similar to: warnings associated with logistic regression

I've been trying to learn about dynamically loading subroutines in R. Ultimately I would like to use this approach to implement some simulations. For the moment though, I've run into a problem compiling c++ code and loading it into R. The 'C/C++' and 'R'code below works fine when compiled and linked with gcc, but gives an error when the library is compiled and linked with

Dear listers, I am trying to assess variance components for a nested, mixed-effects model. I think I got an answer that make sense from R, but I have a warning message and I wanted to check that what I am looking at is actually what I need: my data are organized as transects within stations, stations within habitats, habitats within lagoons. lagoons: random, habitats: fixed the question is:

Hi all I have been trying to use the randomForest package to model insect species abundance in different habitats and identify the key variables (landscape/climate etc) in determining abundance, which has all worked fine and I get nice variable importance plots etc. Many thanks to everyone on this help forum who has given tips/advice along the way. But the percentage variance explained /pseudo r

Estimados Escribo para consultar sobre el uso de modelos mixtos anidados. Los datos que estoy analizando provienen de censos de malezas en cuatro tipos de paisajes de la región pampeana, en los que seleccioné al azar igual número de lotes agrícolas cultivados con tres cultivos (maíz, soja y trigo-soja). En cada lote censé el número de especies de malezas en tres posiciones: el alambrado, el borde

Dear all, I have posted a query which has received a response but that is not working on my computer. Here is the query: https://stackoverflow.com/questions/77387434/pdf-from-rmarkdown-landscape-and-aspectratio-169 Can someone please help me ? Best Regards, Ashim

Does anybody know how to get a pdf file with landscape orientation?. pdf(file= 'my_file.pdf' ,onefile=T,paper='A4') plot(sin, -pi, 2*pi) dev.off() Thank's in advance Juan A. Hernandez Spain [[alternative HTML version deleted]]

Dear R-users I am trying to understand how Sweave works by running some simple examples. In the example I am working with there is a chunk where the R-commands related to plotting a figure are placed. When running R CMD Sweave ? , pdflatex the output is a portrait figure. I wonder whether it would be possible to change the orientation to landscape (not in the latex file but in Rnw file). Many

Is there a way to increase the "sensitivity" of the color palette in order to more clearly represent certain sections of data? For example I am wanting to clearly differentiate between height data for a rolling landscape but because of the extremes of the dataset (sea and mountain tops), the bulk of the landscape is shaded in closely approximating green - i have attempted to do this by

Hi, I made a few graphs by ggplot. The following codes produce a pdf file with graphs in landscape orientation on my Windows PC, while they produce a pdf file with the same graphs, but in portrait orientation: *p2 <- lapply(1:(2*n), function(.x) xyz_outl[.x][[1]]) #a sequence of graphs made by ggplot* *m2 <- marrangeGrob(p2, nrow=3, ncol=2) * *ggsave("xyz.pdf", m2)*

Hello together! How can I plot a landscape letter-format plot? With postscript, I just use the horizontal option and I get what I want, but it seems that the pdf lacks this option. Well, I could do a ps2pdf conversion of the generated ps-file. But is there a way to directly produce landscape pdf-plots with R? Thanks for any help. Greetings, Sebastian

Is there a set of R expressions that has the same effect as the following set of S-Plus 2000 expressions: graphsheet(format="printer", orientation="landscape") par(mfrow=c(2,2)) plot(x1, y1) plot(x2, y2) plot(x3, y3) plot(x4, y4) dev.off() # one page of landscape plots sent to printer I am having trouble with formulating the equivalent of the first line of the above in R.

Hi All, I'm trying to specify the formula for a glm based upon the names in the data.frame. I always discard the first two variables in the frame and the third will always be the only response variable. The problem appears because I would like to specify the rest of the variables of the data.frame as independent variables in the formula. I can't think of a way to do this cleanly and

From: Thorvald Natvig <slicer at users.sourceforge.net> Some optimizing compilers miscompile the current SSE optimizations when full optimizations are enabled. By using output value pointer instead of a return value, we can bypass this misbehaviour. --- libspeex/resample.c | 8 ++++---- libspeex/resample_sse.h | 24 ++++++++---------------- 2 files changed, 12 insertions(+), 20

This is a windows-specific question. After generating a plot, I can print from scripts or the command line with > dev.print(win.print,printer="local windows printer name") I would like to print in landscape mode. From the menus, I can accomplish this by changing the properties of the printer before clicking "print". However, I tried adding

Hello listers, I would like to know how I can get the resulting graphic of the function plot.hclust (from the package cluster) in landscape orientation. Is it possible? Thanks, Juan

Hi: I am haviong problems with Landscape mode on our HP printers (many models). I am running 2.2.7a on two different servers. One is using the "old style" printing (using "printer driver file" parameter). The other is using the newer printing system. It is the same code on both. Both are Solaris systems. For the old one, the drivers are installed on the client, for the

Hello list members, I am working with simulated data for landscape pattern analysis. I have 1000 replicates of binary (2 colour) gridded landscapes at each combination of 9 levels of class proportion and 11 levels of spatial autocorrelation. The results are stored in an array as follows: > dim(surfaces) [1] 38 9 11 1000 The dimensions are defined as follows: [x,,,] 1:38, integers

Hello, I am developing an agent-based model to simulate the spread of infectious diseases in heterogeneous landscapes composed of habitat polygons (or clumps of connected cells). To simplify the model, I consider a habitat grid (or raster) containing the polygon ID of each cell. In addition, I have epidemiological parameters associated with each polygon ID. At each time step, the parameter values

Hello, I am trying to do some simulation using the rmetasim package and I've run to this problem. --beginning of error msg-- Error in "[<-"(`*tmp*`, slice[l, ], slice[l, ], value = c(0.200000002980232, : number of items to replace is not a multiple of replacement length --end of error msg-- Here is the script I used. --script starts here-- ## load 'rmetasim'

Dear R users, I would like to accumulate objects generated from 'for' loop to a list or array. To illustrate the problem, arbitrary data set and script is shown below, x <- data.frame(a = c(rep("n",3),rep("y",2),rep("n",3),rep("y",2)), b = c(rep("y",2),rep("n",4),rep("y",3),"n"), c =