similar to: R-beta: Rank-order tests

Displaying 20 results from an estimated 10000 matches similar to: "R-beta: Rank-order tests"

1998 May 11
2
R-beta: Corrections to documentation
Thanks to Peter Dalgaard's message, I learned a bit more about the 'par' function and rewrote my HTML help file accordingly. Is it appropriate to submit such changes somewhere to improve the documentation? I would also be willing to write some missing documentation as well. Dr. Jim Lemon -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing
2004 Dec 02
7
A possible way to reduce basic questions
Jim Lemon <bitwrit <at> ozemail.com.au> writes: > I have been thinking about how to reduce the number of basic questions that > elicit the ...ahem... robust debate that has occurred about how to answer The traffic on r-help could be reduced by creating a second list where more elementary questions are asked. There may be other ways to partition the universe of questions
2005 Nov 19
1
[package concord] seeking maintainer
Hi, can anybody tell me how to contact the maintainer of the "concord" package? The address given in the help file is not valid anymore. ,---- | > help(package=concord) | | Information f?r Paket 'concord' | | Description: | | Package: concord | Version: 1.4-2 | Date: 2005-05-10 | Title: Concordance and reliability | Author: Jim Lemon
2001 Feb 28
2
(off topic) Re: Notepad
At 21:57 28/02/01 +0100, Peter Dalgaard BSA wrote: >Jim Lemon <bitwrit at ozemail.com.au> writes: > >> 3) The usual number of responses spent a lot of time dissing NotePad and >> advertising their favorite editor. As various contributors noted, >> NotePad actually does most of the things that some people said it >> doesn't. Positive advice (like the fact
2004 Apr 20
2
Rank - Descending order
Dear All, Is there any simple way to way to produce "rank", for a given list, but in a descending order? E.G: x = list(a=c(1,5,2,4)); rank(x$a); produces 1,4,2,3 However I am looking for a way to generate (4,1,3,2). It would be particularly nice if the proposed solution has all the niceties of rank function (like NA handling and ties.method functionality) TIA Manoj
2012 Nov 21
1
I don't know the difference between rank and order
I don't know the difference between rank and order.For example: > x=c(10,30,30,20,10,20) > x[rank(x,ties.method="first")] [1] 10 10 20 30 30 20 > x[order(x)] [1] 10 10 20 20 30 30 the result is quite different, x[rank(x,ties.method="first")] [1] 10 10 20 30 30 20 It is not sorted,why? -- View this message in context:
2007 Aug 06
1
rank in decreasing order
Hi All, I want to give ranks to elements in a column so I used: total_list$field1.rank <- rank(total_list$field1,ties.method="min") But this gives me the rank in increasing order. How do I get the ranks in decreasing order? I know decreasing = FALSE is not a legal argument here. Thanks. Jiong The email message (and any attachments) is for the sole use of the intended recipient(s)
2012 Jan 15
0
Regression for Rank Order Dependent Variable
Dear colleagues, I am looking for a package to analyze rank-order data in the form of regression. My outcome (dependent) variable is a rank ordering in the sense that the respondents to a  questionnaire were asked a single question: to assign the values 1 to 4 to four different objects (e.g. to rank four cars as best , second best etc). Their first preference was number 1, their second was 
2004 Dec 01
2
rank in descending order?
