similar to: Writing text in lattice graphics

Is there any package similar to the XML package that is able to "extract" relevant information from HTML files. Namely, I'm interested in obtained data that is represented as a HTML table, into some R-type structure. Thank you. -- Luis Torgo FEP/LIACC, University of Porto Phone : (+351) 22 607 88 30 Machine Learning Group Fax : (+351) 22 600 36 54 R. Campo

Regarding a previous question concerning the kmeans function I've tried the same example and I also get a strange result (at least according to what is said in the help of the function kmeans). Apparently, the function is disregarding the initial cluster centers one gives it. According to the help of the function: centers: Either the number of clusters or a set of initial cluster

Hi. I frequently use RMySQL package to interface R with MySQL databases. I was having a try with package DBI and I got the following error: > library(RMySQL) > library(DBI) > drv <- dbDriver("MySQL") > ch <- dbConnect(drv, dbname="mydb", user="myuser", password="mypasswd") > ibm <- dbGetQuery(ch,"select * from table where

I'm having some problems with valid field names when using RMySQL to interface R (version 1.7.0, under RedHat9.0), to MySQL (4.1.0-alpha). I think I've spotted the problem and a solution (which is working for me), but I wanted to share this with you as I may be missing something. (Note: I'm aware that this is an old R version, but I've checked the code of the lastest version of

Dear all, I've recently encountered a strange behaviour when using R with portuguese accented characters. The most curious aspect is that using the same code with ESS under XEmacs the behaviour is different. My system is: > R.version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major

Dear R-users, I'm felling kind of blocked on a quite simple problem and I wonder if someone could give me a help with it. My problem: x[0] = 100 x[1] = (1+v[1])*x[0] x[2] = (1+v[2])*x[1] ... i.e. x[i] = (1+v[i])*x[i-1] and x[0]=k Given a set of v values I wanted to obtain the corresponding x values in an efficient way (i.e. without a for loop). For instance, if x[0] = 100 and v =

Can someone please explain to me why the dates get shifted by one day when I create an its ( irregular time-series ) object from a matrix for which I've assigned row names. E.g. in the example run below, why does the its object have dates one-shifted from my original dates? > install.packages('its') > install.packages('Hmisc') > require(its) > m <-

Dear R list, I'm having some problems with font encodings when using R+Sweave+Latex in my native language: Portuguese. My environment: Kubuntu 5.10 Linux $> uname -a Linux nassa 2.6.12-9-686 #1 Mon Oct 10 13:25:32 BST 2005 i686 GNU/Linux R> R.version _ platform i486-pc-linux-gnu arch i486 os linux-gnu system i486, linux-gnu

Deall all, We need to perform a statistical analysis of a large database (40,000 entries with approximately 500 fields in each entry) currently handled in Oracle. The data contains categorical variables only. At the current stage we suggest classification and clustering analysis. We are planning to perform the analysis in R and would be very grateful for any

I've come across the following error when using free scales with bwplot (I use a small example data set just to illustrate the problem): > d <- data.frame( x=c(34.4, 12.4, NA, 65.3, NA, 12.0, 45.0, 645.0, 644.0,323.0), fac1=c('a','a','b','a','b','a','a','c','c','c'),

Hello to everybody, Does anyone has implemented a function for evaluating models using windowing strategies, such as growing window or sliding window ones? The aim is to evaluate regression models on a time series data. I do not use cross-validation once data sorted in a radom way does not make sense when evaluating time series. Thanks Joao Moreira

Hi. I've already posted this question 2 months ago but as I've got no answer I've decided to try again :-) I'm using R1.3.1 on a x86 machine running Win 2000. My problem: I want to convert a string to a date format using strptime. As I'm from Portugal my locale information is the following: > Sys.getlocale() [1]

Dear all, I'm trying to use the lattice barchart function to obtain a bar plot of a variable for different values of two factors. The thing I'm trying to do is something like this: > barchart(MyVar ~ season | place, data=mydataset) My problem is that the column MyVar has some negative values and I would like them to be represented as bars stacking down from zero instead of what

Dear all, I'm having some problems with using the step() function inside another function. I think it is an environment problem but I do not know how to overcome it. Any suggestions are appreciated. I've prepared a simple example to illustrate my problem: > library(MASS) > data(Boston) > my.fun <- function(dataset) { + l <- lm(medv ~ .,data=dataset) + final.l <-

I'm trying to create figures in PDF that use the 'gray' colormodel instead of the default 'RGB' model, by requirements of a publisher. My problem has to do with the fact that I'm not being able to get gray colors with this option on the pdf() driver. Here is a small example for problem replication: > R.version _ platform

Hi. I have a question concerning the easiest way to index a time series object holding some stock quotes. An example: > ibm <- get.hist.quote("IBM",start="2000-01-01") My question is:- Suppose I want to know the stock quotes on 2000-01-03. Which is the easiest way to index the "ibm" time series object to get them? I got what I wanted using: >

I've written a small adaptation of the text.rpart function of the rpart package to better suite my tree presentation needs (I basically left the code untouched, only changing some numbers relating to label positioning). When I changed to version 1.7.0 this function stopped working printing the error : couldn't find function "rpartco" As far as I understand this has to do

Dear all, I'm trying to obtain a fuzzy clustering with fanny from the cluster package, using a given set of data. That worked just fine. I have another separate sample of data from the same problem. For each case in this new sample I would like to know their membership coefficients with respect to the clustering obtained with the first dataset. In effect I want to have a kind of prediction

Hi, i 'dont understand how to take a general formula, view this: x<-1:5 y<-c(0,1,1.7,2,2.1.4) dummy<-data.frame(x=x,y=y) formula<-"y~A*log(x)/log(2)" formu<-as.formula(formula) fm<-lm(formu,data=dummy) Error in eval(expr, envir, enclos) : Object "A" not found but A is the parameter of fitting, why is this?Thanks Ruben

I'm using R on a Linux box: > version platform i686-pc-linux-gnu arch i686 os linux-gnu system i686, linux-gnu status major 1 minor 5.0 year 2002 month 04 day 29 language R I want to use data that is stored in a MySQL database.