Displaying 20 results from an estimated 3000 matches similar to: "robust mixed effects models"
2002 Feb 28
1
multiple replications of a ts
Hello
I have several replicates (30) of a -- short -- time series (19 obs) and
I'd like to estimate the first few lags autocorrelation function.
Is there an immediate way of handling multiple realizations when computing
the ACF in R?
I'm using R-1.4.1 on a Linux Debian box.
Thanks in advance
claudia
-------------------------------------------------------------------------
claudia
2002 Jun 20
1
errors installing R-1.5.1 on linux debian
Hello
I'm upgrading from R-1.4.1 to R-1.5.1, locally on my Linux PC running
Debian.
after running 'configure' this is what I get (just in case it helps
figuring out what follows later...)
R is now configured for i686-pc-linux-gnu
Source directory: .
Installation directory: /usr/local
C compiler: gcc -D__NO_MATH_INLINES -mieee-fp -g -O2
C++
2001 Nov 13
1
models for polytomous data
Hi all
I have a dataset whose response is a categorical variable of the
ordinal scale type (6 levels).
I'm interested in building classification models, and I'm wondering if
there is something implemented in R (or its packages) that I'm not aware
of, to treat the ordinal scale measurements straightforwardly. I can think
of the alternative of building a conditional (hierarchical)
2001 Sep 06
1
interrupting the sourcing of a file
Hi all
I'm running lm()/leaps() kind of computations within a loop, and I
submitted the entire thing by sourcing a file of R code in interactive
mode.
I'd like to interrupt the evaluation of this (it's taking way too long)
but I am not able to.
I'm running R-1.3.0 from an emacs window (ESS-5.0) and I'm on a linux box,
(Debian). I tried Control-c Control-c (nothing happens),
2001 Oct 29
2
times 'til first change
There is probably an elegant and efficient way to do this -- perhaps
already implemented, and some of you knows it. Myself, I'm getting stuck
in long loops ...
Here is the question:
I have a long (80,000 + obs) binary time series.
For each of its elements I'd like to compute and save in a vector "the
number of steps 'til the first switch of state happens". For example,
2002 Mar 27
1
non-decreasing smoother
Hello
Is there a simple way of fitting a 'smooth curve' to a time series with
the additional constraint that the first derivative be not negative?
I know that if I choose a "large enough" window for a moving average
sort of filter on my data I end up with a non-decreasing curve anyway, but
I'm wondering if there is a pre-built method that can include the
constraint from
2002 Oct 17
2
making R-1.6.0 on Linux Debian
I'm running R-1.4.1 on a linux debian (version 2.2) box.
I've tried to upgrade to R-1.6.0, and the execution of make halts with the
following error messages:
make[4]: Entering directory `/home/tebaldi/R/R-1.6.0/src/library/methods'
dumping R code in package 'methods'
Error in testRversion(descfile) : This package has not been installed
properly
See the Note in ?library
2001 Aug 13
2
printing lattice plots
Hi
I'm trying to print several plots to a multi-page postscript file.
Some plots are output of basic commands, some are produced by "trellis"
commands (from the package lattice).
Right now I'm not able to get a straightforward black and white color
scheme for the latter kind: when I open the postscript file the "trellis"
plots are invisible, or parts of them are
2007 Jan 04
5
color of opposite sign values in filled.contour
Dear R-helpers,
I'm plotting geophysical data in the form of contours using
"filled.contour". The display would be much more effective if the areas
with negative values could be color coded
by -- say -- "cold colors" in the range of blue to green, and conversely
the areas with positive values got plotted with "warm colors", from yellow
to red.
Right now if I use
2001 Oct 31
3
maps in R (fwd)
Here is the answer to an old question of mine, regarding maps in R
Hope this help.
claudia
---------- Forwarded message ----------
Date: Mon, 25 Jun 2001 13:48:05 -0400
From: Kieran Healy <kjhealy at Princeton.EDU>
To: Claudia Tebaldi <tebaldi at ucar.edu>
Subject: Re: [R] maps in R
Hi Claudia --
you can get the maps() library from here:
2010 Oct 28
3
help with help()
Hi all
Just this morning I upgraded to R 2.12.0 (for Mac OS X 10.6.4).