Hi, Is there any simple solution to get ranks in descending order? Example, a <- c(10, 98, 98, 98, 99, 100) r <- rank(a, ties.method="average") produces 1 3 3 3 5 6 I would want this instead: 6 5 3 3 3 1 Note that reversing r doesn't work but in small examples. Thanks, -Jose -- jquesada at andrew.cmu.edu Research associate http://lsa.colorado.edu/~quesadaj Dept. of
2005 Feb 23
6
Getting tick positions
While writing a function that includes placing grid lines at the same position as the axis ticks, I found that the axis* functions don't return anything. Thus I have had to copy the appropriate function, removing the call to axis() and adding a line to return the tick positions. Is there a more elegant way to determine the tick positions on an axis? Thanks. Jim (normally bitwrit at
2008 Feb 28
4
p-value in Spearman rank order
Dear R-helpers, I would like to do a Spearman rank order test, and used the cor() function with the method "spearman". It gives me a number (correlation coefficient?) , but how can I get the p-value? Thank you for the help in advance! Regards, Anne-Katrin -- [[alternative HTML version deleted]]
2000 May 30
6
heap size trouble
Hi , I ''ve got a trouble with using R. When I want to load a file that contains 93 thousand raws and 22 colums of data (essentially float) R shows me this error message "heap size trouble" Does anyone could tell me what parameter shall I precise before launching R in order to load my big file. Thanks a lot -------------- next part -------------- A non-text attachment was
2012 Feb 15
7
ggplot rank stack bar automatically.
Hi, all, I am currently trying to learn this example. http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/ I created the stack bar easily. If I would like to rank the stack bar from the highest on the right, shortest on the left and eventually I could show the data "1991-00" on the left and "1823-30" on the right, how could I do that? Apart from this, I find
1998 Feb 24
3
R-beta: qr(A)$rank
I would like to find the rank of a matrix using R. Looking through a list of commands it seems that the command qr should do the job. Checking a simple example gave me the wrong answer. Here is the example: > A <- c(1,2,3,4,5,6) > A <- matrix(A, nrow=2, ncol=3) > A [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 > qr(A)$rank [1] 3 The correct answer is two. I
1998 Feb 24
3
R-beta: qr(A)$rank
I would like to find the rank of a matrix using R. Looking through a list of commands it seems that the command qr should do the job. Checking a simple example gave me the wrong answer. Here is the example: > A <- c(1,2,3,4,5,6) > A <- matrix(A, nrow=2, ncol=3) > A [,1] [,2] [,3] [1,] 1 3 5 [2,] 2 4 6 > qr(A)$rank [1] 3 The correct answer is two. I
2002 May 06
3
Spearman rank-order correlation matrix
I"ve got a data frame with a selection of columns I want to compute a rank-order correlation matrix from without disturbing the original data frame. foo[,c("a","b","d","f","g")] What I wanted to do, intuitively, was: > cor(rank(foo[,c("a","b","d","f","g")])) but rank in that context
2011 Dec 07
4
bug in rank(), order(), is.unsorted() on character vector
Hi, This looks OK: > x <- c("_1_", "1_9", "2_9") > rank(x) [1] 1 2 3 But this does not: > xa <- paste(x, "a", sep="") > xa [1] "_1_a" "1_9a" "2_9a" > rank(xa) [1] 2 1 3 Cheers, H. > sessionInfo() R version 2.14.0 (2011-10-31) Platform: x86_64-unknown-linux-gnu (64-bit) locale: [1]
2002 Jan 24
3
getting rank order
I'm doing a study where people place a deck of cards in a certain order. It's sufficient to assume that their colors & each has a number (it's actually about attributes of hobbies). I'd like to look for patterns in how they've arranged the deck. For each subject I have a list like 3,5,2,4,1, indicating that (s)he chose 3 first, then 5, then 2. . . . I think what I first
2001 Aug 15
2
FORTRAN in R
Hi, Can anyone tell me what might cause this error message? Error in .Fortran("swallocate", as.double(mtx), as.double(wt), as.integer(n), : C/Fortran function name not in load table This occurs when I copied the Splus stepwise() function into R. I can source into R fine, but when I need to call that function on some dataset, I got the above error message. Platform
2003 Jan 21
0
UseMethod; all.equal; isas-tests
1. UseMethod (via usemethod in objects.c) now uses the definition of class() to dispatch, with the methods package attached (dataClass(x)) and without (attr(x, "class")). Packages using a construction of the form if(is.null(class(x))) class(x) <- data.class(x) UseMethod("foo") should now get similar dispatch with the methods package attached. 2. all.equal and some of its