similar to: 2 ajax related questions

Hi! I''ve got a list of project on the main page and if one of them is selected i render a partial using ajax with data of selected project. How to create links to next/previous project using pagination? -- Posted via http://www.ruby-forum.com/.

There must be a better way to write this code: @project_pages, @projects= paginate :project, :per_page => 10, :conditions => ["account_id = ?", account] ?! If only I could pass the sub-collection account = ... @projects = account.project to paginate, instead of letting it extract it with a find :all + sql conditions Alain. -- Posted via

Hi all, I''m creating admin module. in that module i need to get the list of users and also the projects created by the each user. No doubt i''m getting the list of users. but i''m not getting the list of projects done by each user.. This is my code:: <% for user in @users %> <%=link_to

Hi everyone, I''m at the end of my rope on this. I can''t get pagination to work with anything but a standard find on a model. If I try to do a search and customize the pagination, I get lots of different variations. My thought was to have the list action do what it does, but to pass it a list of search conditions from the search action. So, if search determines that we need

Hi, In my blog i display a post. I want to display a link tot he previous post if there is 1 and a link tot he next post if there is one. So i have in my controller def post @post = Post.find(params[:id]) @post_pages, @posts = paginate :posts, :per_page => 1 render(:layout => false) end And the following code in post.rhtml <% if @post_pages.current.next %> <%=

Hi, I am using the rails find command as below @project_pages, @projects = paginate :projects, :per_page => 20, :conditions => "clients.organisation_id = " + params[''search''][''organisation_id''], :joins => ''inner join clients ON clients.id = projects.client_id'' There seems to be a problem with project.id being over written

because I am a grasshopper... Now that I can sort my ''list''...is there a logical way of not repeating myself to having essentially the same list view with multiple sorts? i.e. def list_cl # ordered by clients last name @placement_pages, @placements = paginate( :placements, :include => [:client], :order_by =>

hi everybody, i am new to rails.. plz clear my doubt... this is my question In my table(public_topics), i have 11 rows of data.. whenever i run the following view, it shows the entire rows in the current page.. and i have set the '':per_page'' option to ''2''.so it must show two data per page..but it shows all the rows in a single page..and this case continue

hi, I am curently using rails version 2.1.1. Currently i have done simple pagination using will_paginate plugin.it works.but when i am trying pagination using ajax with help of will_paginate plugin it wont works.i am also using RemoteLinkRenderer helper, but it gives an error uninitialized constant RemoteLinkRenderer. can anyone provide any tutorial or sample code so that i can

I''m trying to create a paginated list that will take note of the "end_date" field in my table. This is what I have: @post_pages, @posts = paginate(:posts, :per_page => 10, :order_by => ''end_date'') in the controller. And for the view: <h1>Posts ending soon</h1> <ul><% for post in @posts do %> <strong>Post Title:

Hello, With default pagination I have this : <a href="/users/infos/3?page=1">1</a> <a href="/users/infos/3?page=3">3</a> but i need this : <a href="/users/infos/1">1</a> <a href="/users/infos/3">3</a> I need to remove the "?page=" parameters and rewrite a little the link ( with a link_to ? )

Hello, How do I get params from a form to use with a paginator? debug(params) shows this city: !map:HashWithIndifferentAccess id: "1" but in my controller, when I try to use @hotel_pages = Paginator.new self, Hotel.count(:conditions => "hotels.city_id = params[:city][:id]"), 3, @params[''page''] it doesn''t work. I suppose it''s a simple

i can use <%= link_to_remote("MEMBER LIST",:update => "mcont", :url => {:controller => :users, :action => :list }) %> this for user listing and then it display record i want to do paging on this list file but it is display one page when i click on second page this will no go to second my controller def list #@images = Image.paginate :page =>

Hi! It''s rather ruby question than rails... I have a single ''list'' action where i call paginate method. I can receive none, 1 or 2 variables that specify conditions for paginate method. How to write the code so i can call paginate without conditions if all conditions variable are nil, with a single condition if one of conditions variables is not empty and with 2 if

Hey all, I''m using a simple search function. It''s working great except for foreign keys. I have one table pets (id,name,owner_id) and another table people(id,name) owner_id being a foreign key of pet pointing to people name. here it is on the pet controller: @paginator, @pets= paginate(:pets, :conditions =>["name OR owner_id like

I have my list view filtering rows shown within the table <tr> tags like most of the introductory tutorials do. As I''m adding a few dozen entries I''m noticing the standard scaffolding pagination doesn''t pick up the number of rows from the filter since it is not being passed the number of rows returned within the scope of the filter statement. >From a

Hello. I call a find_all_by_subject("action") which returns 2 videos and displays them properly. But when I add @video_pages, @videos = paginate :videos, :per_page => 10 so I can paginate the videos, it displays ALL the videos as if I selected list videos. Can someone please tell me what I am doing wrong? Thank you. selectaction.rhtml <table> <tr> <% x = 0 %>

I have following code in my controller: class AlbumsController < ApplicationController def list_by_year(year) @album_pages @albums = paginate :albums, { :per_page => 10, :conditions => ["year = ?", year] } render :action => ''list'' end end Now I want to make a link to the list_by_year action in

Hello, I was talking with someone in IRC, trying to get one form with however many fields to make new rows. He worked with me on the controller, but then I didn''t get the help with the view I needed, and I''ve been trying to do it on my own. I''m uploading pictures to my Pictures table. As you know, I need a few fields for each picture. I''ll need the filename,

I keep getting this error every time I try to pass a value to a method. Here is a sample nonworking method. I''ve been pulling my hair out over this all night! Why won''t it work!? My url path is :3000/store/browse/shoes and I''m getting this in the log Parameters: {"action"=>"browse", "id"=>"shoes",