similar to: Standardized Beta?

R 2.2.0 windows XP How can I perform a regression analyses using a vector of means, a variance-covariance matrix? I looked at the help screen for lm and did not see any option for using the afore mentioned structures as input to lm. Thanks, John John Sorkin M.D., Ph.D. Chief, Biostatistics and Informatics Baltimore VA Medical Center GRECC, University of Maryland School of Medicine Claude D.

Hello, I''m inexperienced with linux, X11 and R. A font problem have surfaced. When I use pairs in John Fox''s car library e.g.: > pairs(cbind(prestige, income, education, women)) Error in text.default(x, y, txt, cex = cex, font = font) : X11 font at size 16 could not be loaded In addition: Warning message: freeing previous text buffer in GText > Evidently

Hi all, I've got at really basic Q for you all: How do I produce a 3D plot in R? Like the one in the screenshot on the R-project wab-page. What is the command? /Fredrik -- ----------------------------------------------------------------- Fredrik Karlsson, Research Student Department of Philosophy and Linguistics Ume? University S-901 87 UME? SWEDEN Tel: +46 90 786 56 84 Web:

Hi all This seems like a very easy question, but I have not found a simple answer to it: If you have a dataframe, how to you plot two of then in different colors depending on a third variable? All help appreciated! /Fredrik -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Dear list, I would like to create histograms for up to three groups, with distincive colour/pattern, in a trellis panel. However, I have not been able to find a way to do this. histogram does not seem to have a group argument. Please help. /Fredrik

Dear list, Sorry for asking this very silly question on the list, but I seem to have made my life complicated by going into string manipulation in vectors. What I need is to get the last part of a sting (the two last tokens, separated by a space), and of course, this should be done for all strings in a vector, creating a new vector of exual size. So, a <- c(" %L H*L L*H H%",

Hi there, after several problems with installing R on a Debian server It now finally works at least roughly. With roughly I mean that the 'core' function do work properly, but I'm still having problems with the image export. When I try to call png(filename="my_file.png", width=800, height=300, pointsize=12, bg = "white") I just get the error message

Hi all, I'm a potential new user of R and have to know this before I start using it: SPSS does not let you do a Post Hoc analysis on repeated measures data. This is a problem for me, since that is what I will have to do. Will R let me do this? /Fredrik -- ----------------------------------------------------------------- Fredrik Karlsson, Research Student Department of Philosophy and

Dear list, I have been working on a report with around 60 images in it, and everything has been fine, until now. I find that the image output that is produced by odfWeave produces images that are NOT readable by OpenOffice or NeoOffice. I get empty boxes with Read-Error written in them. While generating the file using odfWeave, I can see them being generated on the screen, and they all seem fine.

Hi all! I want to do some logistic regression. Is there a fintion in R that does this, or do I have to do the variable conversion by hand? Thankful for all the help I can get. /Fredrik -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Hi all I'm trying to complete a textbook example originally designed for SPSS in R, and I therefore need to find out how to compute an unbalanced ANOVA in R. I did a search on the mailinglist archives an found a post by Prof. Ripley saying one should use the lme function for (among other things) unbalanced ANOVAs, but I have not been able to use this object. My code gives me an error.. Why

Dear R-devel list members, I'd like to suggest a more flexible procedure for generating contrast names. I apologise for a relatively long message -- I want my proposal to be clear. I've never liked the current approach. For example, the names generated by contr.treatment paste factor to level names with no separation between the two; contr.sum simply numbers contrasts (I recall an

Dear R list members, I'm encountering a problem with expand.model.frame(): Suppose that I define the following simple function (meant just to illustrate the problem): > fun <- function(model){ + expand.model.frame(model, all.vars(formula(model))) + } > and I have the following model, created with an explicit data argument: > mod Call:

Hello Rui, Thanks for your helpful suggestions. Just for illustration, let's use the well known Duncan dataset of prestige vs education + income that is contained in the "car" package. Suppose I wish to use boot function to bootstrap a linear regression of prestige ~ education + income and use the following script: duncan.function <- function(data, indices) {data =

Dear list, I have a table that I would like to convert to latex for inclusion into a Sweave file. > round(ftable(prop.table(xtabs(~agemF + votcat + Type , data=work),margin=2))*100,1) Type Voiced Voiceless unaspirated Voiceless aspirated agemF votcat 18 - 24 Prevoiced 2.6 8.7

Dear list, I'm making my current code more generic and would like some advise. The basic problem is subset and the name of the column to be compared for selection. What I've come up with is > data(mammals) > set <- bottompremolars" > subset(mammals, eval(parse(file="",text=set)) > 2) This seems a bit odd. Is there a nicer way? /Fredrik

Hello, Much clearer now, thanks. It's a matter of changing the function boot calls to return the predicted values at the point of interess, education = 50, income = 75. I have changed the way the function uses the indices a bit, the result is the same, it's just the way I usually do it. pred.duncan.function <- function(data, indices) { mod <- lm(prestige ~ education +

Hi, I am trying to get into this REST thing, I have a nested resource whith the following route: ActionController::Routing::Routes.draw do |map| map.resources :members map.resources :clubs do |club| club.resources :members end map.connect '':controller/:action/:id'' map.connect '':controller/:action/:id.:format'' end Everything worked ok for this

Hi all, This is a potentially very stupid question about MySQL <-> R interaction, but I have not been able to solve it. I'm just trying to connect R to my MySQL databse, and gets this: > library(RMySQL) Loading required package: methods > m <- dbDriver("MySQL") > con <- dbConnect(m,group="testdb") Process R segmentation fault at Wed Oct 16 07:04:30

I noticed that when I fit a linear model using 'lm' there is an attribute called "factors" that is added to the "term". It doesn't seem to appear for 'model.matrix', just 'lm'. I have been unable to find where it gets constructed or what it means? It looks like a two dimensional array that I may be able to use so I would just like to get some