similar to: New package ISOweek: Week of the year and weekday according to ISO 8601

Hi All, Two years back, I posted a small function for getting the ISO 8601 defined week number of a date (such as the week number used in all Swedish calendars), in a os-independent manner. I've since discovered an inaccuracy in that code, and so I thought I'd repost the corrected version. Hopefully this will come in handy for someone searching the mailing list archives in the future.

Hi all, Is there a simple function already implemented for getting the ISO weeks of a Date object? I couldn't find one, and so wrote my own function to do it, but would appreciate a pointer to the "default" way. If a function is not yet implemented, could the code below be of interest to submit to CRAN? Best Regards, Gustaf --------------------

Dear R-help, I am working on a R package for public health surveillance where the ISO 8601 representation of dates is of importance. Especially, the ISO Week and ISO Year of a date needs to be extracted. I was quite happy to find all of this implemented in the "Date" class with appropriate calls to strptime/format (using e.g. %G and %V). However, only later I realized that this

We would like to set the standard date and time display on our CentOS hosts to the format "yyyy-mm-dd HH:mm:ss", where HH is the twenty-four hour clock. Does there exist a simple setting in Linux/CentOS that permits such a change for a specific LOCALE (in our case en_CA.UTF-8) or is it necessary to build a custom LOCALE LC_TIME file? If the latter case holds then can someone point me

The US water year extends from 01 October yyyy-1 through 30 September yyyy and is referenced by the year starting on the included 01 January yyyy. I'd like to be able to find the annual means for the water year. To do so I've taken the input date-time, which is in the usual format "1991-10-07 10:35:00" changed it by: w$d<-as.POSIXct(w$date.time) Now I can add an

Hey all, Virgin post to this list - hope I've got it right ;o) I've been learning R intensively the last two weeks and gone from newbie status to *reasonably* comfortable with it. Here's an issue I just cannot solve however as it appears to be some kind of bug in R itself. But I won't claim that for sure. I have a function as follows: FindHighRow <- function(searchVector,

Tomorrow morning my Central Europe will try to steal an hour of daylight by adding an extra hour at 2 am. This event will reintroduce an old but trivial show-stopper for the broader use of Samba. Microsoft has, perhaps intentionally, redefined the summer/winter time reckoning and just acknowledged in a KB article that, yes, MS Windows don't show the correct time, but they show the wrong

Greetings I'm having difficulty witht the strptime function. I can't seem to figure a way to strip month (name) and year and create separate columns from a column with MM/DD/YYYY formatted dates. Can anyone help? Cheers Kurt *************************************************************** Kurt Lewis Helf, Ph.D. Ecologist EEO Counselor National Park Service Cumberland Piedmont Network

Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3 2010-05-31 Monday 0.74813943 4 2010-06-01 Tuesday

Hi, I am trying to count weekday of the month using R. For example, 1/4/2001 is the 4th weekday of Jan, and 1/5/2001 is the 5th weekday of the month, and 1/8/2001 is the 6th weekday of the month, etc. I get as far as extracting the weekdays from a sequence of dates (see below). But I have not yet figured out a fast way of counting without using a For Loop. Does anyone know how to do such counting

(Sorry for reposting. Please delete previous msgs. Thanks!) Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604

Question from an [R] novice... Hi, I have a vector of date/times like the one shown below (a truncated sample of a much longer list...) > dates[1:4] [1] "2006-03-16 08:41:00" "2006-03-16 10:28:00" "2006-03-16 11:03:00" [4] "2006-03-16 11:04:00" I would like to generate a weekday histogram showing the frequency of dates falling on each weekday. I know

Sorry for reposting. The previous message not showing up. Hi, all Here I created a data frame like mydates<- seq(as.Date("2010-05-29"), length = 43, by = "day") myvalues<-runif(43,0,1) myframe<-data.frame(dates=mydates, day=weekdays(dates), value=myvalues) dates day value 1 2010-05-29 Saturday 0.14576143 2 2010-05-30 Sunday 0.37669604 3

Darren Tucker <dtucker at zip.com.au> writes: > On Thu, Oct 29, 2015 at 12:32 PM, Mark D. Baushke <mdb at juniper.net> wrote: > > Diff updated with suggested changes (also, making the timestamp format > > ISO8601 compliant). > > > > Hmmm... full IOS8601 compliance would include the timzeone so the format > > I don't have a copy of the ISO8601

Dear R-Gurus I have a data frame (from CSV file) which has its first column called Date. The Date is in the format mm/dd/yyyy. I was trying to get the weekday for these dates and I tried using wday() and day.of.week() functions and both of them gave me precisely the wrong answers. I think the issue lies in the proper formatting of dates. The class of this column is a factor class and hence I

The (*windows only*) xlsReadWrite package has been updated and the new version is available on CRAN. xlsReadWrite natively reads and writes Excel files (v97 - 2003). o Changes from v1.1.1 to v1.3.3 (versions between never really published) - ROWNAMES-support also for matrices (not only for data.frame) - explicit rowNames argument in interface. (stimulated by email Adrian Dusa) -

Hello there fellow R-users, I have received some data which comes in the following format: example1<-"200301" The first 4 digits correspond to the year and the remaining 2 digits correspond to the week of the year. I have tried to convert this to a date by using strptime as follows: strptime(example1,format="%Y%U") where U (looking up strptime) is the week of the

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Thanks. Regarding axis(1,at=x_yyyymmdd,labels=format(x_yyyymmdd,"%Y-%m-%d")) How do I get the text for YYYY-MM-DD to be drawn vertically, instead of horizontally? Greg > On May 6, 2018, at 11:54 PM, Jim Lemon <drjimlemon at gmail.com> wrote: > > axis(1,at=x_yyyymmdd,labels=format(x_yyyymmdd,"%Y-%m-%d")) [[alternative HTML version deleted]]

Hi Folks! I'm struggling with dates - but enough about my personal life..... I have two daily time series files. In one (x) the date format is Y/m/d and the other (y) is d/m/y. I used read.zoo on both and they read into R with no problem. Then I use: weekdays(as.Date(x$DATE)) and get what I expect - all the days of the week in my data set. When I use: