similar to: Background in lattice plots using dotplot()

I've managed to find how to change trellis.settings$box.rectangle$col and trellis.settings$box.umbrella$col but I can't figure out how to change the colour of the point used to indicate outliers. There doesn't seem to be a general colour. What am I overlooking? best -- ************************************************************* ___ Patrick Connolly {~._.~}

To compare two different models, I've compared the result of using dropterm() on both. Single term deletions Model: growth ~ days + I(days^0.5) Df Sum of Sq RSS AIC <none> 2.8750 -0.2290 days 1 4.8594 7.7344 4.6984 I(days^0.5) 1 0.0234 2.8984 -2.1722 AND Single term deletions Model: growth ~ days + I(days^2) Df Sum

I can use a postscript device to produce a file which I can open with the Gimp, then save quite a good png file. If I try to use the png() function directly, I get something rather like a graphics screen dump. The help file doesn't tell me whether it should be like that or not. _ platform i686-pc-linux-gnu arch i686 os linux-gnu system

I've been able to do most things I'd like to using the map package, but I can't figure out how to fill a region without drawing a black outline. I can draw the outline in a specified colour, but as soon as I set fill to TRUE, I get a black outline in addition. My map has a lot of activity on the coastline so I don't want a black line obscuring what I do there. A pale colour to

I'm sure there's a simple way to do this, but I can only think of complicated ones. I have a number of character vectors that look something like this: "12 78 23 9 76 43 2 15 41 81 92 5(92 12) (81 78 5 76 9 41) (23 2 15 43)" I wish to get it into a list of numerical vectors like this: $Group [1] 12 78 23 9 76 43 2 15 41 81 92 5 $Subgroup1 [1] 92 12 $Subgroup2 [1] 81 78 5

Hi, Now suppose I have just one list called FOO, which has 25 objects, e.g.: [[1]] 1 2 3 4 5 [[2]] 6 7 8 9 10 . . . And I want to do something like: FRED <- data.frame(cbind(unlist(FOO[[1]]), unlist(FOO[[2]]), # ... for all 25 subsets )) Is it possible to do this, without doing unlist(FOO[[i]]) 25

I like the fact that the postscript function enables the possbiility of a more useful title than before. However, I'd prefer the default to be the file name. It's very simple for me to make my own postscript function that does just that simply by setting title = file. I always use onefile = TRUE, so it always works (so far). However, I'm a little reluctant to do that in case some

I like the fact that the postscript function enables the possbiility of a more useful title than before. However, I'd prefer the default to be the file name. It's very simple for me to make my own postscript function that does just that simply by setting title = file. I always use onefile = TRUE, so it always works (so far). However, I'm a little reluctant to do that in case some

I investigated why I was getting this error message... Error in Ops.factor(groups[subscripts], vals[1]) : Level sets of factors are different which led me to putting a browser in panel.superpose: Called from: panel.superpose(x, y, subscripts, ...) Browse[1]> vals vals [1] 1 2 3 Levels: 1 2 3 Browse[1]> groups[subscripts] groups[subscripts] [1] 1 2 3 1 2 1 2 3 1 2 3 1 2 3 Levels: 1 2

&gt;From: Patrick Connolly &lt;p.connolly@hortresearch.co.nz&gt; &gt;To: &quot;RenE J.V. Bertin&quot; &lt;rjvbertin@hotmail.com&gt; &gt;Subject: Re: [R] changing (core) function argument defaults? &gt;Date: Thu, 18 Nov 2004 11:43:10 +1300 &gt; &gt;On Wed, 20-Oct-2004 at 07:48PM +0200, RenE J.V. Bertin wrote: &gt; &gt;|&gt; Hello,

&gt;From: Patrick Connolly &lt;p.connolly@hortresearch.co.nz&gt; &gt;To: &quot;RenE J.V. Bertin&quot; &lt;rjvbertin@hotmail.com&gt; &gt;Subject: Re: [R] changing (core) function argument defaults? &gt;Date: Thu, 18 Nov 2004 11:43:10 +1300 &gt; &gt;On Wed, 20-Oct-2004 at 07:48PM +0200, RenE J.V. Bertin wrote: &gt; &gt;|&gt; Hello,

I'm asking on this list because the question will be more easily understood than on a Perl list. Lots of talented people using R also know how to use Perl, so it's easier to ask them. Running a Perl script with the -d switch can do some pretty neat things, but as far as I can tell, every line has to be done individually. Is there a way to specify where to stop in the way browser() does

platform i686-pc-linux-gnu arch i686 os linux-gnu system i686, linux-gnu status major 1 minor 5.1 year 2002 month 06 day 17 language R I've been using bwplot to plot a dataframe that has a structure like this: str(plot.df) `data.frame': 5952

I have a square matrix wherein a '*' indicates an HSD between the levels indicated by row name and column name. The '.' is simply marking the diagonal. A blank indicates the same group A B C D E F G H I J K L M N A . B . C * * . D * * . E * * * . F * * * .

I've been looking at the kinship package which looks as though it might be appropriate for my purposes. What I can't find is any reference to the data that is used in the example code. A dataframe called d10 with column names, upn, dadid, momid, sex and affect is required. One can get an idea of what sort of values should be in most columns from the description in the pedigree function,

I seem to remember this was discussed a year or two ago, but I can't find it in the archives. platform i686-pc-linux-gnu arch i686 os linux-gnu system i686, linux-gnu status major 1 minor 7.0 year 2003 month 04 day 16 language R

I'm baffled. When I run make check after installing from source, I get a Error 2. From my understanding of how these things work, it would appear to be coming from this (as at the end of base-Ex.Rout.fail: > has.VR <- require(MASS, quietly = TRUE) Attaching package 'MASS': The following object(s) are masked from package:base : confint confint.lm nclass.FD nclass.scott

Some years ago when I used S-PLUS, I seem to remember, there was a discussion about a simple method of removing trailing spaces from vector elements. I'd be fairly sure the same would work in R, but I can't find any mention of anything like it in the R archives or with help.search(). There are ways I could do it with substring(), but I seem to remember there was something more elegant.

Dear R-help, I've run into a problem loading .RData: I was running a large computation, which supposedly produce a large R object. At the end of the session, I did a save.image() and then quit. The .RData has size 613,249,399 bytes. Now I can't get R to load this .RData file. Whenever I tried, I get "Error: vector memory exhausted (limit reached)". I tried adding

Of course, that's as trivial as it gets on the command line, but I can't work out how to get a column of numbers that are entered as "10^5" from its 'character' format into a numeric one? I feel a bit embarrassed asking such a simple question. Too much Easter.... Thanks -- Patrick Connolly HortResearch Mt Albert Auckland New Zealand Ph: +64-9 815 4200 x 7188