similar to: Contrasts with interactions

Displaying 6 results from an estimated 6 matches similar to: "Contrasts with interactions"

2009 Nov 22
0
Repeated measures unbalanced in a split-split design
Hi, I have a experiment with block, plots, sub-plots, and sub-sub-plots with repeated measures and 3 factors (factorial design) when we have been observed diameter (mm), high (cm) and leaves number (count). However, we don't have one treatment in one factor, so, my design is unbalanced. On a previous message here, a friend tell me that "It appears to me that your design is a split-split
2002 Aug 06
2
AOV in MASS not the same??
I would appreciate it if someone could explain the results of the example from the aov() help file. The output given below is different from book Venables and Ripley - MASS The results In R1.5.1 (Under windows) is as follows: > N <- c(0,1,0,1,1,1,0,0,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,0) > P <- c(1,1,0,0,0,1,0,1,1,1,0,0,0,1,0,1,1,0,0,1,0,1,1,0) > K <-
2008 Sep 17
1
ANOVA contrast matrix vs. TukeyHSD?
Dear Help List, Thanks in advance for reading...I hope my questions are not too ignorant. I have an experiment looking at evolution of wing size [centroid] in fruitflies and the effect of 6 different experimental treatments [treatment]. I have five replicate populations [replic] in each treatment and have reared the flies in two different temperatures [cond] to assay the wing size, making
2010 Apr 21
1
How to obtain the coefficients from a summary of aov ?
Dear Madame, Dear Sir, I am able to obtain the coefficients from a 'summary' of 'lm', but NOT from a 'summary' of 'aov'. The following example shows my steps. ## Initialize rm(list = ls()) # remove (almost) everything in the working environment utils::data(npk, package="MASS") # get data model <- yield ~ block + N*P*K ## Using lm npk.lm <-
2013 Jun 30
0
Help: argument is not numeric or logical: returning NA
Hi, One problem with your example dataset is that you have 11 list elements with the last one having different dimensions.? I think it was based on `summarized`. Then, the second problem I encountered for testing is that the dataset you provided doesn't fulfill the criteria. lst1<- list(structure(list......) #output of dput ? lst2<- lst1[1:10] #deleted the last list element
2009 Feb 23
1
Interleave or not
Lets say you had 4 servers and you wanted to setup replicate and distribute. What methoid would be better: server sdb1 xen0 brick0 xen1 mirror0 xen2 brick1 xen3 mirror1 replicate block0 - brick0 mirror0 replicate block1 - brick1 mirror1 distribute unify - block0 block1 or server sdb1 sdb2 xen0 brick0 mirror3 xen1 brick1 mirror0 xen2 brick2 mirror1 xen3 brick3 mirror2 replicate block0 -