similar to: variable scope

Displaying 20 results from an estimated 7000 matches similar to: "variable scope"

2002 Aug 06
1
re| `By reference'
David Brahm <brahm at alum.mit.edu> wrote: >VBMorozov at lbl.gov wrote: >> I would like to pass variables to a function in R in "by reference"... >Just in case the ensuing discussion got too esoteric, here's one simple answer: >R> x <- 1:10 >R> MyFunc <- function(x, zz) assign(deparse(substitute(zz)), sum(x), 1) >R> MyFunc(x,y) >R>
2002 Jun 26
3
Help with concatenation and arrays
Dear R-guRus: I have 2 questions 1) I have 2 variables, e.g. x<-5; y<-"Char" How do I create a new variable which would have both these values in a string (e.g. "5Char", or "5 Char", etc ) ?? 2) if i have an array x[1:100], and I do x[x==345.123], how do I get position j in the array of those x[j] which are equal to 345.123 ? Thank you very much, Vlad.
2002 Mar 17
5
compute variance of every column in a matrix without a loop
Is it possible to compute the variance of every column in a matrix without a loop? -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch
2002 May 06
3
Using Object's Name in Function
Hi, Suppose I have a function: myfunc <- function(x, y) { ... } And within the function I want to print out the name of the x, y vectors. For example, if I do: > myfunc(foo, goo) [1] "foo" "goo" It shall return "foo", "goo" (with or without quotes is fine), where foo and goo are two vectors with numbers. I know this sounds strange, but I'd
2002 Jul 17
9
problem formatting data frames
Dear R-guRus: I have a problem with the format of my data in R. Let's say I have a HUGE text table which consists of columns of numerical data, separated by tabs, but in some places rows of text (error messages, etc) are inserted in between rows of numerical data. Because the data file is so huge and because I have thousands of these files, it's unpractical to try and go thru these
2004 Sep 09
4
scoping rules
Can someone help me with this simple example? sq <- function() { y <- x^2 y } myfunc <- function() { x <- 10 sq() } myfunc() executing the above in R yields: > myfunc() Error in sq() : Object "x" not found I understand that R's scoping rules cause it to look for "x" in the environment in which "sq" was defined (the global environment in
2010 Mar 31
2
Simplifying particular piece of code
Hello, everyone I have a piece of code that looks like this: mrets <- merge(mrets, BMM.SR=apply(mrets, 1, MyFunc, ret="BMM.AV120", stdev="BMM.SD120")) mrets <- merge(mrets, GM1.SR=apply(mrets, 1, MyFunc, ret="GM1.AV120", stdev="GM1.SD120")) mrets <- merge(mrets, IYC.SR=apply(mrets, 1, MyFunc, ret="IYC.AV120",
2002 Jul 01
1
a little statistics help
Dear R-guRus: I am stuck with the following problem in R: Let's say i have a data.frame with columns X,Y & Z. X is a column of numbers, Y is a column of N factors "A", "B", "C", "D", etc and Z is a column of n factors "a", "b", "c", etc if i do MyLm<-lm(X~Y*Z - 1) i get all N coefficients for Y-factors, but only
2011 Feb 18
1
debugger() fails if "..." in function arguments
Dear all, I'm having a problem with debugger() in both R 2.8.0 and R 2.12.0. Probably also versions in-between. I don't see it logged in the bug database, but it's hard for me to imagine that no-one else has encountered it. So my question is whether it's a known problem with a workaround, or do I log it as a new problem? The situation is that if I use
2009 Aug 06
1
Using 'field names' of a data.frame in a function
I may be doing this wrong! but I have a function which I have simplified a lot below. I want to pass some 'field names' of a data-frame to the function for it to then do some manipulation of. Here's my code: #build a simple dataset mydataset = data.frame (
2002 Oct 21
2
overlaying plots
Dear R-gurus: How do I overlay 2 plots in the same frame in R? Or, if I have a histogram, and I want to plot a function in the same frame - how do I do it? Thank you very much, Vlad -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or
2011 Jan 10
2
Integration in R
Dear all, It has been ages since I studied integration in college. Right now I try to recover all this kind of knowledge and then try to understand how integration works. Thus I am doing some first 'experiments' and I would like to request your help and comments. I have the function: p2<-function(x){0.5*(3*x^2-1)} # I found the square of p2 by using some pencil and
2006 Nov 09
3
function
R-help, I am trying to create a function that i pass a data set to and have the function return some calculations based on data. Allow me to illustrate: myfunc <- function(lst,mn,sd){ lst <- sort(lst) mn <- mean(lst) sd <- sqrt(var(lst)) return(lst,mn,sd) } data1 <-c (1,2,3,4,5) data2 <- c(6,7,8,9,10) myfunc(data1,data1mn,data1sd) myfunc(data2,data2mn,data2sd)
2012 Aug 29
5
Extracting the name of a function (inverse of match.fun("myFun"))
Hi all, is there a way to extract the name of a function, i.e. do the reverse of match.fun applied to a character string? I would like to print out the name of a function supplied to another function as an argument. For example: myFunc = function(x) { x+1 } applyFunc = function(fnc, x) { fnc = match.fun(fnc) fnc(x) } Is there a way to obtain "myFunc" from the argument fnc in
2008 Mar 27
1
A faster way to compute finite-difference gradient of a scalar function of a large number of variables
Hi All, I would like to compute the simple finite-difference approximation to the gradient of a scalar function of a large number of variables (on the order of 1000). Although a one-time computation using the following function grad() is fast and simple enough, the overhead for repeated evaluation of gradient in iterative schemes is quite significant. I was wondering whether there are
2012 Jul 20
3
Execute a function
Hi, I would like to evaluate a function, with 3 arguments, for instance, myfunc<-function(a,b,c) { sqrt(a)-exp(b)+4*c } How to execute myfunc(x,y,z), for all x, all y and all z, where x,y,z are vectors? Thank you very much in advance -- View this message in context: http://r.789695.n4.nabble.com/Execute-a-function-tp4637182.html Sent from
2011 Aug 24
1
Passing a large amount of parameters to a function
Hello, I have a function with a long list of parameters (of different types, numeric and string) myFunc <-function(p1, p2, p3, p4, p5...etc) { do.something(p1,p2,....) } I want to loop over this to provide a different set of parameters to the list every time. for (ii in 1:N) { myFunc(p1(ii), p2(ii),....etc) } I would like to simplify the notation and use some kind of structure, maybe
2009 Apr 07
2
Puzzled by an error with apply()
I've written a function, myFunc, that works fine with myFunc(data, ...), but when I use apply() to run it with an array of data apply(myArray, 1, myFunc, ...) I get a strange error: Error in match.fun(FUN) : '1' is not a function, character or symbol which really puzzles me because '1' is meant to be the margin of the array I want to apply over, but how come does apply()
2016 May 17
3
External function resolution: MCJIT vs ORC JIT
When using ORC JIT, I'm having trouble with external function resolution (that is, of a function defined in the app, with C linkage). I add a declaration for the function to my IR, and when I use MCJIT, it finds it and all is well, But when I use ORC JIT (I *think* correctly, at least it closely matches what I see in the tutorial), I get an LLVM error, "Program used external function
2011 Nov 10
3
optim seems to be finding a local minimum
Hello! I am trying to create an R optimization routine for a task that's currently being done using Excel (lots of tables, formulas, and Solver). However, otpim seems to be finding a local minimum. Example data, functions, and comparison with the solution found in Excel are below. I am not experienced in optimizations so thanks a lot for your advice! Dimitri ### 2 Inputs: