Displaying 20 results from an estimated 4000 matches similar to: "Functions on matrix row level"
2002 Jun 11
1
SSH / PAM Problem
Hallo
da mein English nicht so gut ist und bei der ?bersetzung auch noch
Missverst?ndnisse auftretten k?nnten, hier das Orginal :-)
Das Problem ist, dass bei der Kombination openssh pam und ldap, die
Verbindung zum Ldapserver so lange offen gehalten wird bis die ssh
Session geschlossen wird. Das ist nur bei SSH so ! Alle andere Dienste
sprechen den Server an und schliessen nach Best?ttigung des
2002 Jan 05
1
R-WinEdt question - answer
The answer to my question was contained in
http://cran.r-project.org/contrib/extra/winedt/ReadMe ,
although it helped to receive the restatements that were emailed to me.
As mentioned by Uwe Ligges, Renuad Lancelot, Niels Waller, my mistake was
not starting R before
using R-WindEdt.
Below I will copy the instructions on using R-WinEdt by Renaud Lancelot
(except for the last paragraph which is
2003 Mar 25
1
structure only
Hi people,
I used to copy filesystem structures ( only Directories ) with rsync
version 2.3.1.
For this I used
rsync -e ssh -trulogxp - -include "*/" - -exclude "*"
remotemaschine:/source /localtraget
Now, on a new maschine with rsync version 2.5.5 that doesn?t work any more.
Now rsync copies directories and files, too.
Is is possible to do a workaround with the newer
2008 Dec 17
1
using dvi with latex object: directory not correctly set, maybe due to error in shQuote()
Dear friends of R,
I want to produce a pdf file with the contents of a matrix. I employ the latex command in combination with dvi, both contained in the Hmisc package. It seems to me that the function does not correctly set the directory.
> tbl.loc <- matrix(1:4, nc=2)
> latex.obj <- latex(tbl.loc)
> dvi(latex.obj)
warning: extra args ignored after 'cd'
H:\PROJECTS\data
2003 Jan 03
0
Digital unterschriebene E-Mail von FreeMail / Digitally signed email from FreeMail
(english version see below)
Sie erhalten in den naechsten Minuten eine digital unterschriebene E-Mail
von einem Freemail-Anwender. Damit Ihr E-Mail-Programm den Ausweis
ueberpruefen kann, muss das "Root-Zertifikat" von WEB.DE installiert sein.
Klicken Sie dazu bitte auf:
http://trust.web.de/root.sql
Auf dieser Web-Seite finden Sie eine genaue Anleitung zur Installation des
Zertifikats
2012 May 22
3
How to remove square brackets, etc. from address strings?
Hello,
I'd like to remove the individual pairs of square brackets along with
their content - plus the space directly behind it - from address strings
such as this:
[Swidsinski, Alexander; Loening-Baucke, Vera; Lochs, Herbert] Charite
Humboldt Univ, Innere Klin, D-10098 Berlin, Germany; [Hale, Laura P.]
Duke Univ, Med Ctr, Dept Pathol, Durham, NC 27710 USA
I'd like get the
2009 May 15
2
Help with loops
Hi
I am trying to create a loop which averages replicates in my data.
The original data has many rows. and consists of 40 column zz[,2:41] plus row headings in zz[,1]
I am trying to average each set of values (i.e. zz[1,2:3] averaged and placed in average_value[1,2] and so on.
below is my script but it seems to be stuck in an endless loop
Any suggestions??
for (i in 1:length(average_value[,1])) {
2009 May 15
1
Fw: Help with loops(corrected question)
--- On Fri, 15/5/09, Amit Patel <amitrhelp at yahoo.co.uk> wrote:
> From: Amit Patel <amitrhelp at yahoo.co.uk>
> Subject: Help with loops
> To: r-help at r-project.org
> Date: Friday, 15 May, 2009, 12:17 PM
> Hi
> I am trying to create a loop which averages replicates in
> my data.
> The original data has many rows. and consists of 40 column
> zz[,2:41]
2013 May 11
1
How to repeat 2 functions in succession for 400 times? (microarray data)
Hi,
May be this helps:
?set.seed(24)
?mydata4<- as.data.frame(matrix(sample(1:100,10*38,replace=TRUE),ncol=38))
?dim(mydata4)
#[1] 10 38
?library(matrixStats)
res<-do.call(cbind,lapply(1:400, function(i) {permutation<-sample(mydata4); (rowMeans(permutation[,1:27])-rowMeans(permutation[,28:38]))/(rowSds(permutation[,1:27])+rowSds(permutation[,28:38]))} ))
?dim(res)
#[1]? 10 400
A.K.
