similar to: Setting the Number of Columns

I searched the mailing list archives and found one post relevant to my problem, but it was not specific enough to solve my problem. I am reading in a large file of data (I believe it is in ASCII format). I have tried reading the file in as a data frame and as a list, and both methods result in unwanted levels being created which leads to problems when I try to copy or reference certain cells.

Is there any way that R can be programmed so that it will cycle through all files in a directory without having to define file names? The reason I ask is because I will have about 50-100 files in a directory which will be randomly named. ie: MIDEX, OACES-CO2, ODEN91, etc... If not...are there any languages out there that will do this sort of things? Or is there another method you could

Hello togehter, i have a data.frame like this one: No. Date last change 1 1 2012-10-04 change settings 2 1 2012-10-20 bug fix 3 1 2012-11-05 final 4 2 2013-01-15 new task 5 2 2013-01-16 Bug fix 6 2 2013-01-17 final now i want a new data.frame, who show me only the newest entries according to the No. The solution look like

Hello, I'm trying to run an lmer model with family poisson but receive the following warning message: model<-lmer(count~tem+dat+alt+year+tem:dat+tem:alt+tem:year+dat:alt+dat:year+alt:year+(1|id),family=poisson) Error in objective(.par, ...) : Leading minor of order 2 in downdated X'X is not positive definite I'm using the newest version of R and recently installed the

I have a situation like below: Samba servers in many cities; one "backup" server in the central location that fetches user profiles each night (changes really with rsync). Users work in many locations; sometimes one user can work in city A, and a day later he can work in city B. This means that they have problems with their profiles - user profile for city A will be different from

Let me start by saying I am rather new to R and generally consider myself to be a novice programmer...so don't assume I know what I'm doing :) I have a large matrix, approximately 300,000 x 14. It's essentially a 20-year dataset of 15-minute data. However, I only need the rows where the column I've named REC.TYPE contains the string "SAO " or "FL-15". My

Hallo! I read SPSS data in the following way: library(Hmisc) library(foreign) dat<-spss.get("surv_abb.sav") In R1.9.1 I got the message: "Error in all(arg == choices) : Object "typeDate" not found" In R1.8.0 the same script works fine. Does anybody know a possibilty to read a SPSS file under R1.9.1? Thanks! Karl

Dear R-user, I am a R beginner, and therefore my questions are very basic. I have a simple problem: I would like to plot 100 time series each containing 55 steps. The data are stored in a matrix of 100 columns and 55 rows. The first problem is to load the data from a file: I tried the read.table(), the scan() and the matrix(scan()) options, but I have problems to allocate the single columns.

Hi all, assume the following problem: a function call takes a function object and a data variable and calls this function with this data on a remote host. It uses serialization to pass both the function and the data via a socket connection to a remote host. The problem is that depending on the way we call the same construct, the function may be serialized to include the data, which was not

Hi, I' ve read in several files with measurements into R data frames(works flawlessly). Each dataframe is named by the location of measurement and contains hundreds of rows and about 50 columns like this dataframe1. date measurment_1 .... mesurement_n 1 2 3 .. .. .. n For further processing I need to check whether or not ncol and colnames are the same for all dataframes. Also I need to

Dear Colleagues, Occasionally I deal with computer-generated (i.e., websurvey) data files that haven't quite worked correctly. When I try to read the data into R, I get something like this: Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : line 26 did not have 648 elements ...is there any way to get R to tell me how many elements line 26 *did* have? That

Dear UseRs, I just learnt that the number of columns of a data frame is not always what I thought it to be, and I wonder where I should have learnt about this. Consider the following example: dat <- data.frame(X1=1:10, X2=LETTERS[1:10]) ncol(dat) ## evaluates to 2 (of course) dat$X1poly <- poly(dat$X1,3) dat ## five columns displayed ncol(dat) ##

Hi folks, I have a simple question that I just can't solve. I'm trying to merge two columns in my data frame. > sessionInfo() R version 2.13.0 (2011-04-13) Platform: i686-pc-linux-gnu (32-bit) > head(dat) Year Month Number 2002 Jan 0 2002 Feb 0 2002 March 0 2002 April 1 2002 May 0 2002 June 0 I tried to do the following, but it

Hello, I've read in a data file as a frame and now I'd like the columns to be rows and the rows to be columns. What's the easiest way to do this in R? > class(d) [1] "data.frame" > rownames(d) [1] "98x101" "40x98" "30x40" "0x30" > colnames(d) [1] "H..sapiens" "C..elegans"

Dear all, Type III SS time again. This case trying to reproduce some SPSS (type III) data in R for a repeated measures anova with a betwSS factor included. As I understand this list etc, if I want type III then I can do library(car) Anova(lm.obj, type="III") But for the repeated measures anova, I need to include an Error-term in the aov() call (Psychology-guide from Jonathan Baron)

Not a reproducible example, so a bit of guessing here, but a) don't try to assign results to variables inside the ifelse. That is, remove all the single-equals signs and "test" variables. If you really need to conditionally assign variables then use "if"... but chances are good you don't need that. b) "closure" is effectively another word

Hi Everyone, I have the following problem: data <- structure(list(prochi = c("IND1", "IND1", "IND1", "IND2", "IND2", "IND2", "IND2", "IND3", "IND4", "IND5"), date_admission = structure(c(6468, 6470, 7063, 9981, 9983, 14186, 14372, 5129, 9767, 11168), class = "Date")), .Names =

Hi everyone, I'm having some trouble with my ifelse statements. I'm trying to put 12 conditions within 3 groups. Here is the code I have so far: dat$cond <- ifelse(test = dat$cond == "cond1" | dat$cond == "cond2" | dat$cond == "cond3" dat$cond == "cond4" yes = "Uniform" no = ifelse(test =

Hello I have a data frame and one of its columns is as follows: Col chr1:71310034 chr14:23354088 chr15:37759058 chr22:18262638 chrUn:31337214 chr10_random:4369261 chrUn:3545097 I would like to get rid of colon (:) and replace this column with two new columns containing the terms on each side of the colon. The new columns should look as follows: Col_a Col_b chr1

Greetings, I couldn't find any existing function that would allow me to scan a matrix and eliminate invariant rows and columns so I have started to write a simple routine from scratch. The following code fails because the array index goes out of bounds for obvious reasons you'll see shortly. Start with some data x <- read.table("myex.dat",header=T) x v1 v2 v3 v4 v5 id 1