similar to: How do you go beyond tapply()?

The on-line documentation for par() refers to a 'gamma' argument. However, if 'par()' is invoked, there is no gamma argument. -- Art Salwin salwin@mitretek.org (202) 863-2985 (202) 863-2988 (fax) --please do not edit the information below-- Version: platform = Windows arch = x86 os = Win32 system = x86, Win32 status = major = 1 minor = 0.0 year = 2000 month = February

The on-line documentation for the 'ann' argument under par(), states "If set to 'FALSE'...". However, this parameter shows up as a numeric on my machine, not as a logical. -- Art Salwin salwin@mitretek.org (202) 863-2985 (202) 863-2988 (fax) --please do not edit the information below-- Version: platform = Windows arch = x86 os = Win32 system = x86, Win32

The documentation for 'order()' has the following sentence: `sort.list' is the same, using only one argument put allowing partial sorting. Should "put" be "but" or possibly "'partial'"? -- Art Salwin salwin@mitretek.org (202) 863-2985 (202) 863-2988 (fax) --please do not edit the information below-- Version: platform = Windows arch =

Is there an R function that inputs a value and a vector, and returns the percentile corresponding to the value? Something like pvalue<-function(x,vector){mean(x>=vector)} but with interpolation. Given the above function, is there a way to do the following without the loop: for(i in 1:10) y[i] <- pvalue(x[i],vector) where x and y are numeric vectors of length 10? -- Art Salwin

Here are some comments generated by a new R user based on initial experiences with the tool. On-line help for tapply: The following appears "for to each (non-empty) group of values" It seems there's an extra preposition in this sentence. On-line help for cut: "break" should be "breaks" morley.data not available with the distribution. Would be helpful for

Hello, I want to fit some non linear models with the Levenberg-Marquardt algorithm. It doesn''t seem to exist any function to do this in R ( well, maybe one does, but I''m a new user, and the only documentation I have is "An introduction to R"). I''d like to know if this function exists, maybe throught an additionnal package. I''d also like to know if if

> Date: Mon, 02 Oct 2000 08:53:32 -0400 > From: Art Salwin <salwin at mitretek.org> > X-Accept-Language: en > To: R Help List <r-help at stat.math.ethz.ch> > Subject: [R] Use of example() > X-MIMETrack: Itemize by SMTP Server on Mail1/Mitretek Systems(Release 5.0.4 |June 8, 2000) at 10/02/2000 08:51:32 AM, Serialize by Router on Mail1/Mitretek Systems(Release 5.0.4

Hi all, how can I remove objects from the workspace which starts with a certain pattern, e.g. lm (lm1, lm2, lm3 etc). Wildcards won?t work. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the

Dear r user, please find my attached sample of the dataset i? am using to create a crosstable and eventually plot a histogram from the output. I am using? the cut2 function to create bins, about 7 of them using the code after reading the data: cluster <- cut2(cross_val$value, g=7) I get the warning: Warning message: In min(xx[xx > upper]) : no non-missing arguments to min; returning Inf

On Sun, 2016-12-25 at 13:38 -0600, geo.inbox.ignored wrote: > On 12/25/2016 11:53 AM, Mark Woolfson (Notebook) wrote: > > If the server decision makers had not gone for a server designed > > by accountants but a server designed by engineers then you would > > not have this problem. > maybe accountants in U.K., not is U.S.A.. > > accountants in U.S.A. only

I have one factor with say five levels (fact) of different size and a corresponding variable (var). I randomly generate five new levels (nfact ex. 2,2,1,5,4). What I would like to do is to extract the corresponding variable values into a new variable (nvar). I did try the following, why doesn't it work? nvar<-var[fact==nfact[ ]] Patrik Waldmann

If the server decision makers had not gone for a server designed by accountants but a server designed by engineers then you would not have this problem. Regards, Mark Woolfson MW Consultancy Ltd Leeds United Kingdom Tel: +44 113 259 0759 Mob: +44 786 065 2778 -----Original Message----- From: geo.inbox.ignored Sent: Sunday, December 25, 2016 7:49 AM To: centos at centos.org Subject: Re:

This may be a begining question. If so, please bear with me. If I have some data that based on the historgram and other plots it "looks" like a beta distribution. Is there a function or functions within R to help me determine the model parameters for such a distirbution? Similarily for other "common" distirbutions, Poisson(lambda), Chi-Square(degrees of freedom, chi-square

I''m trying to wrap my caffeine soaked brain around has_many :through following along at: http://rails.techno-weenie.net/tip/2005/12/23/teaching_your_blog_model_new_tricks_with_has_many_through I think my models are a little more complex than what fits this narrative. I have a directory of members, each member can belong to multiple categories. The category table references itself

CID DISTRICT SCHOOL YRofSTUDY DATE.ENTRY SEX AGE EGGS.M EGGS.MII EGGS.H POBADN0130 PO Badongo 0 18.1.08 2 11 0 -1 73 POBADN0117 PO Badongo 0 18.1.08 1 10 0 -1 59 POBADN0160 PO Badongo 0 18.1.08 1 11 0 -1 56 POBADN0112 PO Badongo 0 18.1.08 2 10 0 -1 47 POBADN0053 PO Badongo 0 18.1.08 1 8 0 -1 42 POBADN0141 PO Badongo 0 18.1.08 2 11 0 -1 36 POBADN0056 PO Badongo 0 18.1.08 1 8 0 -1 26 POBADN0127 PO

Hi, I'm having permissions problems connecting to a share when the gid of the directory shared is not the primary group of the user connecting to it. Maybe I faced it the wrong way, but I did read (and at least thought I understood) the 'File, directory and share access controls' section of the howto [0]. My users have either one or another 'primary group' (the one set in

Hello, I'm trying to plot a historgram with a density plot superimposed: hist(x, seq(-1, 1, by = 0.1), prob = T, col = "blue") lines(density(x, bw = 0.1)) rug(x) I don't want to add rug(x) but the histogram will not be plotted unless rug(x) is there. It does not work if the "hist" line alone is present. Can you help? Thanks, Kim [[alternative HTML version

Dear: I have two series data, which are: p1-obs p1-exp 13 13 20 23.296 22 18.139 19 14.972 10 12.576 16 10.658 8 9.0794 4 7.7625 3 6.6536 5 5.7141 7 4.9146 4 4.2321 0 3.648 4 3.1471 4 2.7168 2 2.3468 4 2.0283 2 1.7537 2 1.517 5 1.3127 1 1.1362

Dear all, I have a question. How to get the standard errors of alpha and beta when using "ca.jo" to test cointergration? In the paper by Bernhard Pfaff and Kronberg im Taunus “VAR, SVAR and SVEC Models: Implementation Within R Package” pp.24-25. The standard errors are listed on the table 5 following the code: R> vecm.r1 <- cajorls(vecm, r = 1) I tried this in my Mac R, but

I have just managed to get my first Samba/LDAP PDC up and running. But I have one big security problem -- users logging in to the PDC using ssh can access all shares. User credentials, both for ssh login and for Samba access, are retrieved from the LDAP directory. All shares are stored in the /var/lib/samba directory. The directories permissions look like this: drwxrwx--- 2 root Domain