similar to: Weekdays

Hi, how it's possible to extract the year and the number of days from Julian date. i'm little confused about the last two functions and ?years . EDATE comes from sqlQuery with as.is=T EDATE <- as.POSIXlt(datvears$ENROLLDAY) Many thanks, Christian > EDATE[1:5] [1] "2000-06-30 11:25:01" "2000-06-30 11:39:55" "2000-06-30 12:11:11" [4]

I''m using Rails - 2.2.2 gcal4ruby (0.2.6) I''m using google calendar to display events for users in my website. Till 18-march-2012 everything was working fine. But now whenever user add events to the calendar it show only busy in the calendar. My code is def add_event user_id = current_user.id service = GCal4Ruby::Service.new

Hi all, probably really simple: I seem to be lacking some understanding for the character class: I have a bunch of dates in a dataframe and I want to add a string variable with the weekday for each date. If I use something like mydata$day <- weekdays (mydata$date), I can create subsets for each weekday (eg mydata=="Monday"), but summary (mydata$day) doesn't count the instances for

Dear R-users, How do I obtain a sequence of dates consisting of only weekdays without the weekends in R? In S, I can do the following: timeSeq(from="12/17/2007", to="8/25/2008", by="weekdays") I tried using looking at timeSequence (fSeries package) and seq.Date (base package) but I do not know if I can specify "weekdays" rather than "day".

Hello, This doesn't answer the question, but in portuguese it works as expected. > x <- as.Date("2017-06-05") > months(x) [1] "junho" > weekdays(x) [1] "segunda-feira" > sessionInfo() R version 3.4.0 (2017-04-21) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 7 x64 (build 7601) Service Pack 1 Matrix products: default

Hi, I want to reporte some strange behaviour with the "months" function, from base R. When using "months" to extract months from a date column, I'm getting the months in english, when I was expecting months in spanish. When using "weekdays" to extract days of week from a date column, I'm getting the the days in spanish (as expected). My understanding is

For what it's worth, I tried setting my Region | Formats setting to Spanish (Peru) in Windows 10 Control Panel, and got Spanish weekday and month results. I believe on Windows we use the Microsoft C strftime function to produce these strings, with the %A (for weekday) or %B (for month) formats. So this question probably needs to be addressed to Microsoft. Duncan Murdoch On 05/06/2017

Thank you Duncan and Rui for your time and interest in this issue. Maybe it is a problem with Windows 7 and Spanish, and not Windows 10. Let's wait for someone with the same enviroment, before assuming it's a problem with my PC/configuration. 2017-06-05 14:37 GMT-05:00 Duncan Murdoch <murdoch.duncan at gmail.com>: > For what it's worth, I tried setting my Region

Dear all, can anyone please tell me how to generate a sequence of days continuously, however without considering weekends i.e. Saturday and Sunday? I am aware of following code: > seq(as.Date("2010-01-01"), as.Date("2010-02-01"), by="1 day")  [1] "2010-01-01" "2010-01-02" "2010-01-03" "2010-01-04" "2010-01-05"

Have you noticed any problems with big dates (>=1/1/2040) in R? Here is the bit of code that I'm having trouble with: > test.date <- strptime("1/1/2040",format="%m/%d/%Y") > > unlist(test.date) sec min hour mday mon year wday yday isdst 0 0 0 1 0 140 0 0 0 > > date.plus.one <- as.POSIXct(test.date) +

Dear R Helpers, I am having difficulty with strptime. I wish to find the differences between two vectors of times. I have apparently no difficulty to convert the vectors to the appropriate format using strptime. But, then difftime does not calculate all the differences. Here is the code and output:- dob=strptime(as.character(datx$BDT),'%d-%b-%y'); dob$year=dob$year-100

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use:

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

Hi One of the most important calculation in applied finance is the number of days between dates. That kind of calculus become annoying when a specific calendar must be used. That is the case for the business days calculus. The package timeDate has a function isBizday to perform that kind of thing. The problem is that using this function to calculate the number of business days between dates has

Thanks Don MacQueen for this reply to my initial query - please SEE MY REPLIES TO THESE IDEAS AND FURTHER INFORMATION BELOW >From: Don MacQueen [macq at llnl.gov] >Sent: 23 February 2010 21:25 >To: Jonathan Williams; r-help at r-project.org > >Subject: Re: [R] Problem with strptime generating missing values where none appear to exist > >What happens if you do all that NA

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Hi list, I'm trying to turn a date into something productive. (Not what you may be thinking....) I want three functions so I could take a "date" object and get the day of week, month, and year from it. xx <- as.Date("2006-01-05") month(xx) equal 1 day(xx) equal 5 year(xx) equal 2006 I'm aware of the weekdays() and months() functions in the base package. But

This is mostly a RFC [but *not* about the many extra packages, please..]: Noticing to my chagrin how my students work in a project, googling for R code and cut'n'pasting stuff together, accumulating this and that package on the way all just for simple daily time series (though with partly missing parts), using chron, zoo, lubridate, ... all for things that are very easy in base R *IF*

My environment.rb contains config.time_zone = ''UTC'' If my understanding is correct, rails should assume time values coming from the database are UTC, and since config.time_zone is set to ''UTC'', it should not try to convert the times. Instead, rails is assuming that the db values are Eastern (my local zone) and is incorrectly adding four hours to convert to