similar to: Dynamic Memory Allocation Errors in 1.2.0?

I have noticed a definite loss of numerical precision going from 1.1.1 to 1.2.x under both Windows 98 and NT4 on x86 architecture. I noticed the difference when using the abcnon() function in the bootstrap package, but I think you could see the problem in any routine that involves subtracting relatively large numbers from each other. For the case I am looking at (see code below), the abcnon

Good news! I received some feedback from others that they did see the problem I described using abcnon() in 1.2.0 on Windows machines but not on Linux machines. I looked into it some more and discovered that it's most likely some problem with numerical precision or round off in the pre-compiled Windows 1.2.0 version. I was able to run the abcnon function in 1.2.0 successfully in Windows by

Dear all, can somebody please help me how to calculate "McFadden R-square" for a LOGIT model? Corresponding definition can be found here: http://publib.boulder.ibm.com/infocenter/spssstat/v20r0m0/index.jsp?topic=%2Fcom.ibm.spss.statistics.help%2Falg_plum_statistics_rsq_mcfadden.htm Here is my data: Data <- structure(c(1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1,

  Hi r-users,   I would like to use gev and my data (annual rainfall ) is as follows:   > head(dat,20) A B C D E F G H I J 1 45.1 41.5 58.5 50.1 46.0 49.1 37.7 49.1 59.8 54.0 2 50.3 39.8 49.4 56.4 49.4 48.8 42.1 49.8 49.4 58.3 3 41.7 39.3 44.6 39.1 35.7 41.5 40.8 40.8 38.5 45.6 4 50.7 33.9 48.4 28.2 35.5 39.1 61.4 17.0 30.7 38.3 5 39.3 30.6 46.9 23.8 25.8

Dears , I have the follow error when i want too use function abcnon of package bootstrap : Warning message: Package `bootstrap' contains no R code in: library(bootstrap) Can you help me ! Thx. AXA Corporate Solutions Nouveaux Produits Nour-Eddine HAKIM 52 Rue d'Amsterdame - 75009 Paris - France Tel (+33 1) 56 92 97 48 Fax (+33 1) 56 92 97 40 E-Mail : noureddine.hakim at

Dear R-User, Appreciate any helps. It looks simple, but I don't have a clue. Given that I have a dataframe of tree population with three variables: sp=species , d0=initial_size grow=growth increment from initial size per year How can I calculate the future growth increment of each tree for the next 3 years. The following Rscript was written, #---------- a0 <-

Dear all, I am fitting a LOGIT model on this Data........... Data <- structure(c(1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, 0, 1, 1, 0, 1, 0, 47, 58, 82, 100, 222, 164, 161, 70, 219, 81, 209, 182, 185, 104, 126, 192, 95, 245, 97, 177, 125, 56, 85, 199, 298, 145, 78, 144, 178, 146, 132, 98, 120, 148, 123, 282, 79, 34, 104,

Colleagues, I am fitting an Emax model using nls. The code is: START <- list(EMAX=INITEMAX, EFFECT=INITEFFECT, C50=INITC50) CONTROL <- list(maxiter=1000, warnOnly=T) #FORMULA <- as.formula(YVAR ~ EMAX - EFFECT * XVAR^GAMMA / (XVAR^GAMMA + C50^GAMMA)) ## alternate version of formula FORMULA <- as.formula(YVAR ~ EMAX - EFFECT / (1 + (C50/XVAR)^GAMMA)) FIT <-

The partial R-square (or coefficient of partial determination, or squared partial correlation coefficients) measures the marginal contribution of one explanatory variable when all others are already included in multiple linear regression model. The following link has very clear explanations on partial and semi-partial correlation: http://www.psy.jhu.edu/~ashelton/courses/stats315/week2.pdf In

I need to create 100 variable ,whose name is id.1,id.2~~~~id.100 then I need to let a vector say id<-c(id.1,id.2....id.100) any easy way to do this? thanks a lot~ [[alternative HTML version deleted]]

Hello, I have the following data.frame structure(list(Study = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L,

Dear Community, I have been using two types of survival programs to analyse a data set. The first one is an R function called aftreg. The second one an STATA function called streg. Both of them include the same analyisis with a weibull distribution. Yet, results are very different. Shouldn't the results be the same? Kind regards, J -- View this message in context:

I am having some problems adding packages under FreeBSD 2.2.8 and R-0.62.2 I have included the output of "uname -a" below first: == FreeBSD stiegl.niksun.com 2.2.8-RELEASE FreeBSD 2.2.8-RELEASE #0: Thu Dec 10 10:29:07 EST 1998 ath at stiegl.niksun.com:/scratch/obj/compile/STIEGL i386 == The CC in use is gcc (not egcs). The install failed as follows: == stiegl> R INSTALL

Hi! I want to choose part of the data. But it has a question. > attach(PIKO) > PIKO[1:5,] code species dbh x y tag status branch 92 10142 PIKO 38.9 6.05 12.81 10165 alive 0 109 10213 PIKO 41.0 6.71 26.21 10202 alive 0 135 10222 PIKO 48.3 18.98 21.28 10214 alive 0 146 10223 PIKO 47.0 19.45 22.83 10224 alive 0 147 10223 PIKO 20.0 19.74

Hello, I teach statistics and use R Commander for teaching. I have 2 students out of 169 that can't get scatterplots or plot to work. I have had them update packages, restart R/R Commander/their computers and even reinstall R/R Commander. One is using Windows 7 on a new pc and the other is a pc user (not sure the OS). They are both using R2.11.1 and R Commander 1.6-0. The data look like

Thanks for all the helpful responses. I include the data file and the syntax file for reference. Again, if I use the fields function, as is, I get the message: Error in svd(tempM) : error 159 in dsvdc using traceback, I get: > traceback() 4: stop(paste("error ", z$info, " in dsvdc")) 3: svd(tempM) 2: Krig(x, Y, cov.function = rad.cov, m = m, decomp = decomp,

Dear R Users, close to the end of this I used wireframe to create a 3D plot from a matrix. The x and y axis tick labels (1-6) for each were created from the matrix being a 6X6 matrix. I need the axis tick labels to be the row and column headings which you can see in the output (mat.x). I have tried several work arounds, but they have not been successful. Thanks in advance. keith rm(list=ls())

I want to make such plot using the following data set plot Mean with Sd(+/-) by Dim group by Lac here is data Does anyone know how to plot using xyploy Thanks, Aimin Mean Sd Var Min Max Dim Lac 704 44.00000 NA NA 44.0 44.0 -30 3 703 45.92000 9.5484030 91.1720000 60.0 34.4 -30 4 702 57.40000 NA NA 57.4 57.4 -30

> On 15 Sep 2017, at 12:38, yadav neog <yadavneog at gmail.com> wrote: > > hello to all. I am working on macroeconomic data series of India, which in > a yearly basis. I am unable to convert my data frame into time series. Do you really need to convert your data to time series/xts/zoo? I don?t know you try what kind of an analysis but perhaps you don?t have to. > kindly

I would like to be able to shade between two lines using ggplot2 (with faceting too). But, despite reading all the documentation on the website, cant figure out how to do it (either because i am a novice or idiot - or, of course, possibly both) My data looks is readership of paid & free newspapers in london by age since 1994. The structure is reading.melt <- structure(list(Date =