similar to: format backslash behaviour

Full_Name: John Peters Version: 1.5.1 OS: Windows 2000 Submission from: (NULL) (130.155.2.3) solve(a,b) with two arguments gives an error if a is complex and b is a vector: > a_matrix(c(1,2+3i,3,2),ncol=2) > a [,1] [,2] [1,] 1+0i 3+0i [2,] 2+3i 2+0i > b_c(2,2+1i) > solve(a,b) Error in solve.default(a, b) : A must be a complex matrix > is.complex(a) [1] TRUE >

For R bugs: "as.numeric" fails on strings with trailing spaces: (OK in Splus 3.4). > as.numeric(c("2"," 3","4 "," 5 ")) Warning: NAs introduced by coercion [1] 2 3 NA NA > occurs in both "rw0641b" and "R-base-0.64.1-4-i386.rpm". Thanks for R ----------------------------------------------------------------------------

Using rw0642 under win95, on executing from a directory on the c: drive: system("command.com /c dir", intern=T) there is a whirring from drive a: (empty), then the message appears in a dos box: General failure reading device aLP!!? Abort, Retry, Fail? Repeating the command a few times finally results in success with no whirring, after which there are no failures (even

Dear all, We have developed our own Affymetrix chip (Custom Express Array, PM-only with two species). I want to analyse the data with the limma package, but for that I need to built my own CDF package, probe package and built the filters to analyse one specie or another. I'm using the makeProbePackage available in the AnnotationDbi (for a R-2.13.0) but I got the following error message:

Hello, I just tried the rw0640 version for Windows95. If I type link.html.help() a 1: appears. Does anyone knows what to type in after that, it seems that some input is required? Thanks CHRISTOPH ********************************************************* Christoph Kalinowski Catholic University of Eichstaett Department of Business Administration Auf der Schanz 49

Thank you very much for your reply. Your code work well with this example. I modified a little to fit my real data, I got an error massage. Error in split.default(x = seq_len(nrow(x)), f = f, drop = drop, ...) : Group length is 0 but data length > 0 On Thu, Jan 31, 2013 at 12:21 PM, arun kirshna [via R] < ml-node+s789695n4657196h87@n4.nabble.com> wrote: > Hi, > Try this: >

---------- > De : Guido Masarotto <guido at hal.stat.unipd.it> > A : r-announce at stat.math.ethz.ch > Objet : R-0.64.0 for Win9X/WinNT > Date?: mardi 13 avril 1999 10:08 > > > Windows binaries and source at CRAN (binaries/windows/Windows-NT/base) > have been updated to R-0.64.0. Thank you very much Guido and Brian! On my machine (with MikTeX installed), I use

R Version 1.9.1 (2004-06-21) Mac OS X.3.5 Dual 2GHz PowerPC G5 GUI = "AQUA" I have a data.frame comprising percentiles with the column headings containing % characters, e.g. > (pp <- colnames(temp2)) [1] "5%" "10%" "25%" "50%" "75%" "90%" "95%" I use xtable to convert the data.frame to Latex but I want to

Hi All, I'm wanting to convert a ragged list of values into a structured matrix for further analysis later on, i have a solution to this problem (below) but i'm dealing with datasets upto 1GB in size, (i have 24GB of memory so can load it) but it takes a LONG time to run the code on a large dataset. I was wondering if anyone had any tips or tricks that may make this run faster? Below is

Hello, I have a big problem which I’m just not able to solve. I created the following mean value from the following dataset structure: Id |value 1 | 2 1 | 3 1 | 4 2 | 2 2 | 1 3 | 5 4 | 3 etc.|etc. with the command: mean_rating <- tapply(ratok$value, ratok$project_id , mean,simplify = FALSE) this gives me a ragged array: > mean_rating [1] $`14`

Hi all, I wrote a function that actually does what I want it to do, but it tends to be very slow for large amount of data. On my computer it takes 5.37 seconds for 16000 data points and 21.95 seconds for 32000 data points. As my real data consists of 18000000 data points it would take ages to use the function as it is now. Could someone help me to speed up the calculation? Thank you, Tonja

HI, Using c11<- 0.01 c12<- 0.01 c1<- 0.10 c2<- 0.10 One possible problem is that: dim(res5) #[1] 513? 20 res6<-aggregate(.~m1+n1+m+n,data=res5[,c(1:6,9:12,21:24)] ,max) #Error in `[.data.frame`(res5, , c(1:6, 9:12, 21:24)) : ?# undefined columns selected A.K. ________________________________ From: Joanna Zhang <zjoanna2013 at gmail.com> To: arun <smartpink111 at

I want to replace \\ with \ in: str <- "C:\\DOKUME~1\\u0327336\\LOKALE~1\\Temp\\RtmpQ5NJ8X\\TIRIS_PICS\\1_Img.jpg" and tried: gsub("\\\\", "\\", str) but this removes the \\ without replacing them by \ Any help much appreciated, Kay ----- ------------------------ Kay Cichini Postgraduate student Institute of Botany Univ. of Innsbruck ------------------------

How can I add an extra column containing the rank to a ragged array indexed by more than one grouping factors? E.g. with the barley dataset: How can I to add an additional column ``rank'' containing the rank of the ``yield'' of the different varieties in relation to the indices ``year'' and ``site'' to the barley dataframe? I achieved to calculate the ranks with:

Hello everybody, this might be a trivial question, but I have been unable to find this using Google. I am trying to replace double backslashes with single backslashes using gsub. There seems to be some unexpected behaviour with regards to the replacement string "\\". The following example uses the string C:\\ which should be converted to C:\ . > gsub("\\\\",

Hello! I've just started trying gnome-terminal (instead of xterm) because of its "tabbing" facility. However, I note that with it backslashes appear something like a W with a horizontal line through it. Any known way to get a backslash to appear as a backslash? To see what I mean, use gnome-terminal with echo '\' in bash, ksh, etc. Regards, Chip Campbell

Just wondering how come read.table lets you specify fill=TRUE for ragged arrays, but so far as I can tell, no equivalent for write.table? Not a big deal, since I'm perfectly comfortable w/ write and scan and the other file I/O goodies. "A foolish inconsistency..." and all that. Carl

Hello, Can anyone help on gsub() in R? I have a string like something below, and wanted to delete all the strings with leading backslash, including "\xa0On", "\023, "\xab", and many others. How should I write a regular expression pattern in gsub()? I don't care how many characters following backslash. txt <- "Is This Thing\xa0On? http://bit.ly/jAbKem

Hello, I am not very familiar with regular expressions and escaping. I need to replace the %-signs in a character vector with elements as "income 0%-33%# to be replaced by "income 0\%-33\%" (for later use in LaTeX). Using gsub("%","\\%","income 0%-33%") does not give the desired result. However, gsub("%","\\\\%","income

Dear list, After searching many old posts, I can't find the solution to a simple problem. can someone tell me how to create a character string with multiple backslashes, as in: file_dir <- c("C:\files\data\") I need to create this string and then paste it to many files names for batch processing in another software program. R won't accept the backslash and removes