

Dear all I have a function in which I would like to change some values to NA according to some condition. dropout<-function(y, nahr=FALSE,...) { <some stuff for computing an index> if (nahr) y[index]<<-NA invisible(index) } in case y is a vector all works OK but if it is a part of data frame by calling dropout(df$y) or dropout(df[,number]) no change is done. Please can you

Hello everybody. I have a question that has stumped me and the usual "apply" tricks don't seem to work. I run a course where each student's performance is marked by one or more assessors. I have a data frame containing students' names, assessors' names and their marks, arranged as follows: ID student assessor Q1A Q1B Q1C Q2A Q2B Q3 1 2152833