similar to: How do delete all R objects out off a function?

Dear r-devel list members, On a couple of occasions I've encountered the issue illustrated by the following examples: --------- snip ----------- > mod.1 <- lm(Employed ~ GNP.deflator + GNP + Unemployed + + Armed.Forces + Population + Year, data=longley) > mod.2 <- update(mod.1, . ~ . - Year + Year) > all.equal(mod.1, mod.2) [1] TRUE > > f <-

Hi all, how do I change the magnification of xaxis annotation? I need a smaller axis text size in some of my plots. I tried cex.axix=0.5 in plot(), but this doesn't work. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Dear R-help, Can anyone tell me if it's possible to call up the "directory chooser" (the one you get when you click on "File" -> "Change Dir...") in Rgui from the R command line? Seems like file.choose() can't be used to choose a directory. This is in R-1.8.1 on WinXPPro. Any help much appreciated! Andy

Hi all, I don't understand the behavior of is.integer(): > x <- integer() > is.integer(x) [1] TRUE > x <- 10 > is.integer(x) [1] FALSE > x <- 1:10 > is.integer(x) [1] TRUE Why is.interger() returns FALSE if x has only one element? And how can someone check if x is an integer but contains only one value? (R 1.5.0 on Linux i386) Thanks, Sven

Hi all, there is a vector v with several NAs. I want to create a new vector n of the same length as v and the same NAs as in v and tried this: n <- vector(length=length(v), mode="numeric") replace(n, which(is.na(v)), NA) but this does't work, all values in n are 0. What went wrong? Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

Dear R list members, I'm encountering a problem with expand.model.frame(): Suppose that I define the following simple function (meant just to illustrate the problem): > fun <- function(model){ + expand.model.frame(model, all.vars(formula(model))) + } > and I have the following model, created with an explicit data argument: > mod Call:

Hi, I use R with XEmacs and ESS, when I'm editing a R file in XEmacs, the delete key work like the Backspace key. This behaviour is only in XEmacs + ESS + R file, it dont have this behaviour on a R section (M+R). Anybody know how to make a delete key to work like the delete key?? ESS 5.1.20-2 XEmacs 21.4.6-8 Thanks for all -- You will always have good luck in your personal affairs. --

Hi all, suppose I've got a vector y with some data (from a repeated measure design) observed given the conditions in f1 and f2. I've got a model with two unknown fix constants a and b which tries to predict y with respect to the values in f1 and f2. Here is an exsample # "data" y <- c(runif(10, -1,0), runif(10,0,1)) # f1 f1 <- rep(c(-1.4, 1.4), rep(10,2)) # f2 f2 <-

Hi there, if I copy an x11() graphics device to an eps-file (with dev.copy2eps()) the font in the legend is very large and doesn't fit to the legend box in the eps-file (same with a postscript file). I'm not sure if this is a R problem rather than a ghostscript one. But is there a way to solve this problem in R or depends this on my ghostscript installation? System: R Version 1.2.3 on

Dear r-devel list members, I find that adding --sdi to the Target field in the short-cut for R is ineffective in R 2.3.0 beta for Windows (version/platform details below). Setting MDI = no in the Rconsole file works, however. It's probably a bit late to request this for version 2.3.0, but it would be nice to be able to select either the SDI or MDI in the R Windows installer. Regards, John

How about -- d is a vector as you described it, then define d1 <- d[1:(length(d)-1)] d2 <- d[2:length(d)] d3 <- d1!=0 & d2!=0 & (d1-d2)!=0 I think d3 is the final vector you wanted. I didn't test it, so I'm not sure my logic is right, but I think this is definitely a path you can take... -----Original Message----- From: owner-r-help at stat.math.ethz.ch

Dear list members (esp. Duncan), I've run into the following curious problem with Version 2.2.0 alpha for Windows: Options in the Profile file in R's etc directory don't appear to be set. (I habitually uncomment options(chmhelp=TRUE), to no effect in this case.) As far as I can see, the only thing non-standard about my installation is that I put R 2.2.0 alpha under c:\R rather than

Hi there, when plotting a time series I got this error message: Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ In addition: Warning messages: 1: longer object length is not a multiple of shorter object length in: vx.1[int.lr] + (-1) * vx.2[int.rl] vx.1[int.rl] and vx.2[int.rl] have the same length. Does anybody know what the warning message means? Thanks, Sven

Hi all, I can't figure out how to compute Wilks Lambda in a one way repeated measure design. My matrix looks like: > t2.m Blank ECR ENC UEA UED 1 -0.15 0.14 0.16 0.09 0.14 2 0.30 0.08 0.14 0.14 0.14 [...] where each row is a case and the columns are levels of one factor (named trial): > t2.fit <- manova(t2.m ~ 1) > summary(t2.fit, intercept=T,

Dear list members, I'm getting the following error from R CMD check under Windows only with R 2.10.0 devel: ------------- snip ----------- * installing *source* package 'Rcmdr' ... ** libs making DLL ... gcc -I"c:/R/R-2.10.0dev/include" -O3 -Wall -std=gnu99 -c ismdi.c -o ismdi.o gcc -shared -s -o Rcmdr.dll tmp.def ismdi.o -lRgraphapp -Lc:/R/R-2.10.0dev/bin -lR

Hi list, can anybody point me to the trick how glm is computing the dispersion parameter in quasi-poisson regression, eg. glm(...,family="quasipoisson")? Thanks &regards, Sven

Hi all, how can I remove objects from the workspace which starts with a certain pattern, e.g. lm (lm1, lm2, lm3 etc). Wildcards won?t work. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the

Dear R-List, I?m new in R, so I hope my question is not to primitive, but I haven?t found a solution in the R-help. I?ve got a datatframe with 3 factors, called xf (9 levels), yf (9 levels), zf (3 levels) and one variable (rt): > xf yf zf rt > 1 1 1 67 > 1 1 1 56 > 1 1 1 60 [...] > 1 1 2 58 > 1 1 2 61 [...] > 9 1

Dear list members, I have problems to interpret the coefficients from a lm model involving the interaction of a numeric and factor variable compared to separate lm models for each level of the factor variable. ## data: y1 <- rnorm(20) + 6.8 y2 <- rnorm(20) + (1:20*1.7 + 1) y3 <- rnorm(20) + (1:20*6.7 + 3.7) y <- c(y1,y2,y3) x <- rep(1:20,3) f <- gl(3,20,

Dear R-list, is it possible to convert a threedimensional array to a matrix? The array has the form , , -4 -4 -3 -2 -1 0 1 2 3 4 -80 1588 NA 1171 NA 1121 NA 852 NA 1580 0 1497 NA 1311 NA 762 NA 1185 NA 1466 80 1960 NA 1257 NA 941 NA 1435 NA 1636 [...] I need a matrix like -80 -4 -4 1588 -80 -3 -4 NA -80 -2 -4 1171 etc. I?ve tried write.table() with no succes: