Displaying 20 results from an estimated 5000 matches similar to: "Missing value in Rpart"
2011 Mar 31
2
fit.mult.impute() in Hmisc
I tried multiple imputation with aregImpute() and
fit.mult.impute() in Hmisc 3.8-3 (June 2010) and R-2.12.1.
The warning message below suggests that summary(f) of
fit.mult.impute() would only use the last imputed data set.
Thus, the whole imputation process is ignored.
"Not using a Design fitting function; summary(fit)
will use standard errors, t, P from last imputation only.
Use
2004 Nov 30
2
impute missing values in correlated variables: transcan?
I would like to impute missing data in a set of correlated
variables (columns of a matrix). It looks like transcan() from
Hmisc is roughly what I want. It says, "transcan automatically
transforms continuous and categorical variables to have maximum
correlation with the best linear combination of the other
variables." And, "By default, transcan imputes NAs with "best
2007 Jan 04
3
randomForest and missing data
Does anyone know a reason why, in principle, a call to randomForest
cannot accept a data frame with missing predictor values? If each
individual tree is built using CART, then it seems like this
should be possible. (I understand that one may impute missing values
using rfImpute or some other method, but I would like to avoid doing
that.)
If this functionality were available, then when the trees
2008 Nov 04
1
How to generate a new factor variable by two other factor variables
How to generate a new factor variable by two other factor variables?
For example, if I have two factor variables, factorA and factorB,
factorA factorB
0 0
0 0
1 0
0 1
1 1
Is there a simple way to generate a new 4-levels factor variable as
factorC factorA factorB
0 0 0
0 0 0
1 1 0
2 0 1
2012 Sep 21
1
BRugs has a bug to use "OpenBUGS_PATH"
Hi,
When I used BRugs (Version 0.8.0), I found a bug about the
findOpenBUGS way using "OpenBUGS_PATH". I don't know how to contact
the developer, so I think someone here may help me.
The issue is: I want to use OpenBUGS/BRugs in a portable way in
windows, so I set the environment variable "OpenBUGS_PATH" to tell
BRugs the path to OpenBugs. But the R library BRugs is still
2007 Sep 26
1
using transcan for imputation, categorical variable
Dear all,
I am using transcan to impute missing values (single imputation). I have
several dichotomous variables in my dataset, but when I try to impute
the missings sometimes values are imputed that were originally not in
the dataset. So, a variable with 2 values (severe weight loss or
no/limited weight loss) for example coded 0 and 1, shows 3 different
values after imputation (0, 1 and 2).
I
2009 Jul 14
0
[LLVMdev] Writing pass for llc
On Sun, Jul 12, 2009 at 2:09 PM, shu<shuguang.feng at gmail.com> wrote:
> Is there a beginner's tutorial/documentation on how to write passes
> for the llc tool? I've managed to write some simple analysis passes
> for the opt tool but can't figure out how to do the same for llc.
> What is the proper way to integrate a new MachineFunction pass with
> llc? Is there
2011 Apr 23
2
Could I use R function lm or nlm in C code?
Dear R,
I'm doing some simulation work and it takes me a lot of time to do it
in R. So I try to implement it in C code, but I want to use some R
functions directly for my lazy and the robustness of code. For
example, I will use lm and nlm in my program. How could I use R's lm
and nlm function directly? I thinks these functions are not included
in the R's include directory. Do I need
2011 May 23
1
how could I use function in-visible to user in my code?
Dear R user,
How could I use function in-visible to user in my code? For example
'survfitKM' or 'survfit.formula' in package survival. These functions
are in-visible to user.
Thanks,
Shuguang
2007 Jan 04
2
importing timestamp data into R
I have a set of timestamp data that I have in a text file that I would like
to import into R for analysis.
The timestamps are formated as follows:
DT_1,DT_2
[2006/08/10 21:12:14 ],[2006/08/10 21:54:00 ]
[2006/08/10 20:42:00 ],[2006/08/10 22:48:00 ]
[2006/08/10 20:58:00 ],[2006/08/10 21:39:00 ]
[2006/08/04 12:15:24 ],[2006/08/04 12:20:00 ]
[2006/08/04 12:02:00 ],[2006/08/04 14:20:00 ]
I can get
2008 Jul 22
2
rpart$where and predict.rpart
Hello there. I have fitted a rpart model.
