similar to: arima.sim

Displaying 20 results from an estimated 7000 matches similar to: "arima.sim"

2000 Dec 30
3
ARIMA
Thanks, Can't find an ARIMA in base, dse1/2 or tseries, only references to. What package is it in? Thanks again! Best regards, /fb -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the
2010 Aug 19
1
How to include trend (drift term) in arima.sim
I have been trying to simulate from a time series with trend but I don't see how to include the trend in the arima.sim() call. The following code illustrates the problem: # Begin demonstration program x <- c(0.168766559, 0.186874000, 0.156710548, 0.151809531, 0.144638812, 0.142106888, 0.140961714, 0.134054659, 0.138722419, 0.134037018, 0.122829846, 0.120188714,
2005 Oct 02
2
arima.sim bug?
Hi, I am using the arima.sim function to generate some AR time series. However, the function does not seem to produce exactly the same time series when I specify the innov parameter. For example > r <- rnorm(300) > x <- arima.sim(300, model=list(order=c(1,0,0),ar=c(.96)), innov=r, n.start=10) > y <- arima.sim(300, model=list(order=c(1,0,0),ar=c(.96)), innov=r, n.start=10) >
2008 Jul 12
1
Help with arima.sim
Hey, as a bloddy beginner in R I want to simulate a Arima (2,1,0) process with R. My problem is, that I don't know how to specify the AR. For a ARIMA(1,1,0) I use the following syntax: S <- arima.sim(list(order=c(1,1,0), ar=0.9), n=100). I think it is a stupid question with an easy answer. But when I google the only results are arima.sim for an ARIMA (1,1,0). Regards, Chris --
2004 May 24
1
Null model for arima.sim().
In some time series simulations I'm doing, I occasionally want the model to be ``white noise'', i.e. no model at all. I thought it would be nice if I could fit this into the arima.sim() context, without making an exceptional case. I.e. one ***could*** do something to the effect if(length(model)==0) x <- rnorm(n) else x <- arima.sim(model,n) but it would be more suave if one
2005 Oct 10
1
using innov in arima.sim
Hello, I have used the arima.sim function to generate a lot of time series, but to day I got som results that I didn't quite understand. Generating two time series z0 and z1 as eps <- rnorm(n, sd=0.03) z0 <- arima.sim(list(ar=c(0.9)), n=n, innov=eps) and z1 <- arima.sim(list(ar=c(0.9)), n=n, sd=0.03), I would expect z0 and z1 to be qualitatively similar. However, with n=10 the
2011 Nov 22
1
arima.sim: innov querry
Apologies for thickness - I'm sure that this operates as documented and with good reason. However... My understanding of arima.sim() is obviously imperfect. In the example below I assume that x1 and x2 are similar white noise processes with a mean of 5 and a standard deviation of 1. I thought x3 should be an AR1 process but still have a mean of 5 and a sd of 1. Why does x3 have a mean of ~7?
2003 Jul 16
1
arima.sim problems (PR#3495)
Full_Name: Gang Liang Version: 1.7.1 OS: Debian/Woody Submission from: (NULL) (192.6.19.190) > print(arima.sim(list(ar=.3,order=c(1,1,1)), 30)) [1] 0.00000000 0.10734243 0.02907301 -1.23441659 -0.98819317 -2.82731975 [7] -2.69052512 -4.22884756 -5.02820635 -5.41514613 -6.20486350 -7.01040649 [13] -6.78121289 -5.41111810 -4.96338053 -5.42395408 -6.22741444 -5.75228153 [19] -6.07346580
2001 Mar 07
1
lreadline
I compiled R-1.2.2 on my SuSE 7.1, kernel 2.4.2-2 machine with libreadline.4.1 and although I can use vi commands to scroll on the shell (bash) command line, I CANNOT do it in R. Here's the relevant parts of ./configure (and make): anovo at friedman R-1.2.2 > ./configure | grep readline checking for rl_callback_read_char in -lreadline... yes checking for readline/history.h... yes
2012 Oct 08
1
arima.sim
Hi, I have been using arima.sim from the stats package recently, and I'm wondering why I get different results when using what seem to be the same parameters. For example, I've given examples of three different ways to run arima.sim with what I believe are the same parameters. It's my understanding from the R documentation that rnorm is the default function for rand.gen if not
