similar to: assigning to data frames with whole columns of NAs

Is this a bug? If not, I am curious to know why '[<-.data.frame' was designed to yield a.frame$y != a.frame$z rather than refusing to carry out the operation at all. > a.frame <- data.frame( x=letters[1:5] ) > a.frame[ 2:5, "y" ] <- letters[2:5] > a.frame[[ "z" ]][ 2:5 ] <- letters[2:5] > a.frame x y z 1 a b <NA> 2 b c

I saw the following in R help page "Extract.data.frame". The replacement methods can be used to add whole column(s) by specifying non-existent column(s), in which case the column(s) are added at the right-hand edge of the data frame and numerical indices must be contiguous to existing indices. On the other hand, rows can be added at any row after the current

Hi, The specification lists a number of commands that have responses: The operation of a virtio RPMB device is driven by the requests placed on the virtqueue. The type of request can be program key (VIRTIO_RPMB_REQ_PROGRAM_KEY), get write counter (VIRTIO_RPMB_REQ_GET_WRITE_COUNTER), write (VIRTIO_RPMB_REQ_DATA_WRITE), and read (VIRTIO_RPMB_REQ_DATA_READ). A program key or write

What is a smart way to change an entry inside a column of a dataframe or matrix which is of type "factor"? Here is my script incl. input data: > #set working directory: > setwd("K:/R") > > #read in data: > input<-read.table("Exampleinput.txt", sep="\t", header=TRUE) > > #check data: > input Ind M1 M2 M3 1 1

Hi David, I hope all is well w/ you. Co-operation beetwen R and Ox would be most welcome. A possible problem lies in the fact that, although free for academic use, Ox is not open source. I too have been using Ox for computer-intensive programming. I also code some of my programs in C, but I always try Ox first, and in most cases it is efficient enough. For details, see

I am making my first attempts at using some Fortran code with R, and so far it's going OK. To print from my Fortran programs, it seems I need subroutines dblepr, realpr and intpr. From the excellent "Writing R Extensions" document: "Three subroutines are provided to ease the output of information from FORTRAN code. subroutine dblepr(label, nchar, data, ndata)

Is there a straightforward way to convert character information from decimal representation to the octal one used by R? I'd like something like a function ascii(number,base=10), such that > ascii(91) [1] "\133" I can easily do the mapping from 91 to 133, but what is a good way to operate on 133 to deliver "\133"? Would a lookup table be a better solution? David

> ---------------------------------------------------------------------- > > Message: 1 > Date: Wed, 9 Jul 2003 10:53:27 +0100 > From: David Firth <david.firth at nuffield.oxford.ac.uk> > Subject: [R] packaged datasets in .csv format > To: r-help at stat.math.ethz.ch > Message-ID: > <307D34CE-B1F3-11D7-A8D2-0050E4C03977 at nuffield.oxford.ac.uk> >

I am calculating some values that I am inserting into a data frame. From what I have read, creating the dataframe ahead of time is more efficient, since rbind (so far the only solution I have found to appending to a data frame) is not very fast. What I am doing is the following: # create data frame goframe = data.frame(goA = character(10), goB = character(10), value = numeric(10)) goframe[1,] =

I am having a little problem in relation to sending output to the R Console window, when a function is called by pushing a button in a Tk window. Actually there seem to be two components to the problem: -- the R prompt does not re-appear until <return> is pressed -- text output to the R Console window *disappears* after <return> is pressed The following, in R 1.1.1 under

Is there some neat way of storing the printed representation of an object as a character string? I can see how it could be done via disk using sink() and then scan(), but that's ugly. Something like Lisp-Stat's "with-output-to-string" macro perhaps? David Firth Phone +44 1865 278544 Nuffield College Fax +44 1865 278621 Oxford OX1

I am aware of the nice R package "logspline", which does smooth density estimation from interval-censored data (that is, values that are known to lie in a specified interval rather than known exactly). Function logspline.fit uses a maximum penalized likelihood method, with the penalty related to the number of knots used in a cubic regression-spline fit. I need to be able to do some

Dear R Helpers, I am trying to write a character value to the row of a data frame and am running into a problem that I don't have when I do this for numeric arguments. For example, the following works just fine: > test<-data.frame(number=numeric(1)) > test[1,]<-.5 > test number 1 0.5 But the following bombs out: > hold<-data.frame(symbol=character(1)) >

Hi R user, Would you mind to help me on how I can change a value in a specific column and row in a big table? but the column of the table is a factor (not numeric). Here is an example. I want to change dat[4:5,3]<-"20" but it generated NA> do you have any suggestions for me? dat<-structure(list(Sites = structure(1:5, .Label = c("Site1", "Site2",

Could someone tell me how to fix the following error? It looks like that the reason is that df$x is of the class "factor". Thanks! > x1<-LETTERS[1:8]; x2<-letters[1:8]; x1[2]<-NA; x1[4]<-NA; > df<-data.frame(x1=x1, x2=x2) > idx<-which(is.na(df$x1)) > df[idx,1]<-df[idx,2] Warning message: invalid factor level, NAs generated in:

Hi everyone, I would like to find out when and where exactly I get the following warning in a piece of code I've written: Error in "[<-"(`*tmp*`, iseq, value = numeric(0)) : nothing to replace with The code is a for () loop performing a somewhat trivial calculation, modulated by a number of logical if(){} else(){} conditions, involving the creation of a number of

Hi Friends, I'm new to R ,I have a data frame Z16 which is genarated from another data frame, and I want to add ?%? & ?$? in row 4 and 5 respectively. when I?m trying using below logic, I?m getting warning message. I'm using R 2.14.2 Version Can anyone help me out on this. Note: Initially i used tranfrom function to do some calculations,where ever it should give zero,its

Hi Friends, I have a data frame X, and I want to add ?%? & ?$? in row 4 and 5 respectively. when I?m trying using below logic, I?m getting warning message. Can anyone help me out on this. X: Summary G Y R T Accts 582 644 0 1226 AcctCov 230 165 0 395 Cov% 40 26 0 32 UnCov% 60 74 0 68 EqVol11$MM8.5 10.6 0 19.1 Using this logic:

Hi R-users, I had a minor issue while demonstating R that I can't explain. I am hoping someone will have suggestions. The only difference is a call to fix() in between that I made to ensure people were following me. However, that seems to have altered the way R code got executed. I was wondeirng if people have any insights. Arnab # When it does work x <-letters[1:10] marks

I don't think I understand you entirely, but here are a couple things. You need to shorten the loop so you don't run off the end. You basically just write the code as you've stated it except that "and" is && for single values and & for vectors You don't say what should happen if the test is not true. You can probably use "ifelse" instead of a