similar to: selections using text strings (result of noquote)

Displaying 20 results from an estimated 500 matches similar to: "selections using text strings (result of noquote)"

2008 Jun 15
1
c.noquote() weirdness
I haven't been able to get anywhere tracking this down. It seems that c.noquote() does something strange with its third (and subsequent) parameters: R-2.7.0 under NetBSD, R-2.6.0 under Solaris, and R-2.8.0 (unstable) (2008-06-10 r45893) under WinXP, I get: > c(noquote('z'), 'y', 'x', '*') [1] z y x * x * > or: > c(noquote('z'),
2011 Mar 30
1
Class noquote to matrix
Hi, I apologize if the solution is right in front of me, but I can't find anything on how to convert a class of 'noquote' to 'matrix'. I've tried as.matrix and I've tried coercing it by 'class(x)<-matrix', but of course that didn't work. I've been using the function 'symnum' which returns an object of class 'noquote'. Here is an
2020 Nov 05
1
Named class vector
The source to the noquote() function looks like this: noquote <- function(obj, right = FALSE) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(attr(obj, "class"), if(right) c(right = "noquote") else "noquote") obj } Notice what happens with right =
1997 Aug 20
1
R-alpha: R-0.50-a3(+) Method despatching bug ?
It is very wierd... Can some of you confirm the following behavior ? It is a new bug (feature ?) which was not yet in 0.49 ... noquote <- function(obj) { ## constructor for a useful "minor" class if(!inherits(obj,"noquote")) class(obj) <- c(class(obj),"noquote") obj } "[.noquote" <- function (x, subs) structure(unclass(x)[subs], class =
2011 Jan 24
2
normality and equal variance testing
I currently have a program that automates 2-way ANOVA on a series of endpoints, but before the ANOVA is carried out I want the code to test the assumptions of normality and equal variance and report along with each anova result in the output file.  How can I do this? I have pasted below the code that I currently use.   library(car) numFiles = x #
2009 Aug 11
1
Passing a list object to lapply
Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]
2009 Apr 07
3
write text file as output without quotes
Hi R, When I use the below to write the text file try=data.frame(rep("a",5), rep("b",5)) write.table(try,"z:\\try.txt",row.names=F,col.names=F,sep="\t") the output contains two columns with quotes! Is there a way to write without quotes? I tried try[,1]=noquote(try[,1]) try[,2]=noquote(try[,2]) Thank you, Regards, Ravi Shankar
2017 Oct 13
1
Quotation marks hinder for loop
Dear mailing list members, My question is maybe very basic, but I could not find the solution. I would like to do the following things 1) colnames(V1)[2] <- par$V2[1] colnames(V2)[2] <- par$V2[2] colnames(V3)[2] <- par$V2[3] ... colnames(V37)[2] <- par$V2[37] 2) V1 <- V1[,-1] V2 <- V2[,-1] V3 <- V3[,-1] ... V37 <- V37[,-1] 3) ms <- merge(V1,V2) ms <- merge(ms,V3)
2010 May 08
3
Count cases in a list
Hi everybody, I would like to count how many times names in list L, nombreL, apear in list C, nombreC. Can I improve the next program? cuenta <- 0 topL <- length(nombreL) topC <- length(nombreC) for (i in 1:topL) { for (j in 1:topC) { k <- grep(noquote(nombreL[i]),nombreC[j])
2009 Mar 23
2
Looping of read.table and assignment
Dear all, I am trying to read in and assign data from 50 tables in an automated fashion. I have the following code, which I created with the help of textbooks and the internet, but it only seems to read in the final data file over and over again. For example, when I type:> table_1951 I get the same values in the table as when I type> table_2000 despite the values in the source tables
2013 Mar 07
1
Error: no 'dimnames' attribute for array
Dear XpeRts, I prepared a no qoute Character string by the following command s<-noquote(paste (b1, collapse=",")) where, b1 is the vector of 24 intergers. > dput(b1) c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L, 48L, 58L, 64L, 65L, 68L, 82L, 97L, 98L, 101L, 113L, 115L) > dput(s)
2010 Aug 21
1
R-level expansion of Rplot%03d.png
Dear list, I'm using the brew package to generate a report containing various plots. I wrote a function that creates a plot in png and pdf formats, and outputs a suitable text string to insert the file in the final document using the asciidoc syntax, <% tmp <- 1 makePlot = function(p, name=paste("tmp",tmp,sep=""), width=300) {
2013 Jul 02
2
Recoding variables based on reference values in data frame
I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA
2012 Sep 17
4
Using paste to create and evaluate a variable expression
Is it possible to use "paste" to write out an expression and evaluate it? Suppose I want to add two vectors X1 and X2, defined as follows: X1 <- 1:6 X2 <- 6:1 If I write the following it looks like what I want but is a character: noquote(paste(paste("X", 1, sep = ""), paste("X", 2, sep = ""), sep = "+")) Is there a way to tell R
2017 Sep 19
0
remove quotes from matrix
Works fine for me. What do you object to in the following? Calling the above df "d", > dm <- as.matrix(d) > dm Sub_Pathways BMI_beta SAT_beta VAT_beta 1 "Alanine_and_Aspartate" " 0.23820" "-0.02409" " 0.94180" 2 "Alanine_and_Aspartate" "-0.31300" "-1.97510" "-2.22040" 3
2008 Feb 04
1
Concatenation and Evaluation
Hello all, I've run into what I bet is a silly problem; however, I've been trying to get around it now for a couple weeks and every time I think I have the answer it still doesn't work. So I apologize in advance if this is painfully obvious, but I've run out of ideas and would really appreciate any input. My situation is this, I'm importing a number of tab
2010 Nov 16
2
Pass character vector to function argument
A bit embarrassed to post this seemingly trivial question, but I can't find anything in the archive that's quite relevant: a1=1 a2=2 obs=objects(pattern=glob2rx("a?")) I want to utilize 'obs' as a function argument to produce something like: sum(a1,a2) Obviously, sum(obs) doesn't work, but I've tried variations of 'eval', 'parse',
2010 May 08
5
contar casos en un vector
Buenas noches, tengo dos vectores con nombres. El primero es largo, nombreL, y el segundo corto, nombreC. Quiero contar cuantas veces aparece alguno de los nombres del vector corto en el largo. Lo que estoy haciendo es lo siguiente: cuenta <- 0 topL <- length(nombreL) topC <- length(nombreC) for (i in 1:topL) { for (j in 1:topC) {
2009 Dec 09
4
binary string conversion to a vector (PR#14120)
Full_Name: Franc Brglez Version: R 2.9.1 GUI 1.28 Tiger build 32-bit (5444) OS: MacOSX -- 10.6.2 Submission from: (NULL) (24.148.163.114) I am demonstrating what may be a bug or my lack of experience. Please review as it would help to hear from someone. MANY THANKS -- Franc Brglez The function "binS2binV" returns what I consider a wrong value -- see the terminal output binS2binV =
2010 Feb 17
2
How to provide a result from D(f(x), "x") to a curve(f'(x)) ???
Hi all, I want to provide the result from D() to curve(), because I want to plot the k-th derivative of some functions. Actually, I copy from console the result given by D() and paste inside curve(). With a lot of functions and high degree differentiation this process is tedious. Can I provide directly?? # what I actually have done (very simple function) D(expression(x^3), "x") # copy