> rpartModel <- rpart(y~., data=data.frame(y=y,x=x),method="class", ....)
and can use rpart$where to find out the terminal nodes that each
observations belongs.
Now, I have a set of new data and used predict.rpart which seems to give
only the predicted value with no information similar to rpart$where.
May I know how
2009 Jun 09
3
rpart - the xval argument in rpart.control and in xpred.rpart
Dear R users,
I'm working with the rpart package and want to evaluate the performance of
user defined split functions.
I have some problems in understanding the meaning of the xval argument in
the two functions rpart.control and xpred.rpart. In the former it is defined
as the number of cross-validations while in the latter it is defined as the
number of cross-validation groups. If I am
2006 May 01
1
Traffic Shaping with Shorewall
Does anyone here implement traffic shaping with shorewall? I need to shape
BitTorrent traffic on my network so that upload/downloads do not overwhelm
normal function or, even more importantly, my imminent conversion to VOIP for
all telephone service. I followed the shorewall documentation guide but am
not sure if what I have done is the Right Way Of Doing Things. Nor am I
satsified with the
2018 Aug 14
2
Xenial rpart package on CRAN built with wrong R version?
Hello,
I just upgraded my Ubuntu Xenial system to R 3.5.1 (from 3.4.?) by changing the sources.list entry and doing an "apt-get dist-upgrade". Everything works except loading the rpart package in R:
> library(rpart)
Error: package or namespace load failed for ?rpart?:
package ?rpart? was installed by an R version with different internals; it needs to be reinstalled for use with
2004 May 13
2
R 1.9.0 and pred.rpart
I have just upgraded from R 1.7.3 to R 1.9.0 and have found that the
predict function no longer works for rpart:
> predict(hmmm,sim3[1:10,])
Error in predict.rpart(hmmm, sim3[1:10, ]) :
couldn't find function "pred.rpart"
I have re-installed the rpart package to no avail. Any ideas?
Giles Hooker
2011 Sep 07
2
rpart/tree issue
I am trying to create a classification tree using either tree or rpart
but when it comes to plotting the results the formatting I get is
different than what I see in all the tutorials. What I would like to
see is the XX/XX format but all I get is a weird decimal value. I was
also wondering how you know which is yes and which is no in each leaf of
the tree? Is yes always on the left?
2011 Aug 25
2
rpart: plot without scientific notation
While I'm very pleased with the results I get with rpart and
rpart.plot, I would like to change the scientific notation of the
dependent variable in the plots into integers. Right now all my 5 or
more digit numbers are displayed using scientific notation.
I managed to find this:
http://tolstoy.newcastle.edu.au/R/e8/help/09/12/8423.html
but I do not fully understand what to change, and to
2014 Aug 13
1
Request to review a patch for rpart
Dear list
For my work, it would be helpful if rpart worked seamlessly with an
empty model:
library(rpart); rpart(formula=y~0, data=data.frame(y=factor(1:10)))
Currently, an unrelated error (originating from na.rpart) is thrown.
At some point in the near future, I'd like to release a package to CRAN
which uses rpart and relies on that functionality. I have prepared a
patch (minor
2007 Feb 15
2
Does rpart package have some requirements on the original data set?
Hi,
I am currently studying Decision Trees by using rpart package in R. I
artificially created a data set which includes the dependant variable
(y) and a few independent variables (x1, x2...). The dependant variable
y only comprises 0 and 1. 90% of y are 1 and 10% of y are 0. When I
apply rpart to it, there is no splitting at all.
I am wondering whether this is because of the
2006 Aug 09
2
How to draw the decision boundaries for LDA and Rpart object
Hello useR,
Could you please tell me how to draw the decision boundaries in a scatterplot of the original data for a LDA or Rpart object.
For example:
> library(rpart)
>fit.rpart <- rpart(as.factor(group.id)~., data=data.frame(Data) )
How can I draw the cutting lines on the orignial Data?
Or is there any built in functions that can read the rpart object 'fit.rpart' to do