Displaying 20 results from an estimated 2000 matches similar to: "R-beta: ar"
1997 Oct 29
4
R-beta: new executable
I have just put up a new executable as a replacement for the one in
rseptbeta.zip
there have only been a few changes; mostly to the menu's. I am about
to start on a major overhaul including getting survival to work and
grabbing the 0.60 version once it's stable.
Please let me know about other enhancements you want....
robert
1997 Oct 29
4
R-beta: new executable
I have just put up a new executable as a replacement for the one in
rseptbeta.zip
there have only been a few changes; mostly to the menu's. I am about
to start on a major overhaul including getting survival to work and
grabbing the 0.60 version once it's stable.
Please let me know about other enhancements you want....
robert
2010 Dec 08
1
Newbie trying to understand $ so I can understand acf function in stats
I am trying to understand the function acf
stats:::acf shows me the function
I am having trouble understanding the usage "$acf" in the following
acf <- array(.C(R_acf, as.double(x), as.integer(sampleT),
as.integer(nser), as.integer(lag.max), as.integer(type ==
"correlation"), acf = double((lag.max + 1L) * nser *
nser), NAOK =
2011 Jan 17
0
Fw: Re: help in calculating ar on ranked vector
--- On Mon, 1/17/11, Raymond Wong <raywong365@yahoo.ca> wrote:
From: Raymond Wong <raywong365@yahoo.ca>
Subject: Re: [R] help in calculating ar on ranked vector
To: "Uwe Ligges" <ligges@statistik.tu-dortmund.de>
Received: Monday, January 17, 2011, 11:56 AM
Thanks Uwe:
Here is my code. the first set of print statements work, but not the second.
#
2000 Feb 11
1
Help Help!
Hello! I have two questions.
First of all, I have a problem dealing with acf
(Autocovariance function) and need help. First I
defined a time series, x, which is a vector created by
x <- ts(rnorm(200)). So I plugged the series directly
into the acf function, acf(x) and an error message
popped up as:
Error in .C("acf", as.double(x), as.integer(sampleT),
as.integer(nser), :
2000 Jun 20
1
pacf
Dear list,
according to the documentation of acf{ts}
"the partial correlation coefficient is estimated by fitting
autoregressive models of successively higher orders up to lag.max. "
However, R seems to return the Yule-Walker estimates of the PACF by
default. You can check this using c(1:10) as the series: the YW
estimates are 0.7000000 and -0.1527035 for lags 1 and 2 . If the PACF
2010 Jul 13
0
Bug in acf function?
I'm using R-2.9.1, so forgive me if this has already been resolved.
One element of the object returned from the acf function is n.used,
described in the man page as "The number of observations in the time
series".
However, I've noticed that this value is set to nrow(x) via the sampleT
variable, i.e. the number of rows in the passed-in series. This forces
an assumption that all
2011 Mar 29
1
Simple AR(2)
Hi there, we are beginners in R and we are trying to fit the following time
series using ar(2):
> x <- c(1.89, 2.46, 3.23, 3.95, 4.56, 5.07, 5.62, 6.16, 6.26, 6.56, 6.98,
> 7.36, 7.53, 7.84, 8.09)
The reason of choosing the present time series is that the we have
previously calculated analitically the autoregressive coefficients using
the direct inversion method as 1.1, 0.765, 0.1173.
2000 Feb 11
0
Help Help 2
Please pardon me if you see this message twice. The
mail server has a bit problem.
*****************************************************
Hello! I have two questions.
First of all, I have a problem dealing with acf
(Autocovariance function) and need help. First I
defined a time series, x, which is a vector created by
x <- ts(rnorm(200)). So I plugged the series directly
into the acf
2009 Nov 13
2
AR(2) modelling
Hi useRs,
I'm trying to fit a basic AR(2) model with the 'ar' function. And when
I try to check the value of the coefficients, I could not find the
same value as the 'ar' function.
