similar to: quasi-symmetry loglinear models

At 14:49 22/12/00 +1100, M.McStephen at papyrus.mhri.edu.au wrote: >Hi All, > >I'm trying to use the names from a data frame to display data in the >frame: > >> data.n<-names(data) # put names into a vector called data.n >data.n[1] >[1] "ID" > >> >> paste("data$",data.n[1],sep="") # create the name of the column in

Full_Name: Michael McStephen Version: 1.5.1 OS: Win2000 Submission from: (NULL) (203.25.148.63) When using read.table to read a data file section by section, I get an error that indicates R is attempting to read more "fields" than exist. The Data file looks like this: ---Start of file tmp.txt----------- Response Types = TPos TNeg FPos FNeg Anti Post MaxO Test ID,Username,Start

Is there a way to automate fitting and assessing loglinear models for several nominal variables . . . something akin to step or drop1 or add1 for linear or logistic regression? Thanks. --Chris -- Christopher W. Ryan, MD SUNY Upstate Medical University Clinical Campus at Binghamton 40 Arch Street, Johnson City, NY 13790 cryanatbinghamtondotedu "If you want to build a ship, don't drum

Dear netters, Sorry for cross-posting this question. I am sure R-Help is not a research methods discussion list, but we have many statisticians in the list and I would like to hear from them. Any function/package in R would be able to deal with the problem from this researcher? ---------- Forwarded message ---------- From: Heidi Bertels Date: Tue, Jun 5, 2012 at 4:31 PM Subject: How to best

Dear R Users, A would like to fit a loglinear analysis to a three dimensional contingency table. But I Don't want to run a full saturated modell. Is there any package in R that could handle somekind of stepwise search to choose out the best soultion? And how can I fit a non fully saturated modell, which only use the important interactions? Best Regards Zoltan Kmetty [[alternative HTML

The null loglinear model is an intercept-only model for log frequency, log(f) = \mu For a one-way table the test of the null model is the same as the chisq.test. This can be fit using loglin(), but I don't think there is any way to specify this using MASS::loglm > t1<- margin.table(Titanic,1) > t1 Class 1st 2nd 3rd Crew 325 285 706 885 > loglin(t1, NULL) 0

Hi R-masters! I have a problem and need your help. I have 9 discrete variables with 2 levels each. In exploratory analisys I generate one matrix with chi-square for tables with 2 ariables each with this script setwd("F:/") dados<-read.csv("log.csv")[,2:10] dados.x<-matrix(NA,ncol=9,nrow=9) for(i in 1:8){ for(j in (i+1):9){ tab<-table(dados[,i],dados[,j])

I am using the loglin function of the base package to fit log-linear models. I am interested in obtaining the parameter values and their standard errors. Parameters are easily obtained, but I haven't found the way of obtaining their standad errors. Is this possible with the loglin function? If not, is there any other function to get them? Many thanks, -- Vicente Piorno Departamento de Ecolox?a

I have a dataset with 25 subjects and 25 items. For each subject-item combination, there's a 0/1 score for two parts, A and B. I'm thinking of this as a set of 2 x 2 tables, 25 x 25 of them. I'd like to fit a log-linear model to this data to test the independence of the A and B scores. If I ignore the subject and item parts, the following works just fine: glm(count ~ A * B,

Hi all: Here's a question about result of loglinear analysis. There're 2 factors:area and nation.The raw data is in the attachment. I fit the saturated model of loglinear with the command: glm_sat<-glm(fre~area*nation, family=poisson, data=data_Analysis) After that,I extract the coefficients: result_sat<-summary(glm_sat) result_coe<-result_sat$coefficients I find that all the

Hi all, I've been running loglinear models for three-way tables: one of the variables having three levels, and the other two having two levels each. An example looks like below: > yes.no <- c("Yes","No") > switch <- c("On","Off") > att <- c("BB","AA","CC") > L <- gl(2,1,12,yes.no) > T <-

Hi all, I am trying to print some generated text on plot which is comprised of text and the value of a variable. Thanks to the response from Joshua Wiley <jwiley.psych@gmail.com> on the thread "How to format R superscript 2 followed by "=" value, I can now get R^2 = value. However with the following code: ggplot(blData, aes(x = xData, y = yData)) + geom_point(aes(colour

Hi all, Not sure if this is the best list, please point me to a more appropriate list if necessary. Running Mac OSX 10.7.1 R version 2.13.1 Patched (2011-08-14 r56741) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: x86_64-apple-darwin9.8.0/x86_64 (64-bit) I have a locally developed library (libmlalgs), which I am able to install via the command line:

Full_Name: Michael McStephen Version: 1.5.1 OS: w2000 Submission from: (NULL) (202.138.192.38) > R.version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 5.1 year 2002 month 06 day 17 language R

Hello all, I'm running samba3 as domain controller. I have upgraded samba from 3.0.22 to 3.0.23b and faced an issue with groups display: samba does not see any groups. "net rpc group -U Administrator" returns empty set. usrmgr.exe does not show any groups also. Groups are present in ldap, nss_ldap works fine: # id asv uid=2005(asv) gid=513(Domain Users) groups=513(Domain Users),

Hello, i use sieve extension sieve_extprograms to send incoming mail to some script. For security reasons it is needed that script-paths etc. are registered in dovecot.conf This is my current dovecot.conf plugin { sieve = ~/.dovecot.sieve sieve_plugins = sieve_extprograms sieve_extensions = +vnd.dovecot.pipe +vnd.dovecot.filter +vnd.dovecot.execute sieve_pipe_bin_dir =

Hi all, I have recently changed from Suse 10.0 to openSuse 10.2 on my desktop PC, and I am having problems running the latest version of Papyrus (12.56) a Windows word-processor. I can run an older version of Papyrus without any trouble. On the same machine I can also boot into my Suse 10.0 setup and Papyrus 12.56 runs fine in that. Both 10.0 and 10.2 are using the lastest wine version -

Does anyone know if any R package has a function that will conduct Hollander's test of bivariate symmetry? (Hollander, Biometrika, 1971) Either the exact test or an asymptotic version would be sufficient for my purposes. Thanks. Joe Boyer Statistical Sciences Renaissance Bldg 510, 3233-D Mail Stop RN0320 8-275-3661 cell: (610) 209-8531 [[alternative HTML version deleted]]

Open Letter to Developers, Is there any way you can cut through the mob scene at Homeland Defense with a powerful new encryption/decryption formula? The government cryptography bunch are stuck in symmetry and asymmetry and are deaf/dumb/blind to supersymmetry. When it's so easy to line up a supersymmetrical hypercube fractal-to-fractal, pair-to-pair, quantum-to-quantum and slice through

Hello (I hope this is the correct group for this post - if not I am sure you will tell me where to go :-)) ) I use wine 0.9.23-12.1 in Suse 10.1 on my laptop to run Papyrus (a word processor originally written for the Atari platform and now available for Windows). I have been very pleased with recent versions of wine as it seems now to be working almost perfectly for Papyrus :-) However, I