similar to: multiple "keys" in Trellis plots?

Displaying 20 results from an estimated 4000 matches similar to: "multiple "keys" in Trellis plots?"

2012 Oct 25
2
mean of a value of the last 2 hours
Hello, I have a data frame somewhat like that: myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00"), Hunger=c(1,1,1,2,2,1) ) myframestime <- as.POSIXct (strptime(as.character(myframe$Timestamp),
2012 Nov 27
5
loop with date
Hello, I tried to construct my very first loop today and completly failed :-( Maybe someone can help me? I have a dataframe somewhat like this one: myframe <- data.frame (Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "25.09.2012 09:00", "25.09.2012 10:00", "25.09.2012
2012 Dec 17
2
calculate a "rolling mean" including standard deviation
Hello everyone, I have a data frame somewhat like this one: myframe <- data.frame (Timestamp=c( "24.09.2012 06:00", "24.09.2012 07:00", "24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "24.09.2012 12:00",
2012 Oct 26
0
mean of a value of the last 2 hours using plyr (Thank you)
Hi dear three helpers, Thanks a lot! Your solutions worked great. Again I learned a lot. Tagmarie Am 25.10.2012 18:36, schrieb Felipe Carrillo: > Another option using plyr, > library(plyr) > myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", > "Bert"), Timestamp=c("24.09.2012 09:00",
2012 Dec 07
0
apply a function at: dateX, dateX+1, dateX+2, ....
Dear knowing people, Dennis Murphy helped me a lot with my first loop last week. Thanks again - I could have made more than 10 "Thank-You cakes" in the time it saved me! But now I want to complicate the thing. My ideas didn't work. Let's see if anyone is smarter ;-) The following packages are needed: library(adehabitatHR) library(rgdal) library(plyr) # My dataframe looks
2009 Apr 09
2
better way of recoding factors in data frame?
Hi all, I apologize in advance for the length of this post, but I wanted to make sure I was clear. I am trying to merge two dataframes that share a number of rows (but some are unique to each data frame). Each row represents a subject in a study. The problem is that sex is coded differently in the two, including the way missing values are represented. Here is an example of the merged dataframe:
2002 Aug 06
2
[ and setMethod conflict?
I noticed this oddity about [ and setMethod. First, I define testFunc, which sorts a data frame by the first column and returns the entries that aren't NAs, and testIt, which runs testFunc repeatedly on a random large data frame, each time saving the return into a dummy placeholder (for demonstration's sake). > require(methods) Loading required package: methods [1] TRUE > testFunc
2002 Aug 06
2
[ and setMethod conflict?
I noticed this oddity about [ and setMethod. First, I define testFunc, which sorts a data frame by the first column and returns the entries that aren't NAs, and testIt, which runs testFunc repeatedly on a random large data frame, each time saving the return into a dummy placeholder (for demonstration's sake). > require(methods) Loading required package: methods [1] TRUE > testFunc
2002 Jul 19
1
Rprof and setMethod conflict?
I noticed this oddity about R profiling and setMethod. First, I "test out" Rprof. > require(methods) Loading required package: methods [1] TRUE > > Rprof("test.out") > data.frame("a") X.a. 1 a > Rprof(NULL) So far, so good. Next, I define myClass. > setClass("myClass", representation(mySlot = "numeric")) [1]
2002 Aug 26
1
Rprof and setMethod conflict (PR#1949)
Full_Name: Kevin C. Bartz Version: 1.5.1 OS: Solaris 2.6 Submission from: (NULL) (192.223.226.5) A while ago, I noticed this oddity about R profiling and setMethod. First, I "test out" Rprof. > require(methods) Loading required package: methods [1] TRUE > > Rprof("test.out") > data.frame("a") X.a. 1 a > Rprof(NULL) So far, so good. Next, I
2009 Jul 01
2
?max (so far...)
Hi, I have a data.frame that is date ordered by row number - earliest date first and most current last. I want to create a couple of new columns that show the max and min values from other columns *so far* - not for the whole data.frame. It seems this sort of question is really coming from my lack of understanding about how R intends me to limit myself to portions of a data.frame. I get the
2009 Jun 30
2
Using functions to change values in a data.frame
I'm having trouble with something that looks easy. (And I'm sure it will be easier within about 1 minute of receiving my first response.) Thanks in advance. I have a collection of data frames that I need to add columns, do some calculations and then fill in the new columns. Since I have a large number of similar data frames I want to do this with functions to make the code more readable
2009 Jul 01
1
running count in data.frame
Hi, I need to keep a running count of events that have happened in my data.frame. I found a document called usingR that had an example of doing this for random coin flips and I tried to modify it. It seems to sort of work in the beginning, but then it stops and I don't understand why. I'm trying to duplicate essentially the Excel capability of =SUM($A$1:$A(Row number)) The example
2012 Sep 26
2
average environmental data if AnimalID and Time is duplicated
Hello, I tried for about three hours now to solve this problem but I can't figure it out. I am sure someone knows how do it. At least I hope so. I have a data frame somewhat like this: myframe <- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 09:00", "24.09.2012 10:00",
2011 Mar 30
2
summing values by week - based on daily dates - but with some dates missing
Dear everybody, I have the following challenge. I have a data set with 2 subgroups, dates (days), and corresponding values (see example code below). Within each subgroup: I need to aggregate (sum) the values by week - for weeks that start on a Monday (for example, 2008-12-29 was a Monday). I find it difficult because I have missing dates in my data - so that sometimes I don't even have the
2017 Aug 19
0
My very first loop!! I failed. May I have some start-up aid?
Thank you for providing the example code... for the request of running it multiple times it would have helped if you could have confirmed that the example ran through without errors... there were a lot of mistakes in it. Look into using the reprex package to check your example next time. I don't do this kind of analysis... I really don't know what to expect from the functions. The
2010 Aug 13
3
transforming dates into years
Hello! If I have in my data frame MyFrame a variable saved as a Date and want to translate it into years, I currently do it like this using "zoo": library(zoo) as.year <- function(x) as.numeric(floor(as.yearmon(x))) myFrame$year<-as.year(myFrame$date) Is there a function that would do it directly - like "as.yearmon" - but for years? Thank you! -- Dimitri
2012 Nov 09
3
if between 500-600 give 550
I have a data frame somewhat like this: myframe <- data.frame (ID=c(2,3,4,5), Hunger =c(415,452,550,318 )) myframe Now I would like to add a column to the right which summarizes the values for Hunger somewhat to reduce the number of values: If the values for Hunger are between 300-400 I would like to insert the number 350, between 400-500 insert 450 between 500-600 insert 550 Does
2010 Jan 12
3
How to get minimum value by group
I'd like to get a long data set of minimum values from groups in another data set. The following almost does what I want. (Note, I'm using the word factor differently from it's meaning in R; bad choice of words) myframe = data.frame(factor1 = rep(1:2,each=8), factor2 = rep(c("a","b"),each=4, times=2), factor3 = rep(c("x","y"),each=2, times=4),
2009 May 14
1
Problem with viewports, print.trellis and more/newpage
Dear R-users, I have got the following problem. I need to create 4x2 arrays of xyplot's on several pages. The plots are created within a loop and plotted using the print function. It seems that I cannot find the proper grid syntax with my viewports, and the more/newpage arguments. The following script is a simplification but hopefully will suffice to illustrate my problem. Any suggestion