similar to: summary() vs mean()

Hi, using R64.1 the summary function for simple statistics of a vector gives inaccurate results for the maximum. Example: summary(c(123456,1,2,3)) gives : Min. 1st Qu. Median Mean 3rd Qu. Max. 1.00 1.75 2.50 30870.00 30870.00 123500.00 The Max value ist wrong in a mathematical sense. I've tried with S-Plus, it gives the same result, but this seems

Howdy, Should summary() print answers with different numbers of significant figures, as in the following? > dim(iv) [1] 3000 2 > summary(iv) X1 X2 Min. :-4.15261 Min. :-3.271520 1st Qu.:-0.66188 1st Qu.:-0.671205 Median : 0.01233 Median :-0.008175 Mean : 0.01121 Mean : 0.016815 3rd Qu.: 0.67778 3rd Qu.:

Hi, Why when I do a summary on a table it cuts off the other variables? It says Other :58 or Other: 120. how can I get the summary for all the variables under ServLoad.Task and Server.Load and Avg. CPU and Max.CPU? Thanks, summary(probF) Reboot.Id ServLoad.Task Server.Load Avg.CPU Max.CPU Event.Log Min. : 2.00 120067_122395: 5

When I load a table from a data source and run summary() on it, the summary gives me basic summary statistics I'm looking for, and it also discriminates between quantitative and qualitative data and summarizes them accordingly. For example, if I do this: mydata <- read.table("data.txt") summary(mydata) I would get output like this: > summary(mydata) County

I experience random crash of machine (full hang, requiring a hard reset) after trying to test run Asterisk 11. The machine is a centos 5.8 32 bits pc with 1G ram. Asterisk is compiled from the source and no other software has been installed Anyone experience similar situation? -------------- next part -------------- An HTML attachment was scrubbed... URL:

Hi all, I''ve been looking at a potential problem, as documented here: http://projects.puppetlabs.com/issues/19241 To do with a leak within the KahaDB persistence layer of ActiveMQ. Specifically, there are reports of the db.data file growing unbounded: https://issues.apache.org/jira/browse/AMQ-3956 I''m hoping to find out information from other PuppetDB users to see if this is

> fil2s <- read.table("../Data/fil2_s.txt", header = FALSE, sep = "\t") Program received signal SIGSEGV, Segmentation fault. 0x000000000041c2e1 in RunGenCollect (size_needed=8192000) at memory.c:1514 1514 PROCESS_NODES(); (gdb) > sessionInfo() R version 2.13.1 Patched (2011-08-25 r56798) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]

Greetings, I downloaded R for my mac from software, R binaries, rm123, base and then downloaded "rm123.sit.hqx" Now, when I open R and try to type anything in the blank, I get a message that I need CarbonLib 1.20 or newer to run R. Please tell me what this means and where to go to get it. By the way, when I type anything in and recieve the error message, R will then refuse to close

Hello - R-experts, Is there any way with which we can specify the number after decimal point to take. Like I have a situation where the values are comming 0.160325923 but I only want 4 place to decimal say 0.1603. Is there any way for that. I am no expert in R- and this may sound simple to many.sorry Thanks for any help. With Regards Subhabrata

Hello, I'm using Hanhup Handlers in a testing asterisk 11 system. Within one such handler, I'm setting CDR values. To me, it seems those changed CDR values are not saved in CDR back-end. Can you confirm ? Regards -------------- next part -------------- An HTML attachment was scrubbed... URL:

Dear all, I was testing the wonderful package APE. However upon testing a particular Newick's format tree - which I think to be a non-binary tree - it yields different result as expected. > library(ape) > tree.hiv <- read.tree(text="(rat,mouse,(human,chimp));") > is.binary.tree(tree.hiv) [1] TRUE Was that a bug in APE package? - Gundala Viswanath Jakarta - Indonesia

Hi. > a [1] 13 13 14 14 15 15 16 20 21 26 > summary(a) Min. 1st Qu. Median Mean 3rd Qu. Max. 13.0 14.0 15.0 16.7 19.0 26.0 > mean(a) [1] 16.7 > quantile(a) 0% 25% 50% 75% 100% 13 14 15 19 26 Clearly, this is not right. My Instructor and I have no idea why the program does that. I removed the program from the computer , installed it

Thank you ahead of time for help with this. I have two matrices X [,1] [,2] [,3] [,4] [,5] [,6] [1,] 660 693.00 726.0 759.00 792.0 825.00 [2,] 548 575.40 602.8 630.20 657.6 685.00 [3,] 676 709.80 743.6 777.40 811.2 845.00 [4,] 763 801.15 839.3 877.45 915.6 953.75 [5,] 768 806.40 844.8 883.20 921.6 960.00 [6,] 692 726.60 761.2 795.80 830.4 865.00 [7,] 657 689.85 722.7

I find it's just great to be able to say: library(tseries) x <- get.hist.quote(instrument="ongc.ns") and it gets a full time-series of the stock price of the symbol ongc.ns from Yahoo quote. However, once my hopes have been raised by such beauty :-) I get disappointed when I do > plot(x) and the annotation is horrible! The x axis is not labelled as dates. The default

Dear R-users, I would like to know how could I read a file with different lines lengths. I need read this file and create an output to feed my database. So after reading I'll need create an output like this "INSERT INTO TEMP (DATA,STATION,VAR1,VAR2) VALUES (20100910,837460, 39,390)" I mean, each line should be read. But I don`t how to do this when these lines have different

2013/3/29 Julian Lyndon-Smith <asterisk at dotr.com> > check out the endbeforehexten option in cdr.conf > > this needs to set to "yes" > > Julian > Unfortunately, this doesn't help. Let's drop the hangup handler at the moment, and focus on the "saving to file" part. Then my issue is I can't update CDR value is hangup exten. Here is a

Hello List, i have been agonizing over this for days, any reply would be greatly appreciated! Situation:___________________________________ My original dataset is a .csv dataset (w/ 2M records) with 4 variables: job_id (Primary key, won't be used for analysis, just used for join tables), sector_id (categorical variable, for 19 industry sectors), sqft (con't variable for square

Dear all, I wanted to create the mean using a algebra matrix. so I tried this one: > meanAnimals <- new3%*%factorial (Calculates the matrix multiplication of the new3 * factorial). But I get the following error message: Error in new3 %*% factorial : non-conformable arguments These are my matrices: > new3 [,1] [,2] [1,] 1.350 8.1 [2,] 465.000 423.0

Dear R users, I have two n*1 integer vectors, y1 and y2, where n is very very large. I'd like to compute elbp = 4^(y1) * 5^(y2) * sum_{i=0}^{max(y1, y2)} [{ (y1-i)! * (i)! * (y2-i)! }^(-1)]; that is, I need to compute "elbp" for each (y1, y2) pair. So I made R code like below, but I don't think it's efficient Would you plz tell me how to avoid this "for"

Dear R-Helpers, I suspect I'm about to ask a FAQ, but I haven't been able to find an answer in the FAQ, AItR or an R Site Search. When I look at the methods of summary (below) it says, "Non-visible functions are asterisked". I looked at the help file for summary.princomp, which did not comment on it being non-visible. I ran its help file example, which printed visible output. I