similar to: R function for "interp"

Hi I'm working on a remote computer with R (SuSE 8.1) and I want to do some ploting. Does anyone knows if it is possible to export the graphics window in to my display and how I can do it ? Thanks EJ -- Ernesto Jardim <ernesto at ipimar.pt> Marine Biologist Research Institute for Agriculture and Fisheries Lisboa, Portugal Tel: +351 213 027 000 Fax: +351 213 015 948

Hi I'm computing a bca interval using bca.ci from the boot package. When I try to use this I get an error > library(boot) > boot(logglm.data,boot.fishpower,2500,coef.vec=coeflm.vec)->blm8901 > bca.ci(blm8901,index=29) Error: cannot allocate vector of size 456729 Kb However my machine has 2GB of memory and without R running I only have 112M of memory used. Is there something

Hi Does someone knows if there's a function/package that can make thin plate splines ? I've looked in mgcv and splines but I haven't found anything. Thanks EJ -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe"

Hi I'm exporting some graphs from R to M$Word. I used png, jpeg and bmp and the quality is poor when comparing with the postscript. What is the best way to export a chart to be included in a M$Word file ? Thanks EJ

Hi I have a matrix (4 x 950) and I want to remove 3 rows, where the values from the first column are 713, 714 and 715. I can select the rows, one by one, with mat[mat$first==713,] mat[mat$first==714,] ... but I'm unable to (i) select the 3 rows at once, (ii) select the matrix excluding those rows. How can I do it ? Thanks EJ

Hi everyone I'm trying to use sigma2.mat<-apply(ri.mat,2,'-n/2*log(sum(ri.mat^2)/n)') but it's not working. Is it wrong to use that kind of FUN in apply ? or am I doing something wrong ?! Thank's ernesto -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Dear all, I'm trying to interpolate a dataset to give it twice as many values (I'm giving the dataset a finer resolution by interpolating from 1 degree to 0.5 degrees) to match that of a corresponding dataset. I have the data in both a data frame format (longitude column header values along the top with latitude row header values down the side) or column format (in the format latitude,

Hi I have a list with several data.frames, all with the same number of colunms but different number of rows, and I'd like to transform this list into a single dataframe. I need to mimic an rbind of all dataframes ... Transform doesn't seem to work :-( Thanks EJ -- Ernesto Jardim <ernesto at ipimar.pt> Bi?logo Marinho/Marine Biologist IPIMAR - Instituto Nacional de Investiga??o

Full_Name: Ernesto Jardim Version: 1.2.2 OS: SuSE Linux 6.4 Submission from: (NULL) (193.137.98.92) I wanted to import an array, dim=c(28,12,17), from splus into R.On splus I did dump(c("array"),file="dump.out) I checked and Splus could source it. Than, in R I tryied to source it with: source("dump.out") and got and error message: > source("dump.out")

Dear all I have this table > dput(mat) mat <- structure(c(2, 16, 9, 2, 16, 1, 1, 4, 7, 7, 44.52, 42.8, 43.54, 40.26, 40.09), dim = c(5L, 3L)) And I want to calculate result for contour or image plots as I did few years ago. However interp does not compute the z values and gives me zeros in z matrix. library(akima) > interp(mat[,1], mat[,2], mat[, 3], nx=5, ny=5) $x [1] 2.0 5.5

The akima package has a problematic license (it doesn't allow commercial use), so it's been recommended that people use the interp package instead. When I use interp::interp instead of akima::interp, I get reasonable output from your example. So that's another reason to drop akima... Duncan Murdoch On 26/01/2023 9:35 a.m., PIKAL Petr wrote: > Dear all > > I have this

Hi I'm using the gss package to fit thin plate splines. I've fitted the tps without problems and got a ssanova object. Then I wanted to do some prediction using a new set of data (latlon data) and I got an error message: > predict.ssanova(recs.spliney,recn.grid,se.fit=FALSE) Error in array(x, c(length(x), 1), if (!is.null(names(x))) list(names(x), : attempt to set an

Hi I'm doing a bootstrap of a linear model using: boot.fishpower <- function(data, i){ data <- data[i,] fplm <- lm(log(U)~Q+S+P+B+D, data=data) fp <- coef(fplm) exp(fp) } > boot(logglm.data,boot.fishpower,100) Error in "[<-"(*tmp*, r, , value = statistic(data, i[r, ], ...)) : number of items to replace is not a multiple of replacement length

Hi, I want to use the first digit of the elements of a vector. I've tried grep but didn't work. Any help is welcome. Thanks EJ > grep("^[0-9]",as.character(runif(100,0,2))) [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 [19] 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 [37] 37 38 39 40 41 42 43 44 45

Hi! I 've a problem to have a lognorm distribution with mean=1 and var (or sigma)=1. rlnorm(1000,0,0) rlnorm(1000,1,1) rlnorm(1000,0,1) .... ? Can you help me?

Hi Maybe this is not an issue about R. It's probably a programming issue and I am not a developer at all. Anyway my main developing activities are in R and that's where I have difficulties. When I develop a function or group of functions I lose eternities with the objects attributes and classes. I do a lot of object manipulation (lists to arrays, factors to numeric vectors, etc, etc) so

Dear R users, I want to do a fitted.contour plot of selected columns of a dataframe M with M$AM and M$Irradiance as x and y axes respectively. The level of the contour shall be determined by M$PR. Some words on my data first. Dataframe M looks like: head(M$Irradiance) [1] 293 350 412 419 477 509 head(M$AM) [1] 2.407 2.161 1.964 1.805 1.673 1.563 head(M$PR) [1] 70.102 72.600 75.097 80.167

Hi I would like to know if the "penalty associated with the fit" that is printed by the summary.ssanova function is the smoothing parameter (\lambda) of the criterion function that's minimized to find f. Thanks EJ -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send

Hi I've imported some data from a oracle database and the strings have a lot of blank space (because of the delimiter). I want to remove these blanks space with something similar to a trim function. I don't find a trim function or something similar. Can someone give a help on this ? Thanks EJ -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help

Hi I've just submitted to the NEdit development team a R highligth patterns for NEdit (www.nedit.org). NEdit is a text editor for LINUX which I use to write small R functions. In my opinion is a very good tool for small scripts, maybe for huge projects is not the best. I'm attaching the R-5.1.pats file so you can try it. As usual contributions and comments are welcome. Regards EJ