similar to: Any MD5 digests for source files?

Hello, I want to add wireless capability to my Gentoo-linux based firewall/router at home, so I bought a Netgear MA311 PCI and installed the hostap package. I load the hostap_pci module and the wlan0 interface comes up fine. I can detect the signal from a wireless enabled laptop. Now I'm thinking I'm going to bridge the wlan0 interface and the eth1 interface, and run the firewall with br0

My mind has become corrupted by having to use SAS too much. I wanted to calculate the difference of elements of two vectors if the signs are the same. I tried it the corrupted way first: if (effects1[,3] < 0 & effects0[,3] < 0) { imprv1 <- effects0[,3] - effects1[,3] } else if (effects1[,3] > 0 & effects0[,3] > 0) { imprv1 <- effects1[,3] - effects0[,3] } else {

I'm trying to install packages in Gentoo Linux using install.packages(). The packages download fine, but when it comes to installation, I get this message: WARNING: ignoring environment value of R_HOME /var/tmp/portage/R-1.5.1/image//usr/lib/R/bin/Rcmd: /var/tmp/portage/R-1.5.1/image//usr/lib/R/bin/Rcmd: No such file or directory I have the R_HOME set to the correct value (/usr/lib/R), but I

I'm trying to shade part of a density plot. The code I'm trying (using the Old Faithful data as an example) is something like this: # The Old Faithful geyser data data(faithful) d <- density(faithful$eruptions, bw = "sj") plot(d) polygon(d[d$x>4], col = "wheat") I expected that the part of the curve to the right of 4 on the x axis should be shaded, but nothing

I can't remember the programming term -- ``implicit declaration''? Has this changed between 1.4.1 and 1.5? This code used to run as is: for (i in 1:length(diff.time)) { if (diff.time[i] < 16) { total.time[i] <- ifelse(i==1, 7.5, total.time[i-1]) + diff.time[i] last.time[i] <- 0 } else { total.time[i] <- 7.5 last.time[i-1] <- 1 } } Now in 1.5 I

Hello, I'm trying to do a little rlm of some data that looks like this: UNIT COHORT perdo adjodds 1010 96 0.39890 1.06894 1010 97 0.48113 1.57500 1010 98 0.36328 1.21498 1010 99 0.44391 1.38608 It works fine like this: rlm(perdo ~ COHORT, psi=psisquare) But the problem is that I have about 100 UNITs, and I want to do a

Sorry for the way off-topic post, but this list has the highest concentration of statistical computing gurus anywhere. I'm looking for a C routine for efficiently inverting large, sparse matrices (at least 6000 x 6000 and potentially as large as 20,000 x 20,000 with perhaps 80% of the off-diagonal elements empty). I looked in http://gams.nist.gov/serve.cgi/Class/D2a4/ but I have no way of

I seem to remember this coming up before, but I can't find it any messages I've saved or in the archives (searching by subject). I want to rotate mtext so that it's perpendicular to the right side. I tried srt=90 and lots of other values, but it seems to be ignored. Is there a way to do this? ______________________________________________________________________ Stuart Luppescu

I'm stumped with this. When I execute the lines in the function singly, they run fine, but when I run the function, I get this error on the read.table() line: Error in count.fields(file, sep, quote, skip) : can't open file fspci1.dat Can anyone tell my why this should be so? Here is the program: library(rpart) wait <- function(str="Press a key when ready...")

Has the loess.smooth() function changed? It used to work, but now it causes R to abort with a segmentation fault. I stole the function points.lines() from V&R 1st ed. pp. 67--68, but now it only works if I remove the line with loess.smooth. Here's the function I'm using: points.lines <- function(x, y, ...) { cor1 <-round(cor(x, y, use="pairwise"), digits=2)

Colors are real nice, but the publication I'm preparing these barplots for permits only black and white. The Splus plot options ``dbangle'' (or plain ``angle'') and ``density'' (as on p. 65 of MASS 1st ed.) don't seem to be available in R. Is there another way to do this? I'm running R 1.1.0 on Linux (intel). Thanks.

I want to estimate the center of a distribution with lots of outliers in one tail, and thought I would use a function such as S-plus's location.m() with psi.fun=bisquare (as per MASS 3 p. 131). However, R seems not have such a function, so my questions are: 1) Is there an R equivalent to location.m()? 2) Would huber() give me results that are similar (i.e., close enough)? Thanks.

I want to leave a little extra room at the bottom for a legend in a box plot, but I find that the boxplot function ignores ylim. Is there any way around this? Thanks. ______________________________________________________________________ Stuart Luppescu -=-=- University of Chicago $(B:MJ8$HCRF`H~$NIc(B -=-=- s-luppescu at uchicago.edu

I have data on every grade in all elementary schools in Chicago over 5 years. I would like to estimate a trend over time for each grade in each school. There are 17,600 data all together (about 460 schools, nearly 8 grades each, over 5 years). Is there a not-so-hard way to do this in R (I was thinking of using rlm)? ______________________________________________________________________ Stuart

Is the width= parameter in barplot() supposed to work? I couldn't get it to work in my plot, and even in the example, data(VADeaths, package = "base") barplot(VADeaths, width=rep(0.1, 4)) the plot looks identical regardless of what I put in for the width. I looked at the source for barplot() and it looks like it SHOULD work (but what do I know). Am I doing something wrong?

Is there an efficient way to do linear model selection by choosing the model with the highest BIC from all possible models? ______________________________________________________________________ Stuart Luppescu -=-=- University of Chicago $(B:MJ8$HCRF`H~$NIc(B -=-=- s-luppescu at uchicago.edu http://www.consortium-chicago.org/people/sl.html http://musuko.uchicago.edu/pubkey.asc

I would like to make my horizontal barplot vertical axis labels perpendicular to the axis. I tried las=1, srt=90; I even tried yaxt='n' thinking I'd put the labels in using mtext, but the axis continued to be drawn. Can anyone help me with this? My barplot() statement looks like this: barplot(height=foo$rebint[o1], names=foo$Unit[o1], horiz=TRUE, col=mycolors[foo$type[o1]],

I have plain-text data in lower triangular form that I want to read in. Does anyone know of an easy way to do this? ______________________________________________________________________ Stuart Luppescu -=-=- University of Chicago $(B:MJ8$HCRF`H~$NIc(B -=-=- s-luppescu at uchicago.edu http://www.consortium-chicago.org/people/sl.html http://musuko.uchicago.edu/pubkey.asc for PGP

Hello, I'm trying to read data in from a file using scan(). The last field is a character string that contains blanks. I had read it in in S-Plus using this code: ifile <- list(entry=0,measure=0,st=0,count=0,score=0, error=0,inmsq=0,instd=0,outms=0,outstd=0,displc=0,ptbis=0,a=0, r="",name="") if.widths <- c(1, 5, 8, 3, 6, 7, 7, 7, 7, 7, 7, 7, 7, 2,

This is really a question of how to program this *BETTER*. It works as I have done it, but is quite ugly. I want to do a 3d scatterplot of the upper triangle of a matrix, where the z-values are the values in the matrix, and the row and column indices are the y- and x-values. The complete (11 by 11) matrix is mmtop94.2. Here is my awkward code: mmtop94.2[lower.tri(mmtop94.2)] <- NA # Here i