All went well until I needed to run a help() or help.search() in my session,
which I'm running within Emacs (ESS 5.3.7).
Say I need help with the command 'density'. When I type
help(density)
or
?density
the ESS help buffer opens, it is titled *help[R](density)* but it contains
only a couple of lines saying,
2008 Oct 07
2
masking a regular lat/lon grid to extract map boundaries
Dear R-helpers,
I have lat/lon coordinates of regularly spaced grid points, about 4Km
apart, covering the entire US continental region.
I would like to mask this rectangular grid in order to extract all and
only the grid points within a specific region. Today I want to
extract Montana, say, from this grid, and I am hoping to somehow use
the returned value of the function
2010 Oct 31
1
complicated graphic -- persp+map
Hello
I'm trying to render in 3D what I usually plot by image(), or image.plot()
from the library fields, followed by a map("world",add=TRUE) type of
command. More concretely, I have a field of temperature values, for a given
geographic area, and I would like to plot a 3D surface whose x and y axes
consist of longitude and latitude values and whose height and color-coding
correspond
2009 Sep 04
1
predicting from segmented regression
Hello
I'm having trouble figuring out how to use the output of "segmented()"
with a new set of predictor values.
Using the example of the help file:
??set.seed(12)
xx<-1:100
zz<-runif(100)
yy<-2+1.5*pmax(xx-35,0)-1.5*pmax(xx-70,0)+15*pmax(zz-.5,0)+rnorm(100,0,2)
dati<-data.frame(x=xx,y=yy,z=zz)
out.lm<-lm(y~x,data=dati)
o<-## S3
2002 Jan 04
1
plotting maps?
I thought I had plotted a map of oregon and washington and overlayed some
points using R. Is that possibe since I can't seem to find the source file I
used or commands for plotting maps and points?
If not, sorry for the bother...
Thanks,
Jeff.
Jeff D. Hamann
Hamann, Donald & Associates, Inc.
PO Box 1421
Corvallis, Oregon USA 97339-1421
Bus. 541-753-7333
Cell. 541-740-5988
jeff_hamann
2002 Jan 04
3
sorting data frame
Greetings,
I hope this isn't obvious but I've read through the FAQ and the various
other R/S books I have and I cannot, for the life of me, figure out how
to sort a data frame by a specific variable. Suppose I have a four
variable data.frame x and the variables are var1, var2, var3, var4. I
want to sort on say var3 simply for display purposes. How can this be
accomplished? Thanks
2006 Oct 05
2
treatment effect at specific time point within mixedeffects model
Hi David:
In looking at your original post it is a bit difficult to ascertain
exactly what your null hypothesis was. That is, you want to assess
whether there is a treatment effect at time 3, but compared to what. I
think your second post clears this up. You should refer to pages 224-
225 of Pinhiero and Bates for your answer. This shows how to specify
contrasts.
> -----Original Message-----
2011 Jan 19
2
spacing of color key in filled.contour
Hi all
I'm plotting colored contour maps using filled.contour. My levels
are very unevenly spaced, with, say, high resolution in the small
numbers but ranges that can be an order of magnitude or two larger in
absolute value compared to where the action takes place. Aside from
transforming the data, is there a way to control the color spacing in
the key to the right of the map? Right now I
2013 Sep 10
0
Problema con filtros de datos en un data.frame
Cuando utilizas "==" estás comparando el vector "graph$NCar" (longitud 892)
con otro de longitud 2: c("160s","180s").
Es decir, comparas el primer valor de "graph$NCar" con el primer valor de
c("160s","180s"), el segundo valor de "graph$NCar" con el segundo valor de
c("160s","180s"), el tercer valor
2013 Sep 10
1
Problema con filtros de datos en un data.frame
Muchas gracias por la explicación Isidro!
El 10 de septiembre de 2013 08:19, Isidro Hidalgo <ihidalgo@jccm.es>escribió:
> Cuando utilizas "==" estás comparando el vector "graph$NCar" (longitud 892)
> con otro de longitud 2: c("160s","180s").
> Es decir, comparas el primer valor de "graph$NCar" con el primer valor de
>