similar to: changing the magnification of axis annotation

Hi all: I'm using 'persp' for 3D graphics. I need the axis's labels smaller than by defect. I see in 'help()', the information about 'par()'. I have wrote: >par(.....,cex.axis=0.5,cex.lab=0.5) perspc(.................) and the result don't change. The question is: Can I change the size of labels in the perps graph?? Thank you in advance: /salva

Hi all: I'm using 'persp' for 3D graphics. I need the axis's labels smaller than by defect. I see in 'help()', the information about 'par()'. I have wrote: >par(.....,cex.axis=0.5,cex.lab=0.5) perspc(.................) and the result don't change. The question is: Can I change the size of labels in the perps graph?? Thank you in advance: /salva

Hello- I'm new to R, coding and stats. (Oh no.) Anyway, I have about 12000 data points in a data.frame (dealing with dimensions and geological stage information for fossil protists) and have plotted them in a basic scatter plot. I also added a boxplot to overlay these points. Each worked fine independently, but when I attempt to superimpose them with add=true, I get a different scale for

Hi all, I don't understand the behavior of is.integer(): > x <- integer() > is.integer(x) [1] TRUE > x <- 10 > is.integer(x) [1] FALSE > x <- 1:10 > is.integer(x) [1] TRUE Why is.interger() returns FALSE if x has only one element? And how can someone check if x is an integer but contains only one value? (R 1.5.0 on Linux i386) Thanks, Sven

Dear R People, I'm working on a plot function to produce the graph shown below. One of the features my supervisor does not like is that the labels in the Y- axix are shown vertically. Is there a way to change that to horizontally ? This is the axix() function I used : axis(2,at=seq(nstrat),labels=snames) The labels (snames) are: SEV1:HU:C, SEV1:MU:C, SEV1:MU:L, SEV1:RT:C and SEV1:RT:L,

Hi all, there is a vector v with several NAs. I want to create a new vector n of the same length as v and the same NAs as in v and tried this: n <- vector(length=length(v), mode="numeric") replace(n, which(is.na(v)), NA) but this does't work, all values in n are 0. What went wrong? Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-

Hello! I use the version 1.4.0 for Windows. I have made boxplots but only half of the symbols (three letters each) show up on the X-axis? How t can one change their size or orientation so that all show up? I attach the pdf file to illustrate better the problem. Regards Martin Martin Lascoux Department of Conservation Biology and Genetics Evolutionary Biology Center Norbyv?gen 18D 75236

Hi all, suppose I've got a vector y with some data (from a repeated measure design) observed given the conditions in f1 and f2. I've got a model with two unknown fix constants a and b which tries to predict y with respect to the values in f1 and f2. Here is an exsample # "data" y <- c(runif(10, -1,0), runif(10,0,1)) # f1 f1 <- rep(c(-1.4, 1.4), rep(10,2)) # f2 f2 <-

Hi there, if I copy an x11() graphics device to an eps-file (with dev.copy2eps()) the font in the legend is very large and doesn't fit to the legend box in the eps-file (same with a postscript file). I'm not sure if this is a R problem rather than a ghostscript one. But is there a way to solve this problem in R or depends this on my ghostscript installation? System: R Version 1.2.3 on

How about -- d is a vector as you described it, then define d1 <- d[1:(length(d)-1)] d2 <- d[2:length(d)] d3 <- d1!=0 & d2!=0 & (d1-d2)!=0 I think d3 is the final vector you wanted. I didn't test it, so I'm not sure my logic is right, but I think this is definitely a path you can take... -----Original Message----- From: owner-r-help at stat.math.ethz.ch

Hi there, when plotting a time series I got this error message: Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ In addition: Warning messages: 1: longer object length is not a multiple of shorter object length in: vx.1[int.lr] + (-1) * vx.2[int.rl] vx.1[int.rl] and vx.2[int.rl] have the same length. Does anybody know what the warning message means? Thanks, Sven

Hi all, I can't figure out how to compute Wilks Lambda in a one way repeated measure design. My matrix looks like: > t2.m Blank ECR ENC UEA UED 1 -0.15 0.14 0.16 0.09 0.14 2 0.30 0.08 0.14 0.14 0.14 [...] where each row is a case and the columns are levels of one factor (named trial): > t2.fit <- manova(t2.m ~ 1) > summary(t2.fit, intercept=T,

Hi list, can anybody point me to the trick how glm is computing the dispersion parameter in quasi-poisson regression, eg. glm(...,family="quasipoisson")? Thanks &regards, Sven

Dear R-List, I?m new in R, so I hope my question is not to primitive, but I haven?t found a solution in the R-help. I?ve got a datatframe with 3 factors, called xf (9 levels), yf (9 levels), zf (3 levels) and one variable (rt): > xf yf zf rt > 1 1 1 67 > 1 1 1 56 > 1 1 1 60 [...] > 1 1 2 58 > 1 1 2 61 [...] > 9 1

Dear R-list, is it possible to convert a threedimensional array to a matrix? The array has the form , , -4 -4 -3 -2 -1 0 1 2 3 4 -80 1588 NA 1171 NA 1121 NA 852 NA 1580 0 1497 NA 1311 NA 762 NA 1185 NA 1466 80 1960 NA 1257 NA 941 NA 1435 NA 1636 [...] I need a matrix like -80 -4 -4 1588 -80 -3 -4 NA -80 -2 -4 1171 etc. I?ve tried write.table() with no succes:

Hi there, I want to read all data from a binary file (with package Rstreams). I tried the following function (small piece of code): readdata <- function (file) { # open file s <- openstream(file, "read") # read int values while (s$position <= s$size) { readint(s, 1, 2) -> type [...] } return() } and got the following error: > Error in

Hi all, I computed a Wilks Lambda Test with manova: > df.man <- manova(df.mul ~ 1, na.rm=TRUE) > summary(df.man, intercep=T, test="Wilks") Df Wilks approx F num Df den Df Pr(>F) (Intercept) 1 0.0002824 393.3 9 1 0.03911 * Residuals 9 --- Signif. codes: 0 `***' 0.001 `**' 0.01 `*'

Dear list members, I have problems to interpret the coefficients from a lm model involving the interaction of a numeric and factor variable compared to separate lm models for each level of the factor variable. ## data: y1 <- rnorm(20) + 6.8 y2 <- rnorm(20) + (1:20*1.7 + 1) y3 <- rnorm(20) + (1:20*6.7 + 3.7) y <- c(y1,y2,y3) x <- rep(1:20,3) f <- gl(3,20,

Hi all, is it possible to create a multidemensional list? Haven't found anything in the list() help page. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

Dear list, how can I compute the inverse of the X'WX matrix ("inverse of the weighted sum of squares and crossproducts matrix") from an object of class "lm" from a weigthed linear regression? Thanks, Sven