similar to: Silly question

Hello, maybe that I''m a stupid, but I don''t know how I can working with pagination. In all examples is written (for example) next: def user_list @user_pages, @users = paginate(:users, :order_by => ''name'') end So, it''s OK (as a scaffold) for all set of users. But I need a little other functionality. For example I need paginate only a little bit

Hi Guys, I am trying to paginate the results from a search. When I use actual constants in the search conditions, it works fine: def query @k2_result_pages, @k2_results = paginate (:k2_results, :conditions => [''e_date >= ? AND e_date <= ?'', ''2006-07-12'', ''2006-08-12''],

> Unfortunately I still get the same error. Here is my code now (the > commented line works): > > def list > @upload_pages, @uploads = paginate(:uploads, :per_page => > 20, :order > => ''id'') > # @upload_pages, @uploads = paginate(:uploads, :per_page => 20) > end You may have an older version, try using the order_by clause

I''m trying to create a paginated list that will take note of the "end_date" field in my table. This is what I have: @post_pages, @posts = paginate(:posts, :per_page => 10, :order_by => ''end_date'') in the controller. And for the view: <h1>Posts ending soon</h1> <ul><% for post in @posts do %> <strong>Post Title:

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

because I am a grasshopper... Now that I can sort my ''list''...is there a logical way of not repeating myself to having essentially the same list view with multiple sorts? i.e. def list_cl # ordered by clients last name @placement_pages, @placements = paginate( :placements, :include => [:client], :order_by =>

Hi all, Best wishes for the new year! :'') I''m very new to Ruby and Rails, and I ran into a problem with the "paginate" function. When I use the following method to get a number of forum topics based on a category name passed via the URI: @topic_pages, @topics = paginate :topics, :joins => "INNER JOIN categories ON

Hello! I''m a beginner of rails. I made a simple test project with rails 1.1.2 and ruby 1.8.2 on Windows XP. DB is SQLServer 7.0. I''m connecting the server thru ODBC. I created a table named "users" with about 10 columns. I inserted 1000 sample records. I created a scaffold for user model and login controller for it using the script. Everything''s fine

hey, i have users who are in groups, and i have a search form, where i can search on group, user lastname, and user firstname. All this is also with pagination. these are my models class User < ActiveRecord::Base has_and_belongs_to_many :groups end class Group < ActiveRecord::Base has_and_belongs_to_many :users end in my controller i do this THIS works (but in need pagination) @users2

Hi all, I''m creating admin module. in that module i need to get the list of users and also the projects created by the each user. No doubt i''m getting the list of users. but i''m not getting the list of projects done by each user.. This is my code:: <% for user in @users %> <%=link_to

I''m trying to figure out how to change the order of a list view and it''s obvious to me that I don''t understand what I get from a simple scaffold to know enough to alter it. If someone would be so kind to tell me what this means ... def list @placment_pages, @placements = paginate :placements, :per_page => 10 end @placement_pages, # I am guessing that this

Hi, I am trying to implement a few queries now. What are good ways to do this? Right now, I have a list page that does sorting and can carry out a generic pagination request. @user_result_pages, @user_results = paginate(:user_results, :per_page => 20, :conditions => @condition, :order_by => @sort_order) I create @sort_order earlier in the list function. The problem I am having is

there are some things on a scaffold that i would like to use without the whole thing. is it better to generate one and then cut it down to only what you''ll use? are all of the things in a scaffold available to just build by hand? for instance, i have a scaffold for my users. in the list action, it has @user_pages, so that you can put @user_pages.current.next or something like that -

Hi, I have the following find statment @client_pages, @clients = paginate :clients, :per_page => 20, :order => "organisation_id, surname" currently im ordering by organisation_id however I need to order by the field in the organisation table organisations.name how can this be done? Thanks Scott -- Posted via http://www.ruby-forum.com/.

Hello, With default pagination I have this : <a href="/users/infos/3?page=1">1</a> <a href="/users/infos/3?page=3">3</a> but i need this : <a href="/users/infos/1">1</a> <a href="/users/infos/3">3</a> I need to remove the "?page=" parameters and rewrite a little the link ( with a link_to ? )

I know my thinking is sloppy. I want to know how many clients currently in my facility are male... My facilities_controller.rb def list_fac @placement_pages, @placements = paginate( :placements, :conditions => ["placements.facility_id = ?", params[:facility_id] ], :include => [:facility, :client], :order_by => ''facilities.name,

Hi all, Im trying to get my head around rails and to help along Im working through "four days on rails" as this seems to give a good real world example with multiple tables and relationships (the main thing I cant work out!) Ive got stuck. Some help would be really good here. The controller has this code: def list @category_pages, @categories = paginate(:category, :per_page =>

i''ve figured out how to use the next and previous links with the paginator class but now i''m trying to figure out how to display all the page numbers in between. looking through the rails api, i found paginator.each() but i''m not sure how to use it, or if that''s even what i am looking for. also, is there a way to limit the amount of pages like some sites

Hi, newbie here. I am trying to implement a filtering interface using observe_field. Using firebug I can see that I am getting the properly rendered html blob back in the response, but when it get inserted into the dom element that I am targeting, the plain html elements from the partial template have been stripped, leaving only the elements inserted via the <%= statements. I would

Hi there, Is there a neat and easy way to implement pagination with letters rather than numbers eg : A B C D ... Z Rob