similar to: variable pattern

On Tuesday 06 February 2001 12:36, Dr. Jens Oehlschlägel wrote: > I like the idea. Why don't you call duplicated.matrix() directly in > unique.matrix() and duplicated.data.frame() in unique.data.frame() ? > > Jens Oehlschlägel Good point. I guess I got carried away with using methods (having just gotten the hang of the concept). :-) Anyway, here's a corrected version:

The compositional data xi=(x_i1,x_i2,...,x_in), for each fixed i , xij>0, and sum(xij)=1; I want to compare the mean( u_i) of several groups i.e. H0: u_1=u_2=...=u_N or H0: u_11=u_21=...=u_N1 Are there any ANOVA tpye tools to do this work in R? Thanks, WEN S Q [[alternative HTML version deleted]]

Dear List I would like to ask you something concenting a better print of the R output: I have a bit data frame which has the following structure: CFISCALE RAGSOCB ANNO VAR1 VAR2......... 9853312 astra 2005 6 45 9853312 astra 2006 78 45

I discovered recently that the phrase "Oja median" produces no hits in Jonathan Baron's very valuable R search engine. I found this surprising since I've long regarded this idea as one of the more interesting notions in the multivariate robustness literature. To begin to remedy this oversight I wrote a bivariate version and then decided that writing a general p-variate version

Hi, I'm trying to take a matrix such as [,1] [,2] [,3] [,4] [,5] [1,] 2 7 2 7 9 [2,] 10 10 6 8 6 [3,] 1 9 7 2 0 and generate a new matrix which contains only the unique values in each row: [,1] [,2] [,3] [,4] [,5] [1,] 2 7 9 NA NA [2,] 10 6 8 NA NA [3,] 1 9 7 2 0 My problem is that I can use

Hello everyone, Considering the following code sample : ---- indexes <- function(vec) { vec <- which(vec==TRUE) return(vec) } mat <- matrix(FALSE, nrow=10, ncol=10) mat[1,3] <- mat[3,1] <- TRUE ---- Issuing apply(mat, 1, indexes) returns a 10-cell list, as expected. Now if I do: ---- mat[1,3] <- mat[3,1] <- FALSE apply(mat, 1, indexes) ---- I would expect a

Hi Everybody, I have a matrix of about 45 columns. Some of the rows contain zeros. Using >data1<-data[complete.cases(data),], I can remove the "NA" rows. But I am unable to tackle that of zeros. Can anybody give me an idea of how to remove rows containing zeros in a matrix. Thanks so much Best Ogbos [[alternative HTML version deleted]]

For example, subtracting 1:2 from the rows of a two-column matrix: > t(apply(matrix(1:6,ncol=2),MARGIN=1,function(y) y - 1:2)) [,1] [,2] [1,] 0 2 [2,] 1 3 [3,] 2 4 > sweep(matrix(1:6,ncol=2),MARGIN=2,1:2,FUN="-") [,1] [,2] [1,] 0 2 [2,] 1 3 [3,] 2 4 Is there a logic to this difference, or is it just a quirk of the history of these

Dear all, Sorry for the simplicity of the question, but how does one go about removing duplicated rows in a data.frame? I'm looking for a quick and simple solution, as my data.frames are relatively large (50000 by 50). I've racked my brain and searched the help files and found nothing useful or quick, only duplicated() and unique() which work only work on lists. Thanks Gary.

I have independent event sequences for example as follows : Independent event sequence 1 : A , B , C , D Independent event sequence 2 : A, C , B Independent event sequence 3 :D, A, B, X,Y, Z Independent event sequence 4 :C,A,A,B Independent event sequence 5 :B,A,D I want to able to find that most common sequence patters as {A, B } = > 3 from lines 1,3,5. Pls note that A,C,B must

I need a function which is similar to duplicated(), but instead of returning TRUE/FALSE, returns indices of which element was duplicated. That is, > x <- c(9,7,9,3,7) > duplicated(x) [1] FALSE FALSE TRUE FALSE TRUE > duplicates(x) [1] NA NA 1 NA 2 (so that I know that element 3 is a duplicate of element 1, and element 5 is a duplicate of element 2, whereas the others were

I know this is a simple question, but I have yet to master the apply statements. Any help would be appreciated. I have a column of probabilities and sample sizes, I would like to create a column of binomial random variables using those corresponding probabilities. Eg. mat = as.matrix(cbind(p=runif(10,0,1), n=rep(1:5))) p n [1,] 0.5093493 1 [2,] 0.4947375 2 [3,]

Hello All, I would like to select records with identical IDs then sum an attribute then and return them to the data frame as a single record. Please consider Acres<-c(100,101,100,130,156,.5,293,300,.09) Bldgid<-c(1,2,3,4,5,5,6,7,7) DF=cbind(Acres,Bldgid) DF<-as.data.frame(DF) So that: Acres Bldgid 1 100.00 1 2 101.00 2 3 100.00 3 4 130.00 4 5 156.00 5

-- Richard Jones, Emerging Technologies, Red Hat http://et.redhat.com/~rjones New in Fedora 11: Fedora Windows cross-compiler. Compile Windows programs, test, and build Windows installers. Over 70 libraries supprt'd http://fedoraproject.org/wiki/MinGW http://www.annexia.org/fedora_mingw -------------- next part -------------- >From 8f1b06f64807239d4b4c923af4db8626a866ff6f Mon Sep 17

Hi All, I have a 75GB collection of data, including a lot of duplicated files, on a NTFS network drive. I want to backup that data across a DSL link to a Linux host. Currently I use cwrsync on a Windows machine to act as server to the Linux rsync client. I want to avoid transferring duplicated data, as the DSL link is a far more significant factor than computation/disk IO. I can't work

hey guys, I am working on a function to make a duplicated value unique. For example, the original vector would be like : a = c(2,1,1,3,3,3,4) I'll like to transform it into: a.nodup = 2, 1.01, 1.02, 3.01, 3.02, 3.03, 4 basically, find the duplicates and assign a unique value by adding a small amount and keep it in order. I come up with the following codes, but it runs slow if t is large. Is

Dear R helpers,   I am working on the scenario analysis pertaining to various interest rates. In this connection I need to form the various combinations as under :   Suppose I have two sets A = (a, b, c) and B = (x,y,z)   Then I can easily form the cominations as (ax, ay, az, bx, by, bz, cx, cy, cz)   However, if I have say 5 variables, then total no of possible combinations will be 3^5 = 243.

Very low priority. No user data at risk. 8GB virtual disk being installed to, and the installer is puking. I''m trying to figure out why. I first get an rsync error 12, followed by the installer crashing. What''s interesting is this, deleting irrelevant source file systems, just showing the mounts for the installed system: [root@localhost tmp]# df Filesystem

Dear list; I just created a utility function that replicates what I have done in the past with Excel or OO.org by putting a formula of the form =sum($A1:A$1) in an upper-corner of a section and then doing a "fill" procedure by dragging the lower-rt corner down and to the right. When divided by the grand sum of the entries this function then calculates a 2D-discrete-ECDF. I