similar to: xtabs

Recently, I noted a post and replies on R-Help from Professor Marc Feldesman regarding a cross tabulation function that generates row and column proportions, marginal values, expected cell values and tests for independence presumably similar in a fashion to the output of the S-Plus crosstabs() function or the SAS Proc Freq. Martin Maechler had posted some code in reply for folks to update and

i have a data frame(dat) which has many variables.and i use the following script to get the crosstable. >danx2<-c("x1.1","x1.2","x1.3","x1.4","x1.5","x2","x4","x5","x6","x7","x8.1","x8.2","x8.3","x8.4","x11",

I'm running 1.9.1 on Mac OS X 10.1. My simple question is whether there is a crosstabs-like command (I know about "xtabs" which is much like "table") that computes not only cell counts but also row, column, and cell percents. Something like crosstabs(~x+y) in S-PLUS. Thank you.

Good Day, Included below is some code to generate data and to fit a mixed effects model to this fake data. The code works as expected when I call the function "lme" in Splus but not in R. The error message from calling lme in R is: "Error in getGroups.data.frame(dataMix, groups) : Invalid formula for groups" I installed the nlme package for R around 20 August

Hello, My colleague and I would like to write Java code that invokes R to do a simple TTest. I've included my sample java code below. I tried various alternatives and am unable to pass a vector to the TTest method. In my investigation, I tried to call other R methods that take vectors and also ran into various degrees of failure. Any insight you can provide or other Web references you

Let me clarify my question. I have a struct array h1 as follows: dhash h1[10]; I want to get a Constant* to variable h1. It looks like I can use ConstantStruct::get(StructType*, ArrayRef<Constant *>) to do this. My question is how to get the second argument of type ArrayRef<Constant *> from the above variable h1. Thanks, Chaitra ________________________________ From: Tim Northover

Hi, I need to compare two matrices with each other. If you can get one of them out of the other one by resorting the rows and/or the columns, then both of them are equal, otherwise they're not. A matrix could look like this: [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [1,] 0 1 1 1 0 1 1 0 [2,] 1 1 0 0 0 1 0 1 [3,] 1 0 1 0 0

Thank you very much. The code to initialize h1 to non-zero values was what I was looking for. It's almost working except for a type mismatch wrt dlist* llist field of h1. dlist static_lst[10] = { {1, 5, NULL}, ... }; dhash h1[10] = {{"myfile.txt", static_lst}, ... }; Along the lines of the code you had sent, I created a GlobalVariable* llist of type [10 x %struct.dlist]* for the

Hi all, There are matrices with same column names but arranged in different orders and I desire columns of these matrices to have same order. For example, below are 2 arbitrary data sets with columns arranged in different order. I require columns of these to have same order as specified in "columns" object and the results stored in the original object names. I know this can be done

How can i replicate this in Linux: source(file.choose()) I've tried source(tkgetOpenFile()) but with no luck

Hello, I would like to create a global variable for the following struct array, h1 dhash* h1 = new dhash[10]; typedef struct dhash{ char* filenm; dlist* llist; }dhash; typedef struct dlist{ int soffst; int eoffst; uint8_t* dptr; }dlist; I also need to allocate space for: 1) the field llist in struct dhash which is a pointer to another struct dlist and 2) the field

Good Day, I'm using the knn function in the package class. With k set to 3, the function returns proportions of 1/3, 0.5, 0.6, 2/3, 3/4, and 1.0 for the test cases. I don't understand how with k set to 3 the proportions can be anything other than 1/3, 2/3, or 1.0 I've seen similar inconsistencies with k set to 5. R version 2.5.0 with redhat linux. Thanks in advance. Mike

Good Day, I fit a multivariate linear regression model with 3 dependent variables and several predictors using the lm function. I would like to use stepwise variable selection to produce a set of candidate models. However, when I pass the fitted lm object to step() I get the following error: Error from R: Error in drop1.mlm(fit, scope$drop, scale = scale, trace = trace, k = k, : no

Hi, I'm a new R user. I noticed that RKWard has a really nice output when it does crosstabs. It even includes the chi-squared values. However, I obviously can't simply copy this into my standalone R script. Does anyone know the code or a way for me to view the code. Secondly, if I am writing an R script I want to be able to view the output as a pdf even if my function is not a graph,

Hi all! What is the equivalent R function of SPLUS crosstabs? Thank you. Danar. Stat. Inst. Umea Univ. Umea, Sweden -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To:

I see that feature freeze for a better than ever R has been announced. May I ask if there will be or could be "merge" function for data frames? I believe it would be very nice if this were "centrally" implemented (with regard to my humble steps to writing such a function and the related error and other precautions). I know from VR2R.pdf (courtesy Profs. Venables and Ripley)

Is there any existing function for creating contingency tables that will display counts, row, column, and cell percentages in the same tables....anything similar to crosstabs in S? Marc W. Zodet, MS Health Statistician Center for Cost and Financing Studies Division of Statistical Research and Methods 2101 East Jefferson Street, Suite 500 Rockville, Maryland 20852 Phone: 301-594-7072 Fax:

Is there a crosstabs function like the one found in S-Plus available in any of the R addon packages? I can't seem to locate anything other than the chisq.test, which is adequate but does not yield the output customarily required with any journal submission (in my field). (S-Plus, SPSS, SAS all provide examples of the required output). If there isn't such a function already

Hi All, I'm still pretty new to using R - and I was hoping I might be able to get some advice as to how to use 'apply' or a similar function instead of using nested for loops. Right now I have a script which uses nested for loops similar to this: i <- 1 for(a in Alpha) { for (b in Beta) { for (c in Gamma) { for (d in Delta) { for (e in Epsilon) { Output[i] <-

I've been playing around with various table tools, trying to construct a fairly simple cross-tab. It shouldn't be hard, but for some reason it turning out to be (for me). If I want to see how many men and how many women agree with a agree/disagree question (coded 1,0), I can do this: >attach(mydata) >mytable <- table(male, q1.bin) # gender and a binary response variable