similar to: renaming columns

Displaying 20 results from an estimated 2000 matches similar to: "renaming columns"

2010 Oct 13
4
Change global env variables from within a function
Hi, I've looked all over for a solution to this, but haven't had much look in specifying what I want to do with appropriate search terms. Thus I'm turning to R-help. In the process of trying to write a simple function to rename individual column names in a data frame, I ran into the following problem: When I rename the columns within my function, I can't seem to get it to
2000 Jun 25
0
R 1.1.0 Freeze Ups
I've experienced numerous "freeze ups" with R 1.1.0 in the past few days. I'm running on a Windows 98 (*not SE*) notebook with 128 MB RAM. Typically I have no other applications running when I load "R". The circumstances that frequently leads to the "freeze ups" is when I have done the following: >fix(somefunction) This spawns "Notepad",
2000 Aug 24
0
distributional properties of rnorm
I've been trying to generate a series of random normal distributions using the rnorm function. After I generated the first set: set1<-rnorm(150, 505.5, 15.2) I checked the mean and standard deviation of set1. I was surprised to find the mean at 502.37 (rounded) and the standard deviation at 13.3 (again, rounded). While I know that it is unrealistic to expect the distribution of the
2000 Aug 24
0
rnorm
Thanks to all who replied to my query about the "normality" of rnorm. I am using R 1.1.1 (the version released last week) under Windows 98. It has been unusually hot here and I noticed that the CPU fan seemed to be running at high speed for a long time. The CPU probe that I use to monitor the temperature emitted a warning shortly after I sent off the email. After shutting my
2008 Nov 25
1
Efficient passing through big data.frame and modifying select
> -----Original Message----- > From: William Dunlap > Sent: Tuesday, November 25, 2008 9:16 AM > To: 'johannes_graumann at web.de' > Subject: Re: [R] Efficient passing through big data.frame and > modifying select fields > > > Johannes Graumann johannes_graumann at web.de > > Tue Nov 25 15:16:01 CET 2008 > > > > Hi all, > > > >
2008 Dec 23
1
quotation problem/dataframe names as function input argument.
Dear R friends: Can someone help me with the following problem? Many thanks in advance. # Problem Description: # I want to write functions which take a (character) vector of dataframe names as input argument. # For example, I want to extract the number of observations from a number of dataframes. # I tried the following: nobs.fun <- function (dframe.vec) { nobs.vec <-
2012 Mar 30
1
How to use access results of gregexpr in data frames
Hello, I'm trying to figure out how to find the index of the second occurrence of "/" in a string (which happens to represent a date) within a data frame column. I've used the following code successfully to find the first instance of "/". dframe <- data.frame(date=c("5/14/2011", "4/7/2011")) dframe$x1 <- regexpr("/", dframe[, 1])
2011 Jun 09
3
How to subset based on column name that is a number ?
Hi, I have a data frame with column names "1", "2", "3", ... and I'd like to extract a subset based on the values in the first column. None of the methods I tried worked (below). x <- subset(dframe, 1 = = "My Text") x <- subset(dframe, "1" = = "My Text") x <- subset(dframe, names(dframe)[1] = = "My Text") Q
2005 Nov 09
2
error in NORM lib
Dear alltogether, I experience very strange behavior of imputation of NA's with the NORM library. I use R 2.2.0, win32. The code is below and the same dataset was also tried with MICE and aregImpute() from HMISC _without_ any problem. The problem is as follows: (1) using the whole dataset results in very strange imputations - values far beyond the maximum of the respective column, >
2006 Jan 20
3
Selecting data frame components by name - do you know a shorter way?
Hi! I suspect there must be an easy way to access components of a data frame by name, i.e. the input should look like "name1 name2 name3 ..." and the output be a data frame of those components with the corresponding names. I ´ve been trying for hours, but only found the long way to do it (which is not feasible, since I have lots of components to select):
2011 Jul 08
1
Referencing a vector of data labels in ggplot function
Hi, I really feel I've looked everywhere, although I know this can't be a hard problem. I'd like to be able to call the graph below as a function, but I can't get the function to recognize variables beyond 'dframe'. I've read through many papers on writing functions in R, but I can't get this to work. data <- data.frame('date' = as.Date(rep(c(15101,
1999 Oct 19
2
Summary bug?
