similar to: aggregate() example fails]

Hi R users and developers. I compile the R version 2.8.1 Patched (2009-03-18 r48193) On my UBUNTU linux distribution. But hen I ask for the aggregate example it fails. What am I missing? example(aggregate) aggrgt> ## Compute the averages for the variables in 'state.x77', grouped aggrgt> ## according to the region (Northeast, South, North Central, West) that aggrgt> ## each

Hi R developers and debian users: Finally I found how to work with aggregate() function on the last patched version fo R. I you use this command it fails: aggregate(state.x77, list(Region = state.region), mean) But if you modify it in this way, it works!: aggregate(state.x77, list(Region = state.region), function(x) mean(x) ) Is it necesary to change the example? What is changing in

Hi R developers and debian users: Finally I found how to work with aggregate() function on the last patched version fo R. I you use this command it fails: aggregate(state.x77, list(Region = state.region), mean) But if you modify it in this way, it works!: aggregate(state.x77, list(Region = state.region), function(x) mean(x) ) Is it necesary to change the example? What is changing in

I tried: > data(state.x77) Warning message: In data(state.x77) : data set 'state.x77' not found data(iris) seems to work fine, but the other state datasets (which I haven’t every tried before) don’t seem to be available on my windows 7 running R 2.12.2 installation. ?state brings up the state help page page which suggest the dataset should still be there. In help there still seems to

Hi all, I am trying to make tiff files of lattice plots at a resolution greater than 300 dpi required by a journal (PLoS ONE). I have tried both the tiff and bitmap functions. tiff keeps panel colors but reduces axes and tick labels so they are nearly invisible. bitmap maintains correct label size but only produces greyscale. Regular plots work fine with tiff; the problem is only with lattice

R 1.4.0 ?stars has scale: logical flag: if `TRUE', the columns of the data matrix are scaled independently so that the maximum value in each column is 1 and the minimum is 0. If `FALSE', the presumption is that the data have been scaled by some other algorithm to the range [0,1]. but the code has if (scale) { x <- sweep(x, 2,

Hello, I managed to install playwith package and all its prerequisites. My R version is R 2.14: R version 2.14.1 (2011-12-22) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: i486-pc-linux-gnu (32-bit) All my packages were updated, and recently installed. When I attempt to use the command playwith I get the following error message: >

Hello All, Would like to be able to convert a matrix to a dataframe without losing an assigned dimname. Here is an example that should illustrate what I'm talking about. tableData <- state.x77[c(7, 38, 20, 46), c(7, 1, 8)] names(dimnames(tableData)) <- c("State", "") tableData State Frost Population Area Connecticut 139 3100 4862

Dear all, I want to aggregate() my data based of the classes of a factors, just as in the help file, but how do I define the "Region varable" in the ?aggregate example? Now, the column is just like any other in my data matrix. As I understand it from ?(state), state contains a matrix with the columns Pop, Income etc., but Region is somehow separated. I noted below that as.list() is

Hi all, I am looking to create a rank variable based on a continuous variable for subsets of the data. For example, for an R integrated data set about US states this is how a loop could create what I want: ### Example with loop data <- cbind(state.region,as.data.frame(state.x77))[,1:2] # choosing a subset of the data data <- data[order(data$state.region, 1/data$Population),] #

Hola No es lo mismo pero en mi caso personal la forma que utilizo se basa en el ejemplo de http://cran.r-project.org/doc/contrib/grafi3.pdf página 49, no usa el if pero también hay una condición para todos los verdaderos. No intenté en este caso en particular, habría que ver si también da problemas, pero como Carlos Ortega que sabe mucho dio una solución y como vos estas empezando no quiero

Hello All, I have a question about glm in R. I would like to fit a model with glm function, I have a vector y (size n) which is my response variable and I have matrix X which is by size (n*f) where f is the number of features or columns. I have about 80 features, and when I fit a model using the following formula,? glmfit = glm(y ~ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 + x9 + x10 + x11 + x12 + x13

El problema puede estar en el no uso de suficientes paréntesis. Por ejemplo, con: > a=1 > b=0 > c=0 la instrucción ifelse(((a>1) | (b=0) | (c=1) | (d=1)), 11, 22) da el resultado esperado: [1] 11 Pero si se omiten los paréntesis se llega a un error de interpretación: destino de la asignación se expande a un objeto fuera del lenguaje Espero que sirva Jorge El 26/2/14, daniel

Hi, 1) I have noticed that when I use the aggregate function it outputs numbers in the results. for example: aggregate by product group.1 Aggregate 1 ProductA 1000400.00 2 ProductB 23232323.00 3 Missing 232323.00 is there a way to suppress the numbers infront of aggregate outputs. I checked and they don't look like columns when I do a summary so I can't -1

Comunidad superpower, tengo la siguiente pregunta-problema. Tengo una matriz de datos como la siguiente (adjunto archivos de datos): sol con dia rep nca nin iso are 1 con 0 1 1 16 0 s 0.3866520976 2 con 0 1 1 16 1 c 0.0008842527 3 con 0 1 1 18 0 s 0.2409465396 4 con 0 1 1 18 1 c 0.0021092822 5 con 0 3 1 16 0 s 0.6005446999 6 con

Hola, Si no tienes inconveniente en compartir tu conjunto de datos (puedes dejarlo en un Dropbox y compartir enlace) o incluir una salida de la variables: "seta" y "outcomes" (función "save.image()") con eso podemos darte alguna solución mucho más rápida que la que planteas. En tu código con un bucle estás tratando de rellenar una lista que son los diferentes

I try to display the grouping variable in coplot. It work, but it's special solution and rather ugly. Any better idea? # Simulate my data frame data(state) x77<-data.frame(state.x77) x77$region<-state.region coplot(Life.Exp ~ Income | region, data=x77, show.given=F, subscripts=T, panel = function(x, y,subscripts, ...) { panel.smooth(x, y, span = 1., ...)

Dear r-helpers, Does anyone have a straightforward example of putting together three unrelated (expect for a common y-axis) xyplot() figures in what would be in base graphics a par(mfrow = c(1, 3)) arrangement? _____________________________ Professor Michael Kubovy University of Virginia Department of Psychology USPS: P.O.Box 400400 Charlottesville, VA 22904-4400 Parcels: Room 102

Dear List, I've around 1000 *.txt files, I've generate with other software. I've now done the following code (below). My question is how can I automate this (with do.call () ?), so it could be done for all the *.txt files. Thanks in advance, Rog??rio names<- list.files() file <- "BLU_Var_%04d.txt" for(i in 1:1000){

Hi - a newbie question, if someone can please help.... I want to change X1, X2,,.....to X.1 X.2 etc in the names below. I am using the Principal Component Regression function (pcr) and it seems to want it this way > datap3.pcr <- pcr(water ~ X, 10, data = datap3, Validation ="cv") Error in model.frame.default(formula = water ~ X, data = datap3) : invalid type (list) for