similar to: manipulating the result of by()

Hi I'm trying to extract complete rows from a dataframe by group based on the maximum in a column within that group. Thus I have a dataframe: cvd_basestudy ... es_time ... _____________ study1 ... 0.3091667 study2 ... 0.3091667 study2 ... 0.2625000 study3 ... 0.3033333 study3 ... 0.2625000 __________ etc I can extract the basestudy and the max(es_time)

Friends I have a data frame, df that I want to extract some rows from Here is a sample of the data > head(df) TDate Expiry Underlie Strike CSettle PSettle Futures ExDate TTE 1 20080102 200801 200803 0.840 0.0000 0 0.9207 20080104 0.005479452 2 20080102 200801 200803 0.850 0.0000 0 0.9207 20080104 0.005479452 Rate Disc 1 0.0457 0.9997496 2 0.0457

Peter, Paulo reported some problems with his config files under ISOLINUX and PXELINUX - basically TIMEOUT and TOTALTIMEOUT were broken. The patches I've pushed to the elflink branch fix this and also fix parsing of the ALLOWOPTIONS config directive. The following changes since commit d5e02fb16a11bfdbce1e90a39e6cb5f2ad925389: get_key: Valid key values are positive (2012-04-17 11:25:53

I am a novice R user, and I am having difficulty understanding R's influence plots. I am trying to remove outliers from a particular variable, "sib." I am able to generate influence plots and further outlier information such as below (which is a shortened example). For my analyses, I end up excluding the points R refers to, 7, 18, 26, and 105. However, my question is, how can I

Howdi. I'm new to dovcot (just succeded in compiling on unixware 713 today) I'm noww configuring for tests on other port. The sample configuration file is pretty well documented, however, I don't understand how I can firstt authenticate against passwd/shadow if not found against pgsql. What's the syntax? Please cc responses as I'm subscribed to digest TIA Reghards --

Dear all, I am trying to plot KM curves with confidence bands with function survplot under package rms. However, the following codes do not seem to work. The KM curves are produced, but the confidence bands are not there. Any insights? Thanks in advance. library(rms) ########data generation############ n <- 1000 set.seed(731) age <- 50 + 12*rnorm(n) label(age) <- "Age"

I am setting up a test domain to learn bind, and how it,s working. The master domain is bbb.ttt.domene 10.11.12.13 the child domain ftp.bbb.ttt.domene 10.11.55.77 The thing I don't understand is, why don't the query report additional info (ip address)? Her is two queries(the first the one that troubles me), cut of named.conf, test of zone file, the zone file and cut from log file.

You may also want to check this out: plot(ttt, type = "p") points(ttt, col = ifelse(ttt < 8, "black", "red")) Eivind K. Dovik Bergen, NO On Tue, 1 May 2018, Christopher W Ryan wrote: > Excellent! Worked like a charm. Thanks. > > --Chris Ryan > > On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > >> The

temp.ttt <- "ttt <- 1\nttt" conn.ttt <- textConnection(temp.ttt) source(conn.ttt, echo=TRUE) ## name of variable is echoed close(conn.ttt) cat(file="c:/temp/temp.R", temp.ttt) ## name of variable not echoed source("c:/temp/temp.R", echo=TRUE) temp.abc <- "abc <- 1\nabc" conn.abc <- textConnection(temp.abc) source(conn.abc, echo=TRUE)

The ts method for plot() is quirky. You can use the default method: plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, "black", "red")) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, May 1, 2018 at 1:17 PM, Christopher W Ryan <cryan at binghamton.edu> wrote: > How would I color points conditional on their value in a plot

We have frequent timeout problems after upgrading our imap servers from dovecot 1.1.16 to dovecot 1.2.11. One server acts as proxy only, and the other one is the "real" imap server". The credentials for the proxy service are stored in a remote MYSQL database. There were no trouble with dovecot 1.1.16. But now, with the most recent version, we get frequent login failures. It

At times we want to convert a two-sided formula to a one-sided formula. In S we can do this by dropping the second entry in the formula. In R that object no longer has a formula class. R> ttt <- score ~ age | Infant R> class(ttt) [1] "formula" R> length(ttt) [1] 3 R> ttt[-2] [[1]] ~ [[2]] age | Infant R> class(ttt[-2]) NULL R> do.call("~",

Excellent! Worked like a charm. Thanks. --Chris Ryan On Tue, May 1, 2018 at 4:33 PM, William Dunlap <wdunlap at tibco.com> wrote: > The ts method for plot() is quirky. You can use the default method: > > plot(as.vector(time(ttt)), as.vector(ttt), type = "p", col=ifelse(ttt<8, > "black", "red")) > > > Bill Dunlap > TIBCO Software

Hi, I have a query about sqldf, and dates in general. I couldnt find much on the net or on the forums, hence I am here. Here is the issue: I want to write a function that accepts 3 arguments: date1, date2 and a dataframe, say 'df'. Within the function, I want to populate a temp dataframe which essentially contains the output of the query "select * from df where DATE between date1

Hi: I have some problems when I use the function "solve" function in a loop. In the following code, I have a diagonal martix "ttt" whose elements change in every iteration in a loop. I defined a "dpoMatrix"class before the loop so I do not need to define this class every time in the loop. The reason is to save some computing time. The code is below. The inverse

Hello, I am forwarding this from ESS mailing list, as it's a failure of internal R completion system: This fails: utils:::.assignLinebuffer('iris[iris$Spec') utils:::.assignEnd(15) utils:::.guessTokenFromLine() utils:::.completeToken() utils:::.retrieveCompletions() ## -> [1] "iris[iris$Spec" This works utils:::.assignLinebuffer('iris[ iris$Spec') # note the

How would I color points conditional on their value in a plot of a time series. Something like this: ## demonstration data ttt <- ts(rpois(12, lambda = 8), start = c(2000, 1), freq = 4) ttt plot(ttt, type = "p") ## doesn't work--all points the same color plot(ttt, type = "p", col = ifelse(ttt < 8, "black", "red")) ## also doesn't work--all

Hello, everyone, I don't quite understand the following message: > TTT <- t.test(1:10, y=c(7:20)) > class(TTT) [1] "htest" > TTT@p.value Error: Trying to get slot "p.value" from an object whose class ("htest") is not defined > TTT$p.value [1] 1.855282e-05 Why the message says the class of TTT is not defined while class(TTT) gets

Dear colleagues, preparing a release of my package ?polmineR? I encountered the following issue with a new warning issued when running R CMD check with the --as-cran option on Debian with R-devel. To reexport the magrittr pipe operator %>%, my package adopted I snippet you?d see in the dplyr package, for instance: #' @importFrom magrittr %>% #' @export magrittr::`%>%` The

Confusing. Github says that is open. Ok. My mistake. The question remains why the Windows clients allow login for an expired certificate despite a correctly loaded CRL. What is the purpose of specifying the CRL in smb.conf? It seems to me that the smartcard login is not really reliable. Then my users still have to log in with password. For now, as long as 4.19 is not yet released. Hans