similar to: Interpolating variables into quoted strings

Hello I am new to R and am coming from a Perl background. I have had trouble figuring out from the documentation how to interpolate a variable into a quoted string (if it's possible). This seems to be necessary when writing a script that must print out strings (for example plot legends) whose content is calculated during the execution of the script. In perl I could write: $name =

Hi R User, Would you give me your hand to standardize some columns in a matrix? I have included the example table. > dput(test) structure(list(X = c(1, 2, 3, 4, 5, 6), Y = c(4, 5, 6, 7, 8, 9), temp = c(0.818, 0.113, 0.256, 0.587, 0.955, 0.207), oxy = c(0.797, 0.487, 0.727, 0.128, 0.514, 0.031)), .Names = c("X", "Y", "temp", "oxy"), row.names =

Hi everyone, I am desperately looking for a method to interpolate strings within an SQL statement as follows: I get a lot of rows out of a database (in my example POSITION_to_ZIPCODE Database with holds records for German ZIP Code <--> Gauss-Krueger Coordinate System ) and want this to be selected and computed individually row by row as follows: library(RODBC) channel <-

Hi Guys I am trying to read a bunch of files in the loop but pipe function which I use to cut few columns is somehow unable to interpolate the file variable. eg: > file="check.txt" > data <- read.table(pipe("cut -f 2,3 file"), sep="\t", col.names=c('pos','cov') ) cut: file: No such file or directory how can I pass variable file to pipe

I have a big dataset containing a lot of values for 1970, 1980 and 1990. I want to interpolate values for the years in between, and also if possible to extrapolate to 1968 and 1969. The method doesn't have to be clever but I am looking for a function that will do all the data at once. (Doing foreach, or apply, is just too slow!) Is there something that will take list(df$val.1970, df$val.1980,

Greetings R Users, I?m new to R but at least managed to read in multiple files: filenames <- list.files(path=getwd()) numfiles <- length(filenames) for (all_temp in c(1:numfiles)) { filenames[all_temp] <- paste(filenames[all_temp],sep="") assign(gsub("[.]ASC$","temp",filenames[all_temp]),read.delim2(filenames[all_temp],

Hi everyone I was using spline to interpolate single or two consecutive missing data points in time series. However, when it comes to longer gaps in the data the spline function generate new data for both my known and unknown data (see below). Aside from not understanding why this happens, I thought thought I might try function "aspline" in library (akima). However, I cannot install or

#I would like to interpolate a straight line between 06/08/06 04:16:00 - 06/08/06 20:31:00 with values and then sum them. This is an estimate of ecosystem #respiration and I will be using this in a larger context(48 days of these diurnal curves), but for right now I am just trying to figure out how to do it for this one #day example. I have some other code for Ecosystem (stream) Metabolism that

In accordance with Venables and Ripley, SAS documentation and other sources AIC with sigma^2 unknown is calculated as: AIC = -2LL + 2* #parameters = n log(RSS/n) + 2p For the fitness data: (http://support.sas.com/ctx/samples/index.jsp?sid=927), SAS gets an AIC of 64.534 with model oxygen = runtime. (SAS STAT User's Guide. Chapter 61. pp 3956, the REG Procedure). This value of AIC accords

So I have Need For Speed Porsche Unleased and I have ubuntu 6.06 LTS and I have wine 0.9.90-ubuntu2 which I installed using the package manager . So I simply use wine and I get to play NFS on ubuntu simple right. I install NFS and everything goes fine. I then go to wincfg and add NFS and change it to run in 98. Error one I run the shortcut on my desktop in a terminal and I get this

Dear R-help community, I have looked on the R search site and archives but cannot find mention of a way of interpolating a gaussian distribution of data to a standard 2.5 degree grid. I have two global dataset and I need to correlate - unfortunately one is a 2.5 degree grid dim[longitude=144,latitude=72] and one is gaussian dim[longitude=192,latitude=94]. I would rally appreciate hearing

Thanks to David Meyer [david.meyer@ci.tuwien.ac.at] and David Brahm [brahm@alum.mit.edu] who suggested: m[ cbind(index.i, index.j) ] <- vals This works fine for the example I gave. Unfortunately, this approach doesn't extend to using the row and column names to make assignments: > m <- matrix("",ncol=3,nrow=3) > dimnames(m) <-

Hi, When an audiopacket is received too late I could interpolate this frame. The problem is that I don't know if it is a true bufferloss or just the last audiopacket of a talkspurt. Now my question is if it's harmfull for the audioquality that at the end of the talkspurt one frame is interpolated? Or would this be almost inpossible to hear since the last audiopacket in the talkspurt

The purpose of this email is to ask for pre-built procedures or techniques for smoothing and interpolating missing time series data. I've made some headway on my problem in my spare time. I started with an irregular time series with lots of missing data. It even had duplicated data. Thanks to zoo, I've cleaned that up -- now I have a regular time series with lots of NA's.

Full_Name: Albrecht Gebhardt Version: 0.99.0 OS: alpha, osf4.0 Submission from: (NULL) (143.205.180.40) DEC cc doesn't like c++ style comments // like this one Please use standard cc comments or #if 0 ... #endif A quite large patch follows (I hope it will pass mailing with not too much wrapped lines): --- ./src/main/g_her_glyph.c.dec-cc.patch Mon Feb 7 14:48:10 2000 +++

Hello, I have been getting the following intermittent error from kmeans: >str(cavint.p.r) num [1:1967, 1:13] 0.691 0.123 0.388 0.268 0.485 ... - attr(*, "dimnames")=List of 2 ..$ : chr [1:1967] "6" "49" "87" "102" ... ..$ : chr [1:13] "HYD" "NEG" "POS" "OXY" ... > set.seed(34) >

Hello, I have a column in a data frame that need to be 10 digits long. As such: Decimal.Year 1 1994.25997 2 1994.26020 However, R keeps rounding the digits. As such: Decimal.Year 1 1994.260 2 1994.260 *Is there any way to stop this from happening?* Here is how I created the data frame: x <- read.table('bats_1994_CTD.txt') colnames(x) <-

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Any doubts about R's big-league status should be put to rest, now that we have a Sudoku Puzzle Solver. Take that, SAS! See package "sudoku" on CRAN. The package could really use a puzzle generator -- contributors are welcome! -- David Brahm (brahm at alum.mit.edu) [[alternative HTML version deleted]] _______________________________________________ R-packages mailing list

Hi, i have setted up a DC ESC.LAN, if i try to do "samba-tool domain join MUNICH.ESC.LAN SUBDOMAIN -Uadministrator" i get the following error, how can i build up a AD Subdomain (Domain Tree) [root at MUC-PDC ~]# samba-tool domain join MUNICH.ESC.LAN SUBDOMAIN -Uadministrator Administrator password will be set randomly! Finding a writeable DC for domain 'ESC.LAN' Found DC