Displaying 6 results from an estimated 6 matches similar to: "Contrasts with interactions"
2009 Nov 22
0
Repeated measures unbalanced in a split-split design
Hi,
I have a experiment with block, plots, sub-plots, and sub-sub-plots
with repeated measures and 3 factors (factorial design) when we have
been observed diameter (mm), high (cm) and leaves number (count).
However, we don't have one treatment in one factor, so, my design is
unbalanced.
On a previous message here, a friend tell me that "It appears to me
that your design is a split-split
2002 Aug 06
2
AOV in MASS not the same??
I would appreciate it if someone could explain the results of the
example from the aov() help file. The output given below is different
from book
Venables and Ripley - MASS
The results In R1.5.1 (Under windows) is as follows:
> N <- c(0,1,0,1,1,1,0,0,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,0)
> P <- c(1,1,0,0,0,1,0,1,1,1,0,0,0,1,0,1,1,0,0,1,0,1,1,0)
> K <-
2008 Sep 17
1
ANOVA contrast matrix vs. TukeyHSD?
Dear Help List,
Thanks in advance for reading...I hope my questions are not too ignorant.
I have an experiment looking at evolution of wing size [centroid] in
fruitflies and the effect of 6 different experimental treatments
[treatment]. I have five replicate populations [replic] in each
treatment and have reared the flies in two different temperatures [cond]
to assay the wing size, making
2010 Apr 21
1
How to obtain the coefficients from a summary of aov ?
Dear Madame, Dear Sir,
I am able to obtain the coefficients from a 'summary' of 'lm', but NOT from a 'summary' of 'aov'.
The following example shows my steps.
## Initialize
rm(list = ls()) # remove (almost) everything in the working environment
utils::data(npk, package="MASS") # get data
model <- yield ~ block + N*P*K
## Using lm
npk.lm <-
2013 Jun 30
0
Help: argument is not numeric or logical: returning NA
Hi,
One problem with your example dataset is that you have 11 list
elements with the last one having different dimensions.? I think it was
based on `summarized`.
Then, the second problem I encountered for testing is that the dataset you provided doesn't fulfill the criteria.
lst1<- list(structure(list......) #output of dput
?
lst2<- lst1[1:10] #deleted the last list element
2009 Feb 23
1
Interleave or not
Lets say you had 4 servers and you wanted to setup replicate and
distribute. What methoid would be better:
server sdb1
xen0 brick0
xen1 mirror0
xen2 brick1
xen3 mirror1
replicate block0 - brick0 mirror0
replicate block1 - brick1 mirror1
distribute unify - block0 block1
or
server sdb1 sdb2
xen0 brick0 mirror3
xen1 brick1 mirror0
xen2 brick2 mirror1
xen3 brick3 mirror2
replicate block0 -