similar to: problem with toString

Dear R-help Listers, I am curious if there is some (hopefully easy) way to change the number of characters that can be converted to a single string via any of deparse, as.character or toString. It seems that the limit is 500 for all of these. I saw a previous post where Prof. Ripley suggested that it was a "trivial" change in the R internals to change as.character's limit from 60

Hello there, I want to create a string from strings and numbers, here is my code: str <- "name" & toString(20) but it returns me this error: Error in toString(20) : could not find function ".jcall" what did I do wrong? I couldn't find this error anywhere... -- View this message in context: http://n4.nabble.com/Error-with-toString-tp1290327p1290327.html Sent from

Hi all, I got a problem with * "toString()"* function its behaving odd in some times most of the times its giving correct results but in peculier cases its giving results like *"愭]"* especially while i am working with c# +R-project thats also after getting some error like after trying to caliculate "*mean("NA")" * can any one help me why its

Hello, I have an expression "a" in R that has about 2300 characters and I want to convert it to a string using toString or as.character. The problem is I am only getting the first 500 or so characters when I convert it to string. I tried to use substring in order to convert one bunch at a time, but when I type substring(a, 498, 1000) I get only 2 characters, meaning it seems there is a

Hi! I wonder if llvm::APFloat::toString() can be const since it should not modify the APFloat. -Jochen

Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",

Derar Rxperts, I have a strange situation.. I see curly brackets around "strip.levels" in multipanel strips while using lattice::xyplot. .How do I get rid of the curly brackets? For some reason, I am not able to reproduce the problem using an example below... Any suggestions are highly welcome! Thanks, Santosh q <-

any suggestions on the following gratefully welcome, I have a dataframe, which I am subsetting via labels atpi[, creativity] where (for example) atpi = as.data.frame(matrix(1:50, ncol = 5, nrow = 10)) names(atpi) = c("Q1", "Q2", "Q3", "Q4", "Q5") and creativity = c("Q1", "Q3", "Q4") I want to add an extra column

Greetings! I want to have the coefficients that R uses in shapiro.test() for the Shapiro-Wilk test for a prticular sample size, i.e. the a[i] in W = Sum(a[i]*x[i])/(Sum(x[i] - mean(x))^2) (where the x[i] are sorted). Two questions: Q1: Is there a readymade R function from which I can extract these? Q2: I was wondering if I might be able to modify the code for the function shapiro.test() so

On Mar 6, 2010, at 3:39 AM, Jochen Wilhelmy wrote: > Hi! > > I wonder if llvm::APFloat::toString() can be const since > it should not modify the APFloat. Done in r97883, thanks.

The following dummy data frame has factor Q (with 2 levels) nesting factor P (with levels p1 and p2 nested under q1, and p3 and p4 nested under q2), but both crossing the random variate s, which has 8 levels. The dependent measure is dv. > # The data frame: > testnest dv s P Q 1 1 s1 p1 q1 2 2 s2 p1 q1 3 1 s3 p1 q1 4 2 s4 p1 q1 5 1 s5 p1 q1 6 3 s6 p1 q1 7 3 s7

Dear R-help, I wonder if you could give me some suggestions in how to do a union join of two data frames as follow: -> union join the common column, and insert a 0 if one is missing. I made a function to perform the following, and I know it may not that quite welly written, but it works. Any suggestions are welcome, many thanks. Anthony > q1 =

sample report data that i want to forecast quarter quarter_index Revenue 2007 Q1 1 $3,856,799 2007 Q2 2 $4,243,328 2007 Q3 3 $4,930,369 2007 Q4 4 $5,443,579 2008 Q1 5 $5,164,830 2008 Q2 6 $5,104,413 2008 Q3 7

sample report data that i want to forecast quarter quarter_index Revenue 2007 Q1 1 $3,856,799 2007 Q2 2 $4,243,328 2007 Q3 3 $4,930,369 2007 Q4 4 $5,443,579 2008 Q1 5 $5,164,830 2008 Q2 6 $5,104,413 2008 Q3 7

Example: Will ts objects be obsolete or modified? > a [,1] 1983 Q1 2.747365190 1983 Q2 2.791594762 1983 Q3 -0.009953715 1983 Q4 -0.015059485 1984 Q1 -1.190061246 1984 Q2 -0.553031799 1984 Q3 0.686874720 1984 Q4 0.953911035> lag(a,4) [,1] 1983 Q1 NA 1983 Q2 NA 1983 Q3 NA 1983 Q4 NA 1984 Q1 2.747365190 1984 Q2

I have a data.frame named "df". The dput of df is at the bottom of this e-mail. What I'd like to do is replace the "n/a " values with NA. On Mac OSX, it works to do this: df[df == "n/a"] <- NA However, it does not work on Ubuntu. See below. Thanks in advance, Garrett > x <- df[27, 4] # complete data.frame dput is below > dput(x) "n/a?"

Greetings, I'm learning R and I'm stuck on a basic concept: how to specify a logical condition once and then perform multiple transformations under that condition. The program below is simplified to demonstrate the goal. Its results are exactly what I want, but I would like to check the logical state of gender only once and create both (or any number of) scores at once.

I would like to add an extension to the current name of a variable to create a new variable that is its sqrt transform. Each piece of the equation below works independently, but the left side definition fails on run. I also tried creating the variable name first, but ended up with an object that toString() did not fix. Better ideas? Example 1

Hi Guys, I'm using zoo package now. I found lag is not doing what I assumed. > x <- zoo(11:21) > z <- zoo(1:10, yearqtr(seq(1959.25, 1961.5, by = 0.25)), frequency = 4) > x 1 2 3 4 5 6 7 8 9 10 11 11 12 13 14 15 16 17 18 19 20 21 > lag(x) 1 2 3 4 5 6 7 8 9 10 12 13 14 15 16 17 18 19 20 21 > z 1959 Q2 1959 Q3 1959 Q4 1960 Q1 1960 Q2 1960 Q3 1960 Q4

hi, for example, I have an string "q1 q2 q3". how can I encode it in rails to produce the result like "q1%20q2%20q3". Thanks! Best Regards, Zhenjian -------------- next part -------------- An HTML attachment was scrubbed... URL: http://wrath.rubyonrails.org/pipermail/rails/attachments/20060717/3824f992/attachment.html