similar to: Two scattered matrix

Hello! Two questions: 1: I have to import a matrix of adjacency from a file of a software that is not R (for example "bloc notes" of Windows). The problem is that the matrix is not in the explicit form as 0 1 1 1 0 0 1 0 0 but it is a scattered matrix where in each row there are two nodes that have a direct path. The matrix is a b a c b a c a For example, the first row

I have a scattered matrix that I have to import from an external file. In this case all the lines could have a different size. The graph is oriented. I give you an example: a b c b a c d c b The first row expresses that "a" has a direct path with "b" and also with "c". In the second "b" has a path with "a" and one with "c". In the third

I have an adjacency matrix and I want to obtain a matrix of the minimum paths between the nodes. Thank you Alessandro Ambrosini -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

The first: if I have a vector as (1,1,3,2,1,1), which is the command that gives all the positions of the min value? From the vector of the example a would like to obtain a new vector as (1,2,5,6) that give me all the positions of the minimum value 1. The second: if I have a matrix "A" and I want to obtain a new matrix deleting a column or a row of A, what have I to do? Thank you.

Here's my command copied from a shell script:\ rsync --verbose --progress --stats --compress --rsh=/usr/bin/ssh --recursive --times --perms --links \ /home/* trt@xxxxxx.xxxxxxx.xxx:/remotebackups/ Here's some (a small part) of the output: jk/.recently-used 253 100% 0.00kB/s 0:00:00 rsync: recv_generator: mkdir "jk/.secpanel/.runfiles": Permission denied (2) stat

Hello. Given a vector 1 3 4 2 8 9 5 I want to obtain a vector with all 0 except in the second position and in the fifth, where the numbers are the same of the first vector. The new vector must be 0 3 0 0 8 0 0 Thank you very much. Excuseme but my mind is out of order. Alessandro -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

-----Messaggio originale----- Da: Ambrosini Alessandro [mailto:klavan at tiscalinet.it] Inviato: luned? 29 aprile 2002 20.38 A: R-help at lists.R-project.org Oggetto: Problem Hello! This is the situation. I have a file in wich there is a scattered matrix. I give an example: aa bb cc bb xx dd cv st rw xx yu de qw ww zzp where aa is a node that has a path with aa, one with bb, and one with cc.

I'd like to create a data frame with components > jk$x1 [1] 2 > jk$x2 [,1] [,2] [1,] 0 0 I used to be able to do it with > jk <- data.frame(x1=2,x2=I(matrix(0,1,2))) But now I get a error message. Can I still do what I want? Thanks for any help. Chong Gu -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list --

Alex thank you for your response. In this case we are USING INBAND, though I have tried both. Nothing works. Yes ser is configured with mediaproxy. Thank you, -JK JK, In-band or RFC2833 DTMF signaling? Also, unless you have SER configured with a media proxy, the actual "call" is not running through SER. It's a signaling proxy only. -- Alex Balashov Evariste Systems Web :

I'm still having trouble getting to grips with time classes. I wish to calculate the difference in days between events. Browse[1]> insp.j$First [1] "2002-02-19 13:00:00 NZDT" Browse[1]> spray.j$Date [1] "2001-11-29 13:00:00 NZDT" Browse[1]> insp.jk - spray.j$Date Time difference of 82 days If I save insp.jk to a vector, I get a nice useful value of 82.

i have a list of users that I?ve removed from LDAP and I want to delete their mail storage. sdbox Dovecot 2.2.15.8 I have mail messages in one location and indexes in another. Should I just rm -rf /messages/<username> rm -rf /indexes/<username> Thanks, JK ----------------------------------------------------------------------- John "JK" Krug System Administrator The

Hi, So I'm going to be upfront about this: I don't know how to fix this problem or even who to talk to. I've tried the JK community, #winehq, #ati, and even the ATI forums, but no there was help to be offered. Here's the problem... Playing Jedi Knight: Dark Forces II (http://appdb.winehq.org/objectManager.php?sClass=application&iId=122) on Wine, I get such horrid framerates

Dear all, Need a help. I would like to count combination of two columns: structure(list(V1 = structure(c(4L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 3L), .Label = c("23", "55", "67", "Env"), class = "factor"), V2 = structure(c(9L, 7L, 7L, 7L, 2L, 1L, 11L, 11L, 11L, 11L, 5L, 6L, 6L, 3L, 8L, 2L, 1L, 4L, 4L,

*Hi guys.. i got this type of error when i configured Gemfile then what to do?* gem "thinking-sphinx" gem ''ferret'' Updating git://github.com/mark-moseley/linecache Fetching gem metadata from https://rubygems.org/....... Fetching gem metadata from https://rubygems.org/.. Resolving dependencies... Using rake (10.0.3) Using ClothRed (0.4.1) Using RedCloth (4.2.9)

Hello I have the matrix a<-matrix(c(2,1,0,1,2,2,1,5,7,2,5,12),nrow=6) a [,1] [,2] [1,] 2 1 [2,] 1 5 [3,] 0 7 [4,] 1 2 [5,] 2 5 [6,] 2 12 Suppose that in the first row we have 3 men of England, 2 with hair, and 1 no In the second we have 6 italian men, 1 with hair and 5 no ... I want to find if there is a dependence between men withouth hair and

*Hi guys.. i got this type of error when i configured Gemfile then what to do?* gem "thinking-sphinx" gem ''ferret'' Updating git://github.com/mark-moseley/linecache Fetching gem metadata from https://rubygems.org/....... Fetching gem metadata from https://rubygems.org/.. Resolving dependencies... Using rake (10.0.3) Using ClothRed (0.4.1) Using RedCloth (4.2.9)

Dear All, I would like to ask clarifications on the gower distnce matrix calculated by the function gdistin the library mvpart. Here is a dummy example: > library(mvpart) Loading required package: survival Loading required package: splines mvpart package loaded: extends rpart to include multivariate and distance-based partitioning > x=matrix(1:6, byrow=T, ncol=2) > x [,1]

Hello. I don't know if you can help me but I try. I have a collection of objects, we suppose that they are 1000. After some works that I made I divided this collection in some clusters. Suppose to have obtained 50 clusters. For each cluster I found a particular value called Precision, where 0<Precision<1. Taken the firs cluster I want to compare his Precision with the precision of his

i chose to install tomcat during the OS install as well as java....however, since I needed to use a different jvm, i used the method described in http://wiki.centos.org/HowTos/JavaOnCentOS for Sun jdk 1.5.0_13 and it worked fine as I can tell, as using the alternatives --config java command, i see both 1.4.2 and 1.5.0 versions and choosing the 1.5.0 version yields the right version when doing a

On 27 November 2016 at 13:59, Paul Walker <Paul.Walker at arm.com> wrote: > Thanks Renato, my takeaway is that I am presenting the design out of order. So let's focus purely on the vector length (VL) and ignore everything else. For SVE the vector length is unknown and can vary across an as yet undetermined boundary (process, library....). Within a boundary we propose making VL a