similar to: R hangs when hist() gets vector with a single value

Well, I upgraded to a later release and have been having good luck (R vers. 0.65.0) I haven't upgraded my Red-Hat linux from 5.2 so I had to compile from source , ... so far so good. My problem is with the time series functions [library(ts)]. I'm trying to use the autocorrelation function-acf() and am having problems with it. mainly an error ERROR -Couldn't find function

# CASE 1 # The following plots a single cell or block for all three location 0,1,2. y <- rep(2,8) hist(y) # why is this a single block? hist(y,xlim=c(0,2)) # same thing hist(y,breaks=2) # same # CASE 2 # adding a different value, plots as expected y <- append(y,0) hist(y) # plots as expected In most cases of the data I have variances in the data so

I am new to R so I apologize if my question is trivial. I have not been able to figure out whether what I want to do is even possible. I have a data frame of stock ticker symbols which I store into R space from a txt file as follows: tickers <- read.csv("stocks.txt", header=FALSE, sep=",") tickers <- tickers[1] / the tickers are stored in the first column >

Hi all I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong... > hist.Date(dt_cycles) Error: couldn't find function "hist.Date" > hist.date(dt_cycles) Error: couldn't find function "hist.date" > cycles [1] 7 1

Can someone help me with a misunderstanding I'm having with hist? I expected, from the example below, that the number of bins would always be 10 and the length of the counts array the same. According to the help section 'breaks' can be a integer indicating the number of bins. From the example below, the number of bins (length of the counts array) varies. Am I wrong in expecting the

Full_Name: Alex Deckmyn Version: 2.4.0 OS: linux Submission from: (NULL) (193.190.63.62) specifying the "right" option in hist results in a warning when plot=F. The option is taken into account correctly, but a warning is issued anyway. When plot=T there is no warning. > hist(c(1,1.5),breaks=0:4)$counts [1] 1 1 0 0 > hist(c(1,1.5),breaks=0:4,right=T)$counts [1] 1 1 0 0 >

Dear developers, the current implementation of hist.default() calculates 'density' (and 'intensities') as dens <- counts/(n*h) where h has been calculated before as h <- diff(fuzzybreaks) which results in 'fuzzy' values for the density, see e.g. > tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE) > print(tmp$density,digits=15) [1]

Hi, all. I'm using hist() to obtain a vector of break values in an interval. I then want to be able to identify which cell any value from another vector falls in. E.g. applying > breaks [1] -3.5 -3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 2.0 to > x [1] -3.74519666 -0.38183630 -1.22884247 -0.20971824 -0.30533939 -0.36271207 [7] -2.27513499 -2.23688653 -1.98827155 -1.48666274

Full_Name: Reinhold Koch Version: 1.6.1 OS: redhat 8.0 Submission from: (NULL) (131.152.84.111) I came across rather weird behavior of the breaks in hist: hist(1:3) gives the expected result, besides an unnecessary gap between 2nd and 3rd column hist(1:4) always merges up the first two columns, also if I resort to hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an

Hi, This is a very basic question, but I would like to undestand hist(). I thought that the hist( , freq=FALSE) should provide the relative frequencies (probabilities), and so they should sum 1, however: set.seed(2) ah <- hist(rnorm(100), freq=F) sum(ah$intensities) [1] 2 set.seed(2) bh <- hist(rlnorm(100), freq=F) sum(bh$intensities) [1] 0.4999996 I'm getting similar figures with

Hi there, # Consider the following example: A = 19 B = 20 A< B A==B hist(c(1:15,B,50),breaks=c(0,15,A,50),plot=F)$count hist(c(1:15,A,50),breaks=c(0,15,B,50),plot=F)$count # I was expecting the same results with the following values of A and B: A = 19.6019203953960 B = 19.6019204365543 A< B A==B hist(c(1:15,B,50),breaks=c(0,15,A,50),plot=F)$count# wrong

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hi all, A friend send me a question on why does this: x<-rpois(100,1) sum( hist(x)$density ) Gives out "2" I tried this: sum( hist(x, freq =T)$density ) It didn't help. Then he came back with the following insight: # with breaks b<-c(0,0.9,1:8) sum(hist(x,breaks=b)$density) # Much more then 2 # but if we add weights according to the interval length

The following code is giving me problems. I want to export densities of a distribution to a csv file. At the bottom of the code I use the hist function to generate the densities. But hist is returning values greater than 1. I don't understand, why. Any help you can supply is greatly appreciated. # Set word path dir<-"~/Research/MR Distribution Analysis/" setwd(dir)

Full_Name: Stephan Schlueter Version: 1.9.0 OS: Submission from: (NULL) (217.184.109.24) During my studies, I found a fault in the hist()-function: If you have a vector x with values around zero and also bigger than 10,000,000 , there will be a shift of -max(x)/10,000,000 in the hist-datas. See my example: x<-runif(10000) hist(x,breaks=c(seq(-3,3,0.1)),prob=TRUE) #everything ok, but

Hi! How to find out which plot function is used when i call plot(hist.default(1:10,plot=F)) and all works fine ? The reason why I would like to know it is that after loading some self written R functions > plot(hist.default(1:10,plot=F)) Error in xy.coords(x, y, xlabel, ylabel, log) : x and y lengths differ > traceback() 5: stop("x and y lengths differ") 4: xy.coords(x, y,

hist() is designed so that the total area sums to 1. You should build you desired behavior using a barchart. ? David Sent from my iPhone > On Aug 5, 2023, at 11:50 PM, Ott Toomet <otoomet at gmail.com> wrote: > > ?Sorry if this topic has been discussed earlier. > > Currently, hist(..., log="y") fails with > >> hist(rexp(1000, 1), log="y")

Sorry if this topic has been discussed earlier. Currently, hist(..., log="y") fails with > hist(rexp(1000, 1), log="y") Warning messages: 1: In plot.window(xlim, ylim, "", ...) : nonfinite axis=2 limits [GScale(-inf,2.59218,..); log=TRUE] -- corrected now 2: In title(main = main, sub = sub, xlab = xlab, ylab = ylab, ...) : "log" is not a graphical

Full_Name: Arto Luoma Version: 1.3.1 OS: Windows 98 Submission from: (NULL) (153.1.53.119) Hi! The function get.hist.quote in the package tseries (Version 0.7-6) does not work in my computer. I found that it uses the function strptime which did not "understand" English month names in my Finnish locale (see bug report 811). I changed the regional settings to be English (UK) and

In plot() I can get greek symbols into text items without trouble. However, some of the same commands don't work as I would expect with hist(). See the example below. > plot(1:10, 2:11, xlab=expression(paste("scaled", rho))) ---- works as expected, ie. prints the greek rho > hist(c(0,0,0,0,4,5,6,6,6,8), xlab=expression(paste("scaled", rho))) Error: Object