similar to: Using Object's Name in Function

Displaying 20 results from an estimated 7000 matches similar to: "Using Object's Name in Function"

2002 Apr 15
1
Re: Writting R Function
Hi, I think I found the problem. It lies in my Fortran program. Is there a way, after a DO loop, to make sure it does NOT return anything? Cheers, Kevin On Mon, 15 Apr 2002, Ko-Kang Kevin Wang wrote: > Date: Mon, 15 Apr 2002 17:27:20 +1200 (NZST) > From: Ko-Kang Kevin Wang <kwan022 at stat1.stat.auckland.ac.nz> > To: R Help <r-help at stat.math.ethz.ch> > Subject:
2002 May 06
4
Subtitle?
Hi, Is it possible to add a subtitle that appears directly below the main title? I tried the "sub" parameter, but it adds sub-title to the bottom of the plot. Cheers, Kevin ------------------------------------------------------------------------------ Ko-Kang Kevin Wang Postgraduate PGDipSci Student Department of Statistics University of Auckland New Zealand Homepage:
2002 May 18
5
Length of a string
Hi, Suppose I have created something like this in R: foo <- "myfoo" and I want to find out the number of character in foo (in other words, R should return 5 since "myfoo" has 5 charactors. How can I do it? I tried: length(foo) but it returned 1. Cheers, Kevin ------------------------------------------------------------------------------ Ko-Kang Kevin Wang
2002 Nov 15
1
postscript()
Hi, I've been trying out postscript() when onefile is set to FALSE. However I'm having trouble understanding the documentation for postscript(). Suppose I want to do: plot(1:10) plot(1:10, type = "l") and store them in foo.ps and goo.ps. Furthermore, I'd like to do then with one postscript() command -- because this is just a simplified version of what I really need
2002 Sep 18
2
More on list to data frame (was: Re: List to Data Frame
Hi, Now suppose I have just one list called FOO, which has 25 objects, e.g.: [[1]] 1 2 3 4 5 [[2]] 6 7 8 9 10 . . . And I want to do something like: FRED <- data.frame(cbind(unlist(FOO[[1]]), unlist(FOO[[2]]), # ... for all 25 subsets )) Is it possible to do this, without doing unlist(FOO[[i]]) 25
2002 Sep 23
4
Overall Title in par(mfrow)
Hi, Say I did something like: par(mfrow = c(1, 2)) plot(1:10) plot(1:10) and I'd like to have an overall title, i.e. a title that would appear, centered, on the top of both plots, rather than the top of the last plot. I tried: title("FOO", outer = T) but it doesn't appear right. Half of the FOO is outside the figure region and can't be seen... Is there another
2002 May 10
1
barplot()
Hi, Is it possible to draw barplot with x-axis being shown? I looked up the help file and I couldn't seem to find it. For example, I tried to do x <- 1:9 p <- log10(1 + 1/x) barplot(p, xlab = "Digit d", ylab = "Probability", ylim = c(0, 0.35), axes = F, main = "Benford's Law Probability") axis(1, 1:9) axis(2, seq(0, 0.35, by = 0.05),
2002 Jun 08
2
More on for() Loop...
Hi, Say I want to do something like fitting 10 different sized trees with rpart() function. The only modification I need to do is to set 10 different cp's, which I have in a vector called foo. Can I do something like: for(i in 1:10) { rpart(y ~ ., cp = foo[i], data = mydata) } My problem is, I wish to save the 10 rpart objects into 10 different names, my.rpart1 ~ my.rpart10, for
2002 Sep 27
3
xtable()
Hi, Does anyone know how to manually configure the number of digits printed out from xtable()? For example, I'm exporting a data frame through xtable() into a LaTeX table, I only have two columns in the data frame so by default I only get two decimal places. But I'd like at least 5 decimal places. I had a look at ?xtable() but can't seem to find an example. Cheers, Kevin
2002 Sep 24
4
print(), paste()
Hi, Suppose I have the following lines at the end of a function: answer <- c(2, 1, 0, 4, 5) # In fact, answer will be generate in my # function print(answer) # Print the answer # Now, find the best fitted n degree polynomial print(paste("The best fit is with", which.min(answer) - 1, "-degree polynomial")) this will return:
2002 Sep 19
2
Rounding
Hi, Suppose I have: 459 1789 23590 and I'd like to round them to: 400 1700 24000 On the other hand, say if I have: 232 1234 23120 that need to be rounded to: 300 1300 24000 I tried the round(), floor() or ceiling() and can't get what I want. Is there any tricks I can use to achieve this goal? Cheers, Kevin
2002 Apr 09
1
Fortran (77) in R
Hi, I'm learning Fortran and trying to load a Fortran subroutine into R. I've done: R SHLIB Fibonacci.f and it compiled fine. Then I went into R and done: > dyn.load("Fibonacci.so") > Fib <- function(n) { + .Fortran("Fibonacci", + as.integer(n))[[1]] + } > Fib(5) Error in .Fortran("Fibonacci", as.integer(n)) :
2002 Sep 19
2
R 1.6 for windows?
