similar to: faster vector subtraction??

Hello dear R people, for my MSc thesis I need to program some functions, and some of them simply do not work. In the following example, I made sure both vectors have the same length (10), but R gives me the following error: Error in if (vector1[i] == vector2[j]) { : missing value where TRUE/FALSE needed I googled for possible solutions, but I did not find a good explanation for this...

Dear all, I was encountering with a typical Matching problem and was wondering whether R can help me to solve it directly. Let say, I have 2 vectors of equal length: vector1 <- LETTERS[1:6] vector2 <- letters[1:6] Now I need to match these 2 vectors with all possible ways like: (A,B,C,D,E) & (a,b,c,d,e) is 1 match. Another match can be (A,B,C,D,E) & (b,a,c,d,e), however there

Hi All, I am counting the number of occurrences of the terms listed in one vector in another vector. My code runs: for( i in 1:length(vector3)){ vector3[i] = sum(1*is.element(vector2, vector1[i])) } where vector1 = vector containing the terms whose occurrences I want to count vector2 = made up of a number of repetitions of all the elements of vector1 vector3 = a vector of NAs that is

Hi All, I am trying to match two character arrays (email lists) using either pmatch(), match() or charmatch() functions. However the function is "missing" some matches due to differences in the cases of some letters between the two arrays. Is there any way to disable case sensitivity or is there an entirely better way to match two character arrays that have identical entries but written

Looking for help with the following problem. Given a sample of zeros and ones, for example: > VECTOR1<-rep(c(1,0),c(15,10)) > VECTOR1 [1] 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 How would I create a new sample (VECTOR2) also containing zeros and ones, in which the phi-coefficient between the two sample vectors was drawn from a population with a known

i am having some problems with a program that i am writing and i think that knowing how the while command works will help me to figure out where i am going wrong *when do you get kicked out of a while loop?* (i.e., in the following example what would the final value of 'a' be?) i thought it would be 99 but running it in R i get 101 (and 101 for x too!) while (x <100) { for (i in

Dear Statisticians--- This is not even an R question, so please forgive me. I have so much ignorance in this matter that I do not know where to begin. I hope someone can point me to documentation and/or a sample. I want to compute a covariance as quickly as non-humanly possible on an Intel core processor (up to SSE4) under linux. Alas, I have no idea how to engage CPU vectorization. Do I need

Hi, I have many files containing one column of data. I like to use the scan function to parse the data. Next I like to bind to a large vector. I try this like: count<-1 files <- list.files() # all files in the working directory for(i in files) { tmp <- scan(i) assign(files[count], tmp) count<-count+1 } This part works! Now I like to plot the data in a boxplot.

Hola Jose, si CONCATENAR significa APILAR, es decir, concantenar verticalmente, por decirlo de algun modo, podrias hacerlo con rbind(): nuevovector <- rbind(vector1,vector2) Si ademas quieres que cada valor de los vectores originales sea identificado en el nuevovector, puedes usar: nuevovector <- stack(vector1,vector2) en este ultimo caso se agrega una columna adicional tipo factor, con

Windows binaries at CRAN (bin/windows/Windows-NT/base) have been updated to R-1.1.0. See below for a list of Windows-specific changes. We thanks all the people who checked over pre-test versions. guido masarotto (for the R-core team) Windows-specific changes to R ============================= There is now a GUI preferences editor on the Edit menu in Rgui. A data entry editor is now

Windows binaries at CRAN (bin/windows/Windows-NT/base) have been updated to R-1.1.0. See below for a list of Windows-specific changes. We thanks all the people who checked over pre-test versions. guido masarotto (for the R-core team) Windows-specific changes to R ============================= There is now a GUI preferences editor on the Edit menu in Rgui. A data entry editor is now

Hello, My name is Ick Hoon Jin and I am Ph. D. student in Texas A & M Univ.. When I run the C embedded in R in the Linux system, I confront the following error after 6,000 iteration. By googling I found this error is from the problem in C. *** caught segfault *** address (nil), cause 'memory not mapped' My C code is following:

hi there is there a way that i can coerce a vector of integers to ONE string with the numbers comma separated like: 1:500 -> "1,2,3, ..., 500" i've tried deparse, but it divides the result into a vector of string (depending on the setting of width with a max of 500) regards soren

hi there tried to use subset with drop=TRUE, but all the 'old' levels are preserved, i.e. when calling e.g. ftable a lot of zeros are displayed >x<-subset(LREG, (kir=='AA' | kir=='BB') & (type=='t1' | otype=='t2'), drop=TRUE, select=c(event, kir, type)) > ftable(x) i explicit have to call factor like

Dear R users, I have a problem computing time differences using R. I have a date that are given using the following format: 20080620.00, where the 4 first digits represent the year, the next 2 ones the month and the last 2 ones the day. I would need to compute time differences between two vectors of this given format. I tried around trying to change this format into any type of time serie

I'm using win XP R 1.51 (Rterm) emacs-20.7 ess-5.1.20 and everything except from command completion works Is it possible to have this functionality using a windows enviroment? thanks soren -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info",

Hello everyone, I have two vectors having only one element different: vector1 vector2 vector1 TWC TWC TWC VFC TWX NA VIA/B VFC VFC

Hello everyone. I use double for loops to fill in matrices, but there are surely better (and computationally faster) ways to perform that task. Could someone show me, given the following example of a double for loop, how this could be done? It is much easier to learn by examples. Val <- matrix(0, nrow=n+1, ncol=n+1) for( i in 0:n){ for(j in 0:i){ Val[j+1, i+1] <- u^j*d^(i-j)

I have the following (simple!?) problem which I am unable to find a relatively trivial solution to. If I have a dataframe, A 1 A 7 B 4 B 5 C 3 D 3 D 2 E 5 F 5 F 6 I would like to create a new data.frame in the form ID pt1 pt2 A 1 7 B 4 5 C 3 NA D 3 2 E 5 NA F 5 6 so that for each identifier, in this

hi there is there a way to convert objects of class ftable into LaTex code preserving the 'look' with row and column infomation? xtable() {xtable} can't handle such objects and latex() {Hmisc} just texify the number matrix, without row/column information regards soren