similar to: Date formatting and adding question

The Time::next_week method is supposed to give the time of the start of the next week. But look at this, it cocks up : >> t=Time.parse "Monday October 16th 2006" => Mon Oct 16 00:00:00 BST 2006 >> t.next_week => Mon Oct 23 00:00:00 BST 2006 >> t.next_week.next_week => Tue Oct 24 00:00:00 BST 2006 >> t.next_week.next_week.next_week => Mon Oct 30

Hello, I can't get setup.exe to install Microsoft Office Project 2007 on Xubuntu Jaunty 9.04 using Wine 1.0.1. At first the installation box will open, and I may see a hint of the colorful Office 2007 logo; but then a small box opens and says "Setup cannot continue because a required file is either corrupted or not available. Run Setup again from the original source disc or download

i ran into an error today when dealing with the method next_week and daylight savings time... >> Time.local( 2006,10,23 ).next_week => Tue Oct 24 00:00:00 EDT 2006 Any one know if this is a know issue or should a ticket be created for this issue? thanks for the help mark -- Mark Van Holstyn mvette13@gmail.com http://lotswholetime.com -------------- next part -------------- An HTML

Am 23.06.2020 10:07, schrieb Marek Greško: Hi > this is a correct response: > > From 62.156.246.57 (62.156.246.57) icmp_seq=1 Frag needed and DF set > (mtu = 1492) > > So PMTU discovery is working. No problem here. You got correct message > to lower the packet size from 62.156.246.57. This is probably the last > hop before your site. No, the last hop is 62.156.246.65:

Hi, I would like to make @dates in my controller. I tried the following: startdate = Time.now enddate = startdate.next_week for enddate > startdate @dates << startdate startdate = startdate.tomorrow end But I get an errormessage when I check the syntax: "warning: useless use of a variable in void context" Anyone? Thanks! Steven. -- Posted via

Hi, How do i convert a Date to a Time?? I have a date returned from sql and i need to be able to use handy functions like next_week or beggining of week. Any help appreciated Thanks, Chris -- Posted via http://www.ruby-forum.com/.

I''ve spent all day digging through the rails api and postgres-pr on this, I think it''s time to ask the list. Postgres stores a Date in YYYY-MM-DD format. My users want the dates in MM/DD/YYYY format. Sure, I could explicitly convert it on the app level every place where a date is displayed, but that seemed like a DRY violation. I thought I''d be clever and simply

Hi all, I am getting ActiveRecord to produce XML with render :xml => @user.to_xml However, on the client end it is a bit annoying for me to deal with attributes like first-name. I would much rather have first_name. Is there any way for me to turn off the behavior of converting _ to -? This seems to be done by a call to dasherize inside the to_xml of

Hi, I''ve followed these directions : http://railswiki.pdxruby.org/HowToDefineYourOwnDateFormat.html It seems pretty straightforward but obviously it doesn''t work for me... article.date_edited.to_formatted_s(:my_format_1) produce a default formatted date, not the one I''ve defined in environment.rb : ActiveSupport::CoreExtensions::Date::Conversions::DATE_FORMATS.merge!(

hi, overhere users go nuts if they have to enter the date in iso format, so i have to make my applications in such a way that not only dates are displayed in the "dd-mm-yyy" format but also can be entered in that way. somewhere i found this code to put in the environment script: ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.update( :default => ''%d/%m/%Y

So, I have a "schedules" table and a "hours" table, joined by a "hours_schedules" table. Think of the hours table as a category for when people will schedule themselves to work, which happens in weekly increments. At any given hour, there will be X number of people working. I need to represent each worker with an asterisk symbol in the weekly view. For example,

Hi, In my form I have date field set as ''datetime_select'' which is fine as I wanted it in the same format. But while displaying (list action) it displays date in long format i.e. ''Tue May 30 15:39:00 Central Daylight Time 2006''. How can I format it so that it will just be diaplyed as ''dd/mm/yyyy'' format? Thanks -- Posted via

Hey All, Anyone know of a library for parsing "human" dates, like "this friday" or "2 days ago"? I used to use strtotime in php, but starting from here; http://wiki.rubyonrails.com/rails/pages/PhpStrtotime and doing lots of googling, I haven''t been able to find anything similar for ruby. I know of javascript solutions to this, but I''d need to do

I have a test/fixtures/users.yml like so: apa: id: 1 username: apa [...] created_at: <%=Time.now.strftime("%Y-%m-%d %H:%M:%S")%> updated_at: <%=Time.now.strftime("%Y-%m-%d %H:%M:%S")%> I don''t like how I''m repeating myself with the strftime bit. Is there some shorter Time method to format time for a (MySQL) datetime field that

I am using http://code.google.com/p/calendardateselect/ for my date time picker. I am using dd.mm.yyyy format (:finnish) and i am using ActiveSupport::CoreExtensions::Date::Conversions::DATE_FORMATS.merge! (:default => "%d.%m.%Y") ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.merge! (:default => "%d.%m.%Y %H:%M") in my enviroment. Everything is working

Hi Marna, This is a condition that the function cannot handle. It would be possible to reformat the result based on the time intervals, but the stretch_df function doesn't try to interpret the values, just stretches them out to a wide format. Jim On Wed, May 2, 2018 at 9:16 AM, Marna Wagley <marna.wagley at gmail.com> wrote: > Hi Jim, > The data set is correct. I took two

Can anyone give me some insight as to why the ActiveSupport::CoreExtensions::Float::Time method ''years'' is being deprecated? I have an application managing contracts and being able to manipulate and report on them based on the number of years the contract lasts, is very convenient. -- Posted via http://www.ruby-forum.com/. --~--~---------~--~----~------------~-------~--~----~

Hi Jim, Thank you very much for your suggestions. I used it but it gave me three sites. But actually I do have only two sites "Id_X" and "Id_y" . In fact "A" is repeated two times for "Id_X". If it is repeated, I would like to take the first one among many repeated values. dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label =

Hi Jim, The data set is correct. I took two readings from the "SITE A" within a short time interval, therefore I want to take the first value if there are repeated within a same group of "timeGroup". Therefore I wanted following FinalData1 B1 B2 id_X "A" "B" id_Y "A" "B" thanks, On Tue, May 1, 2018 at 4:05 PM, Jim

Hi Marna, I think this is due to having three rows for id_X and only two for id_Y. The function creates a data frame with enough columns to hold the greatest number of values for each ID variable. Notice that the SITE_n columns contain three values for id_X (A, A, B) and two for id_Y (A, B, NA) as there was no third occasion of measurement for the latter. Even though there are only two _values_