1998 Nov 28
2
dyn.load and/or add new package (Windows 98)
Hi, I have been trying to dyn.load a library (rq.obj), which will allow me to run a quantile regression function, but so far unsuccessfully. I have tried under windows 98 and R 6.24: 1) dyn.load("d:\\...\\rq.obj") 2) dyn.load("d:\...\rq.obj") 3) 1 and 2 accounting for case sensitivity. 4) dyn.load("d:/.../rq.obj") 5) Place the files in the directory where from I
2004 Jan 14
1
seasonal fractional ARIMA models
Hello, does anyone know about: a) simulating seasonal ARIMA models? arima out of package ts can fit it, but it does not look like it can simulates data from seasonal models b) fitting and simulating fractional seasonal ARIMA models? Hints will be appreciated, Henning -- Henning Rust Potsdam Institute for Climate Impact Research Dept. Integrated Systems Analysis Tel.: #49/331/288-2596
2000 Mar 29
2
regularly lattice & neighbors
Dear R-users, Is there a procedure to identify neighbors in a regular lattice using either a "rook" or a "queen" criterium? To be more specific, suppose: My lattice: 1 2 3 4 5 6 7 8 9 "Rook" Neighbors 1 has neighbors 2,4 2 has neighbors 1,3,5 ... 5 has neighbors 2,4,6,8 "Queen Neighbors" 1 has neighbors 2,4,5 2 has neighbors 1,3,4,5,6 For each case,
1998 Nov 26
1
heap memory exhausted
Hi I always have following error message when I try to read a big ascii-file: > inzp<-read.data() > Error: heap memory (1953 Kb) exhausted [needed 0 Kb more] read.data() is a small function that reads the ascii-file. When I cut the ascii-file to a small one I don't have this problem. Can I extend this 'heap memory' for reading big data files? How? I'm working with R on a
2004 Mar 04
2
adding trend to an arima model
Hi, Does anyone know a method for adding a linear/polynominal trend to a simulated arima model using the arima.sim function? Any help will be greatly appreciated. Cheers, Sam.
1999 Sep 24
1
analysis of multivariate normal (missing values)
Hi, I could not find an R package for the analysis of multivariate normal datasets with missing values. Prof. Joseph Schafer has created an S+ library (norm) that does such type of analysis, which I now ported to R. I guess that I should have asked here if there are other people working on such project, before I actually ported it, but... If such package has not been ported, I will upload the
1999 Oct 19
2
Summary bug?
Hi, It seems that there's a bug in summary, in the max. output... but max() alone works fine. > hw04.dframe$area ... [41] 1790 1380 1296 2745 798 2306 438649 1481 1559 2450 ... > summary(hw04.dframe) area Min. : 798 1st Qu.: 1349 Median : 1690 Mean : 6962 3rd Qu.: 2306 Max. :438600 ### should read 438649 or, to the point,
1999 Nov 23
3
problems with postscript device
Hi! The postscript device in 0.90 does not produce symbols (pch=) as it should. E.g.: postscript(file="test.ps",width=8,height=6.4,horizontal=FALSE) plot(1:10,1:10,pch=1:5) legend(1,9,letters[1:5],pch=1:5) dev.off() The result looks quite different compared to the X-windows version. The symbol 1 (pch=1) is much to small, while the other symbols seem to big. Is it a bug? How can I
1999 Jan 30
3
installing R under RH Linux 5.2
I am trying to install R under Red Hat Linux 5.2, but the following error happens: [root at edgeworth cribari]# rpm -ivh R-base-0.63.2-1.i386.rpm failed dependencies: libncurses.so.3.0 is needed by R-base-0.63.2-1 I must be missing something very simple. I would appreciate any guidance. Thanks. FC. -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help
2009 Sep 29
0
Incoherence between arima.sim and auto.arima
Hello, I have a question about function arima.sim I tried to somulate a AR(1) process, with no innovation, no error term. I used this code: library(forecast) e=rnorm(100,mean=0,sd=0) series=arima.sim(model=list(ar=0.75),n=100,innov=e)+20 Then I tried to applicate ti this series auto.arima function: mod1<-auto.arima(series,stepwise=FALSE,trace=TRUE,ic='aicc') The best model returned