similar to: identical calls are not equal !?

Hi everyone: I?m one of the interns at RStudio this summer working on a project that helps teachers grade student code. I found an unexpected behaviour with the |==| operator when comparing |quote|d expressions. Example 1: |u <- quote(tidyr::gather(key = key, value = value, new_sp_m014:newrel_f65, na.rm = TRUE)) s <- quote(tidyr::gather(key = key, value = value,

> -----Original Message----- > From: llvm-dev [mailto:llvm-dev-bounces at lists.llvm.org] On Behalf Of Tim > Northover via llvm-dev > Sent: Wednesday, July 25, 2018 3:07 AM > To: Nat! > Cc: LLVM Developers Mailing List > Subject: Re: [llvm-dev] A question to the DWARF experts on symbol > indirection > > Hi Nat!, > > On Wed, 25 Jul 2018 at 01:21, Nat! via

Hi, I want to write a plugin that uses JavaScript and I am wondering how to put the static content, i.e. the JavaScript, in place? I read the documentation I found ( http://wiki.rubyonrails.org/rails/pages/Plugins and links) and looked at the listed plugins. One thing I found was that subversion seems to be a prerequisite for providing or even installing plugins. Is that right? The other thing

Dear all, I am having trouble creating summary tables using aggregate function. given the following table: Var1 Var2 Var3 dummy S1 T1 I 1 S1 T1 I 1 S1 T1 D 1 S1 T1 D 1 S1 T2 I 1 S1 T2 I 1 S1 T2 D 1 S1 T2 D 1 S2

#subject: type III sum of squares - anova() Anova() AnovaM() #R-version: 2.12.2 #Hello everyone, #I am currently evaluating experimental data of a two factor experiment. to illustrate de my problem I will use following #dummy dataset: Factor "T1" has 3 levels ("A","B","C") and factor "T2" has 2 levels "E" and "F". The

Dear R-List, I use Sweave (which is wonderful) and I have a problem with the strings when they are too long according to the width of the page. For example when I do in my .Rnw document : <<UsingRODBC,echo=TRUE>>= channel <- odbcConnect(dsn="database",uid="root",pwd="password") df1 <- sqlFetch(channel,"table1",rownames=TRUE) df2

Dear R-help Members, I am wondering if anyone think of the optimal way of computing for several numeric variable the difference between 2 levels of a factor. To be clear let's generate a simple data frame with 2 numeric variables collected for different subjects (ID) and 2 levels of a TIME factor (time of evaluation)

Oh, got it. Thanks for your explain. I misunderstand what getLocation does. If I would like to get the result of alias analysis referring to the stored value, what should I do in llvm? On 2/16/15 1:42 PM, Hal Finkel wrote: > ----- Original Message ----- >> From: "Haopeng Liu" <hyliuhp at gmail.com> >> To: "Hal Finkel" <hfinkel at anl.gov> >>

Hi all, Our target does not have native support for 64-bit integers, so we rely on library calls for certain operations (like sdiv). We recently ran into a problem where these operations that are expanded to library calls aren't maintaining the proper ordering in relation to other chains in the DAG. The following snippet of a DAG demonstrates the problem. t0: ch = EntryToken t2:

I'm attempting to create an array of treatment comparisons for modelling data generation. This involves comparison of one treatment (c2) with another (c3), relative to a common comparator (c1). Attached code gives me the correct array but need to remove duplicates. Duplicates relate only to c2 and c3 such that I need to remove r3 because c2 and c3 are same as r1 with c2 and c3 swapped r5

Yes, in my example, %1 and %2 point to t. %3 points to t2. But t and t2 point to the same var, is it? That's where I'm confused. On 2/16/15 12:37 PM, Hal Finkel wrote: > ----- Original Message ----- >> From: "Haopeng Liu" <hyliuhp at gmail.com> >> To: "Hal Finkel" <hfinkel at anl.gov> >> Cc: llvmdev at cs.uiuc.edu >> Sent:

'grepl' returns a logical vector; you have to use this to get your subset. You can use: df_tq <- subset(df, grepl("t1", Command)) df_t2 <- subset(df, grepl("t2", Command)) # if you want to also get a subset that has both, use df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) Jim Holtman Data Munger Guru What is

now after this: df_both <- subset(df, grepl("t1", Command) & grepl("t2", Command)) I use factor to apply the subset to df but then the Command level becomes 0 df_both$Command=factor(df_both$Command) str(df_both) $ Protocol : Factor w/ 0 levels: Do you know what is the reason? Thanks for replying On Sunday, April 24, 2016 12:18 PM, jim

t and t2 are two pointers defined in .c file. The definitions in .bc are: %thd = alloc i64, align 8 %t = alloca i64*, align 8 %t2 = alloca i64*, align 8 .c file likes this: int thd; int *t = &thd; int *t2 = t; On 2/16/15 12:28 PM, Hal Finkel wrote: > ----- Original Message ----- >> From: "Haopeng Liu" <hyliuhp at gmail.com> >> To: llvmdev at cs.uiuc.edu

--- fish/Makefile.am | 2 +- src/Makefile.am | 2 +- 2 files changed, 2 insertions(+), 2 deletions(-) diff --git a/fish/Makefile.am b/fish/Makefile.am index 6ca8a82..16a29b0 100644 --- a/fish/Makefile.am +++ b/fish/Makefile.am @@ -139,7 +139,7 @@ if HAVE_RPCGEN rc_protocol.c: rc_protocol.x rm -f $@-t $@-t2 $(RPCGEN) -c -o $@-t $< - sed 's,\.\./\.\./fish/,,' < $@-t >

Hello fellow R people, I can not figure out a pretty way to use strplit with vectors Imagine that I got the following data from someone with ID's representing several factors ID data A1-B1-t1 0 A1-B1-t2 1 A1-B2-t1 5 A1-B2-t2 10 A1-B10-t1 0 A1-B10-t2 1 A1-B20-t1 5 A1-B20-t2 10 ... I would like to turn this dataframe to station substation time data A1 B1 t1 0 A1 B1 t2 1 A1 B2 t1 5

I have a multidimensional data which looks like the following: "S1-a" "S2-b" "S3-c" "S4-d" "S5-a" "S6-b" "S7-c" "S8-d" "T1-A" "T1-B" "T1-C" "T1-D" "T2-A" "T2-B" "T2-C" "T2-D" I read it from csv file and would like to have 16

Hi all! I want to generate a heat map from an all-vs-all comparison. I have the data, already scaled to 0-1. However, I have the values only for the comparisons in one way, and not for the comparisons between the same group (which are always 1), i.e. I have half the matrix and am missing the other half and the diagonal. What is a good way to get it into a form that ggplot2 can use for the

(earlier I sent it as html by mistake). Hi, How can I get from C an object name used as a function argument? I have sample code in C that gives me access to the name of the function being called: SEXP xname(SEXP x) { const char *fun_name = CHAR(PRINTNAME(CAR(x))); x = CDR(x); const char *arg_name = isNull(TAG(x)) ? "" : CHAR(PRINTNAME(TAG(x)));

I have big .csv file. I would like to filter that file into a new table. For example, I have .csv file as below: f1 f2 f3 f4 f5 f6 f7 f9 f10 f11 t1 1 0 1 0 1 0 0 0 0 1 t2 1 0 0 0 0 1 1 1 1 1 t3 0 0 0 0 0 0 0 0 0 0 t4 1 0 0 0 1 0 0 0 0 0 t5 0 0 0 0 0 0 0 0 0 0 t6 0 0 0 0 0 0