similar to: check without loop

i am sure that there is a simple solution that i am just overlooking, but there is no logical test for = there is one for != and >,<, >=, <=... what do i do if i need to check if something IS EQUAL or is there an easy way, in working with a matrix of size n x 3, to sort the matrix by one of the columns? specifically what i am trying to do is i have a matrix with individual and

i am having some problems with a program that i am writing and i think that knowing how the while command works will help me to figure out where i am going wrong *when do you get kicked out of a while loop?* (i.e., in the following example what would the final value of 'a' be?) i thought it would be 99 but running it in R i get 101 (and 101 for x too!) while (x <100) { for (i in

me again, new to R, haven't programmed in a long time at all sorry to ask what is probably basic a while ago i asked how to remove an element from a list apparently what i am using is not a list but a vector, didn't realize there was a list data type could also use a matrix for what i am doing, is there a way to remove single elements from either of those? thanks for any help, if i was

i have a set of files that i am reading into R one at a time and applying to a function that i have written where each is a 'table' n (columns) x 10000 (rows) n varies across the files and most of the rows only have data in the first few columns currently i am reading them in with the command: read.table(file="2.75.0.997.1", header=FALSE, sep="", skip=13, fill=,

i am trying to use the sample command and have one question about it: i am getting the error Error in sample(length(x), size, replace, prob) : insufficient positive probabilities when i use something like: sample (1:4, prob=c(0,0,1,0))[1] i was expecting that to return a 3 every time while this is not exactly what i am using it for, i need the capabilities to deal with zeros (as the

i have a 2 x n matrix that is a paired list of connections, i am working with that looks something like: 1 2 1 3 1 5 2 1 2 3 3 1 3 2 4 5 5 1 5 4 for later operations it would be helpful if i could change this into the form of: 1 2 3 5 2 1 3 3 1 2 4 5 5 1 4 the initial list is randomly generated and the max number of times that any one number can appear is previoulsy defined by a limiting

i have a function that returns a list containing a variety of variable types i am trying to run the function multiple times and return the output into a variable with a semi-consistent naming pattern i.e., for ten trials i want to return the list into variables trial1,trial2,...trial10 is there a generic way to get this to happen i have a similar process that does the same thing to an external

Dear All, I have a data set with the following structure: [A], [a], [B], [b] where [A] and [B] are measurements and [a] and [b] are the associated uncertainties. I produce [B]/[A] vs. [A] plots in R and would like to show uncertainties as error ellipses (rather than error bars). Would this be relatively easy to do in R? I would appreciate any help on this Thanks a lot Tibi

All! This piece of code: zzz1 <- as.POSIXct("1999-03-18", tz="CET") zzz2 <- as.POSIXlt("1999-03-18", tz="CET") zzz1 == zzz2 as.Date(zzz1) as.Date(zzz2) yields TRUE for "zzz1==zzz2", but the two dates returned by as.Date are different: > as.Date(zzz1) [1] "1999-03-17" > as.Date(zzz2) [1] "1999-03-18" I'm

Hello listers, Does anybody know how to add text to an xyplot without whipping out the existing curve? That's all. For instance, Lets say you generate a graph like this A <- data.frame(x = rnorm(100), y = rnorm(100)) xyplot(y ~ x, data = A) How would you add 'Hello world'? I tried 6.02E23 different partial solutions found on the web and failed. I just need one EXAMPLE that

Hello, I need to select a sample from a small population using simple random sampling without replacement. I've found two possibilities in R, the function sample() and the function S.SI() in the package TeachingSampling, but I don't know which one is better. Can someone help me? Thank you -- Lourdes Molera Peris M?todos Cuantitativos para la Econom?a y la Empresa Facultad de Econom?a

Hi all, In a data-frame, I have two columns of data that are categorical. How do I form some sort of measure of correlation between these two columns? For numerical data, I just need to regress one to the other, or do some pairs plot. But for categorical data, how do I find and/or visualize correlation between the two columns of data? Thanks!

How should I analysis it in R ???? all the resposes variables are ordinal from 0 to 10. and the explanatory variable is a factor ... -- View this message in context: http://old.nabble.com/Multivariate-problems-.-.-.-with-200-resposes-variables-and-1-explanatory-variable-tp26522912p26522912.html Sent from the R help mailing list archive at Nabble.com.

Hi dears while modeling an interaction random effect in lmer i receive the instantaneous error message > ldlM4<-lmer(ldl~rt*cd4+age+rf+pharmac+factor(hcv)+ + hivdur+(rt:cd4|id),na.action=na.omit,REML=F) *Warning message: In mer_finalize(ans) : false convergence (8) * I think the matter lies in syntax, 'cause i sistematically receive the same message even when changing response... PS:

Hello, I am learning R and I am fluent in Stata and I try to translate part of my Stata code to R to check the reliability of the data under R. I have a proportion variable as a dependent variable pQSfteHT . Independent variables are dummies for two categorical variables called dQSvacrateHTQuali3 and cluster_3. I am fitting a model with the Stata command below: glm pQSfteHT dQSvacrateHTQuali3_2

Hi, x <- 0.2*5 is.integer(x) gives me FALSE because R stores it as a float number, right? Is there an elegant way to work around that problem? Right now I'm using x <- 0.2*5 round(x) == x which returns TRUE. But more strictly I should use all.equal(), right? I somehow just don't like the--pardon--ugliness of those pieces of code. Maybe there is a beautiful

Hi, R users, I'm using the "lme" function in R to estimate a 2 level mixed effects model, in which the size of the subject groups are different. It turned out that It takes forever for R to converge. I also tried the same thing in SPSS and SPSS can give the results out within 20 minutes. Anyone can give me some advice on the lme function in R, especially why R does not converge?

Dear R users, I’ve search the R site for help on this topic but it is hard to find a precise answer for my questions. Which are the best options to overcome the RAM memory limitation problems when using R on “large” data sets (such as 2 or 3 million records)? - Is the free available version of R (as opposed to the one provided by REvolution Computing) compatible with a windows 64-bit

Can R support data manipulation programming that is available in the SAS datastep?  Specifically, can R support the following: -          Read multiple dataset one record at a time and compare values from each; then base on if-then logic write to multiple output files -          Load a lookup table and then process a different file; based on if-then logic, access and lookup values in the table

Hello, I wanted to fit a linear mixed model to a data that is similar in terms of design to the 'Machines' data in 'nlme' package except that each worker (with triplicates) only operates one machine. I created a subset of observations from 'Machines' data such that it looks the same as the data I wanted to fit the model with (see code below). I fitted a model in