On Thu, 19 Sep 2002 10:43:01 -0400 (EDT), you wrote in message <200209191443.KAA17404@falmouth.bwh.harvard.edu>: >Hi Duncan -- I am curious as to whether you are building/distributing >R 1.6.0 for windows? There's nothing urgent about it, I have one. >The question is how to identify a distribution URL if one exists. I will be building and distributing the final release.
2002 Feb 04
1
row.names in read.table()
Hi, I was trying to read in the following data set by using: gas <- read.table("gas.tab", header = T) when I got the error message: Error in "row.names<-.data.frame"(*tmp*, value = row.names) : duplicate row.names are not allowed Any help are appreciated. Thanks, Ko-Kang Wang
2002 Oct 01
1
Cleveland's Cut-and-Stack Plot
Hi, Is there a function in R that does Cleveland's Cut-and-Stack plot (Page 190 -- 191, The Elements of Graphing Data, William S. Cleveland)? Or do I need to do it the hard way, i.e. set par(mfrow = c(m, n)) then do it one-by-one? (I have a time series data set that is almost identical to the description in Cleveland's book, hence I'm interested in trying the Cut-and-Stack plot)
2002 Nov 06
2
Re: some questions!
Hi, I'm also cc'ing it to r-help. On Wed, 6 Nov 2002, Kenneth Cabrera wrote: > Date: Wed, 06 Nov 2002 10:09:21 -0500 > From: Kenneth Cabrera <krcabrer at perseus.unalmed.edu.co> > To: kwan022 at stat.auckland.ac.nz > Subject: some questions! > > Hello Dear Ko-Kang Wang: > > I am trying to compile R v 1.6.1 . > > I am following the
2002 Sep 10
9
R 1.6.0 beta
R 1.6.0 has gone into final feature freeze as of today. As a new feature, we'll make interim beta versions available via ftp://cran.us.r-project.org/pub/R/src/base alias http://cran.us.r-project.org/src/base (filename R-1.6.0beta_*.tar.gz, where * is the creation date). If you want to help ensure that the final 1.6.0 works satisfactorily on *your* platform, it might be a good idea to
2002 May 25
2
Ploting in for() loop
Hi, Suppose I have a for() loop that draws 6 boxplots as follows: par(mfrow = c(2, 3)) for(i in 2:length(spam.sample)) { boxplot(split(spam.sample[,i], yesno)) } Where spam.sample is a data frame with 7 columns, and I'm interested in plotting column 2 ~ 7 against column 1 (yesno). The boxplots appeared fine, however I'm trying to add a meaningful title, x and y labels to them.
2002 Feb 11
2
Time Series ts() Objects
Hi, Is it possible to create a ts() object, whose data is daily based BUT measured only on working days? In other words, suppose I have a data set with 255 observations, measured from 29 June 1959 to 30 June 1960. How would I create such a data? I tried something like: ts(c(...), start(1959, 180)) but I'm not sure what to use for frequency. In other words I don't know how to
2002 Oct 09
3
Multiplication of Matrices
Hi, Suppose I have a matrix, A. Is there an easy way to find A^{n}? I mean, I can do something like: A %*% A %*% A %*% A for A^4, but if I want A^{10} it would be kind of annoying... Cheers, Kevin ------------------------------------------------------------------------------ Ko-Kang Kevin Wang Postgraduate PGDipSci Student Department of Statistics University of Auckland New Zealand