Here is my example:
myserie <- c(212, 205, 210, 213, 217, 222, 216, 218, 220, 212, 215, 236)
#plot(myserie, type="l")
myserieminus0 <- tail(myserie, -2)
myserieminus1 <-
2009 Nov 13
2
AR(2) modelling
Hi useRs,
I'm trying to fit a basic AR(2) model with the 'ar' function. And when
I try to check the value of the coefficients, I could not find the
same value as the 'ar' function.
Here is my example:
myserie <- c(212, 205, 210, 213, 217, 222, 216, 218, 220, 212, 215, 236)
#plot(myserie, type="l")
myserieminus0 <- tail(myserie, -2)
myserieminus1 <-
1999 Jul 27
3
Preliminary version of ts package
There is now a preliminary version of a time series package in the R-devel
snapshots, and we would welcome feedback on it. It is based in part on the
packages bats (Martyn Plummer) and tseries (Adrian Trapletti) and in part
on code I had or have written. (Thanks for the contributions, Martyn and
Adrian!) Some of the existing ts code has been changed, for example to plot
multiple time series, so
2003 Jun 19
1
What's wrong with ar for my data?
Dear helpers,
When I use ar to fit the data with length 180, I have the following
error:
ar(x,method="burg")
Error in acf(x, type = "covariance",lag.max=order,plot=FALSE):
lag.max must be at least 1
If I use
ar(x), then I have
Call (x=x)
order selected 0 sigma^2 estimated as 5374
Obviously I missed some points for using ar.
This is R 1.7.0 under Redhat Linux
2011 May 16
1
Inverse autocorrelation fonction
I've been looking for an IACF() procedure in R for a long time (it's a very
convenient function to check for overdifferencing time series), and
eventually decided to write my own function. Here's what I came up with :
3 web-pages helped me estimate it :
http://www.xycoon.com/inverse_autocorrelations.htm
2005 May 12
3
acf problem ?
Hi
I'm getting the following error that do not make sense to me, what am
Idoing wrong ?
> acf(Recsim[1,], lag.max=1)
Error in acf(Recsim[1, ], lag.max = 1) : 'lag.max' must be at least 1
Regards
EJ
2001 Mar 19
0
DUP=T/F
In some tests I am getting a difference in the 7th or 8th significant digit depending
on whether I set DUP=T or DUP=F in the .Fortran call below. While this is not a huge
error it is bigger than I would expect and may be a symptom of another problem. Any
comments or suggestions? (R1.2.2 on Solaris.)
Paul Gilbert
_______
genD.ARMA <- function(model, data, d=0.01, eps=1e-4, r=6, warn=F){
n
1999 Jul 19
9
time series in R
Time Series functions in R
==========================
I think a good basic S-like functionality for library(ts) in base R
would include
ts class, tsp, is.ts, as.ts
plot methods
start end window frequency cycle deltat
lag diff aggregate
filter
spectrum, spec.pgram, spec.taper, cumulative periodogram, spec.ar?
ar -- at least univariate by Yule-Walker
arima -- sim, filter, mle, diag, forecast
2012 Sep 18
2
Data frame divison by another data frame with common groups and different length
Dear all,
I have two different data frames, that have two common variables: date and
sample. Here is a small extract of both of them
> head(traffic)
datet sessiont samplet buddleiat
1 07-08-2012 1 1 1
2 07-08-2012 1 1 1
3 07-08-2012 1 1 1
4 07-08-2012 1 2 3
5 07-08-2012 1 2
1997 Oct 10
1
R-alpha: rsept31.zip
I tried rsept31.zip under Windows 3.11 yesterday and it didn't work
at all ... the screen went black for a second and that was it.
Any glue what I've done wrong? Should it work under 3.11 or only under
95/NT?
.f
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Send "info",
2010 Apr 08
1
incomplete final line found by readTableHeader
Hi
I am trying this
> x <- read.table("/home/kenji/1245/GDS1_2grps_.cls", header = F, skip = 2)
> x <- read.table("/home/kenji/1246/MYCset.cls", header = F, skip = 2)
Warning message:
In read.table("/home/kenji/1246/MYCset.cls", header = F, skip = 2) :
incomplete final line found by readTableHeader on
'/home/kenji/1246/MYCset.cls'
Here are the