Hi, It seems that there's a bug in summary, in the max. output... but max() alone works fine. > hw04.dframe$area ... [41] 1790 1380 1296 2745 798 2306 438649 1481 1559 2450 ... > summary(hw04.dframe) area Min. : 798 1st Qu.: 1349 Median : 1690 Mean : 6962 3rd Qu.: 2306 Max. :438600 ### should read 438649 or, to the point,
2006 Jun 09
3
sqlSave() and rownames=TRUE makes my Rgui crash
Hello, I created a table in MySQL with this command CREATE TABLE example (pk INT NOT NULL AUTO_INCREMENT,PRIMARY KEY(pk), id VARCHAR(30),col1 VARCHAR(30),col2 VARCHAR(30)) ### In R, I can connect to this table: library(DBI) library(RODBC) chan <- odbcConnect("MySQL51", uid="root", pwd="xxx") first <- sqlQuery(chan, "select * from example")
2008 Sep 12
2
Finding a vector position using names rather than values
Dear R gurus, I have been struggling with this for a while and thought you might be able to give me some guidance. I have a data frame, on which I apply a row function. The result looks to me like a vector that retains the old row names. I then sort the vector and subsequently need to be able to identify the rank of certain values by searching for their row names. See this mock example: >
2000 Aug 01
1
Testing for parallel slopes
I'm running a series of simple bivariate linear regressions on grouped data. I want to test the slopes to see if they are parallel. I normally use analysis of covariance to do so, looking at interaction between the covariate and the factor to make this determination. VR3 pp.149 - 154 has a very nice example of an ANOCOVA, ending with a discussion of this very operation. My question has
2012 Aug 24
1
help with a special variant of balloonplot
Hi, I am interested in implementing a special variant of balloonplot.  Let me explain with an example dataset from the reference manual : library(gplots) data(Titanic) dframe<-as.data.frame(Titanic) survived<-dframe[dframe$Survived=="Yes",] attach(survived) balloonplot(x=Class,y=list(Age,Sex),z=Freq,sort=TRUE,show.zeros=TRUE,cum.margins=FALSE,             main="BalloonPlot :
2010 Jul 09
2
select columns from vector of column names
Hi I want to extract columns from a data frame using a vector with the desired column names. This short example uses the select argument in the subset function to accomplish what I am trying to do. Is there a better solution? #names of desired columns colnames <- c("col1","col3") #my data data <-
2001 Mar 16
0
boot() vs S-Plus bootstrap()
I'm trying to adapt some S-Plus scripts to run in R (1.2.2, Windows). In one of these scripts, I've bootstrapped the prediction success rate under the discriminant function (lda). The bootstrap() functions are proprietary to S-Plus and there aren't exact equivalents in R. The closest is Canty's library boot based on the Davidson and Hinkley book. Unfortunately, I
2000 Jun 22
1
Summary: 'pausing' in R (fwd)
The question was: > I have this 'odd' problem; I need to let R pause, for a given time, before > starting next iteration in a loop. I'm using the following to do this > task, but feel a little bit guilty because I'm using as much CPU time as I > can get while pausing: > > while(keepGoing) { > t.end <- proc.time()[3] + 5 ## the time this loop should end
2011 Jul 22
2
averaging rows based on string¿?
Hi Folks, Ran into something I'd really like to do in R simply/elegantly, but my R - coding skills seem surpassed. This is the thing. Imagine the following data: labs<-c("abcdef","abcgg","tgthefdk","tgtijuel","tgtnjmoi","gbnt","dlift") dat<-c(0.5,0.25,1,2,16,0.250,4) dframe<-data.frame(labs,dat) I would like to