2008 Jun 12
3
Problem with rowMeans()
Hi all,
I have a matrix called 'data', which looks like:
> data[1:4,1:4]
Probe_ID Gene_Symbol M1601 M1602
1 A_23_P105862 13CDNA73 -1.6 0.16
2 A_23_P76435 15E1.2 0.18 0.59
3 A_24_P402115 15E1.2 1.63 -0.62
4 A_32_P227764 15E1.2 -0.76 -0.42
> dim(data)
[1]
2011 Feb 10
2
Calculating rowMeans from different columns in each row?
Hello!
I have a dataset like this:
X1 X2 X3 X4 X5 X6 X7 X8
1 2 2 1 2 3 2 6
2 3 2 5 7 9 1 3
1 9 12 6 1 1 3 6
The columns X1-X6 contains ordinary numeric values.
X7 contains the number of the first column that the rowMeans should be calculated from and
X8 contains the last column
2012 Oct 12
1
Error in rowMeans function
Hello,
I am trying to create parcels for a CFA model. I am trying to average 6 sets of 3 variables each into parcels. I don't understand why I am getting an error message as follows:
Thanks for your help,
Catherine
atds1par <- rowMeans(semHW1dat1[, c("atds1", "atds2", "atds3")], na.rm=TRUE)
atds2par <- rowMeans(semHW1dat1[, c("atds4",
2008 Jun 28
2
[LLVMdev] need to store the address of a variable
Hello everybody,
my problem is, that I want to get an array of pointers to all local variables
in a function. This array will be used for transfering these Variables to
another execution engine.
I've code which generates this array, and a pointer to the target field of the
array.
name = variables.fname + "_pointerArray";
Instruction* pointerArray = new
2007 Nov 25
2
rowMean, specify subset of columns within Dataframe?
I would like to calculate the mean of tree leader increment growth over 5
years (I1 through I5) where each tree is a row and each row has 5 columns.
So far I have achieved this using rowMeans when all columns are numeric type
and used in the calculation:
Data1 <- data.frame(cbind(I1 = 3, I2 = c(0,3:1, 2:5,NA), I3
=c(1:4,NA,5:2),I4=2,I5=3))
Data1
Data1$mean_5 <- rowMeans(Data1, na.rm =T)
2017 Apr 01
3
mean(x) != mean(rev(x)) different with x <- c(NA, NaN) for some builds
In R 3.3.3, I observe the following on Ubuntu 16.04 (when building
from source as well as for the sudo apt r-base build):
> x <- c(NA, NaN)
> mean(x)
[1] NA
> mean(rev(x))
[1] NaN
> rowMeans(matrix(x, nrow = 1, ncol = 2))
[1] NA
> rowMeans(matrix(rev(x), nrow = 1, ncol = 2))
[1] NaN
> .rowMeans(x, m = 1, n = 2)
[1] NA
> .rowMeans(rev(x), m = 1, n = 2)
[1] NaN
>
2011 Feb 27
2
replacing missing values with row average
Hello,
I have some dataset, which i read it from external file using the (data <-
read.csv("my file location")) and read as a dataframe
> is(data)
[1] "data.frame" "list" "oldClass" "vector"
but i have also converted this into a matrix and tried to apply my code but
didnt work.
Anyways, suppose i have the following data.
2004 Jul 01
3
list structure question
Hi,
I have a list in which element is a vector (all of the same length and
all numeric). I want to find the mean of the first elements of the
vectors, the mean of the second elements of the vectors and so on.
Currently I convert the list to a data.frame and apply rowMeans(). But
is there a way to to do this directly on the list? I seem to recall a
post in which there was such a function (or
2011 Apr 05
1
Inconsistency between rowMeans documentation and reality?
Dear List,
I'm not even sure this is an issue or not, but ?rowMeans has:
Value:
A numeric or complex array of suitable size, or a vector if the
result is one-dimensional. The ?dimnames? (or ?names? for a
vector result) are taken from the original array.
If there are no values in a range to be summed over (after
removing missing values with ?na.rm = TRUE?), that
2015 Oct 02
0
Office 365, Windows 10 and Samba AD
Hi,
i managed to create a level 10 debug log - bug id 11538
-----Ursprüngliche Nachricht-----
Von: Dirk Laurenz [mailto:dirk at laurenz.ws]
Gesendet: Freitag, 25. September 2015 11:58
An: 'Dirk Laurenz (Samba Mailinglisten Account)' <samba at laurenz.ws>; 'David Disseldorp' <ddiss at suse.de>
Cc: samba at lists.samba.org
Betreff: AW: [Samba] Office 365, Windows 10
2008 Oct 31
4
[ifelse] how to maintain a value from original matrix without probs?
Dear all,
I have a matrix with positive and negative values.
>From this I would like to produce 2 matrices:
1st - retaining positives and putting NA in other positions
2nd - retaining negatives and putting NA in other positions
and then apply rowMeans for both.
I am trying to use the function ifelse in the exemplified form:
ifelse(A>0,A,NA)
but by putting A as a 2nd parameter it