similar to: quick q on script/generate scaffold

Hello, I have Oracle XE installed. I have a table USERS. When I try to generate a scaffold it gives me this error. I tried also with Mysql and it worked. E:\radrails\projects\MPS>ruby script\generate scaffold user exists app/controllers/ exists app/helpers/ create app/views/user exists test/functional/ dependency model exists app/models/ exists

Hi everyone, I''m a rails & ruby nuby, and this is my first post to the list. Here''s my environment in case it helps diagnose my problem: Ruby version 1.8.4 (powerpc-darwin8.6.0) RubyGems version 0.8.11 Rails version 1.1.2 Active Record version 1.14.2 Action Pack version 1.12.1 Action Web Service version 1.1.2 Action Mailer version 1.2.1 Active Support version 1.3.1 I did

Since I upgraded from Rails 0.13.1 to 0.14.1 "generate scaffold <Model> <Controller>" doesn''t take any notice of the controller parameter. Anyone else suffering from this? E.g.: C:\Ruby\work\test>ruby script\generate scaffold User Admin exists app/controllers/ exists app/helpers/ create app/views/users exists test/functional/

Hi... I have list.rhtml file default generated by scaffold for user table. This file displays list of all user table rows. Inside this file I want to display the list of the all the rows from my anothe table (stores). How to do that? I tried with following inside my above list.rhtml. ================== <% for store in @stores %> <tr> <% for column in Store.content_columns

All, I have need of getting at some underlying database metadata for ActiveRecord descendants. Does anyone know if I can get access to the following attributes of the underlying column for a given ActiveRecord object: Is it a currency object? Is it nullable? Is it a signed int? Is it searchable? Column length Column name Column precision Column scale Column data type - how specific can I get

Apparently a scaffold creates at least one instance variable for views to use, and if I override the scaffold then I must also explicitly create that instance variable for the view. I''d like to know exactly what work is performed by the scaffold so that I can know this when over-riding the view. (OR, is it that the controller makes these variables available by default?..) EXAMPLE:

Hi all, Got a Win2k3 Server box (but this has been verified not to work also on WinXP Pro SP2) with: Ruby 1.8.2 Rails 1.1.4 PostgreSQL 8.1 The generate\scaffold script fails to generate the files inside the app/model/views directories. It actually generates the view directory but fails to produce any files. The same thing works perfectly when I''m targetting MySQL. So is this normal

I''ve created several different Rails applications but I''m running into the same trouble with each one. Lets say I create an app called Test. I type ''rails test'' and it generates the directory for me. Now I edit my database.yml file. Then I create a database with Postgresql by typing createdb test. Now I go into Postgresql by typing ''psql

Hello there, I am a Ruby on Rails newbie, and have been reading the book, "Agile Web Development with Rails", by Dave Thomas. Seem to be stuck on page 57, when trying to invoke "ruby script/ generate scaffold Product Admin"... My depot/config/database.yml file''s contents are: development: adapter: mysql database: depot_development socket:

Hi all, I''m new to rails after having used perl for most of these things, and am trying to get my head around the generate script for a project playing around with. If I do: ./scripts/generate controller Device I get app/controllers/device_controller.rb where I can then add: scaffold :device However, if I want to actually generate the scaffolding so I can make some changes:

Hi! Sorry for the newbie question... I''m following the depot example in AgileWebDevelopmentWithRails. Stangelly, generating scaffolding using the command (page 53): ./script/generate scaffold Product Admin does not generate any .rhtml file, but just: exists app/controllers/ exists app/helpers/ exists app/views/admin exists test/functional/

Preface: I''m trying to find my way through the "Build Your Own Ruby on Rails Web Application" book. I''m completely new to programming and am having a hard time figuring out the differences between rails 2.0.2 and what''s in the book so please forgive me if this is a stupid question. I''m confused because I finally thought I''d figured out the

there are some things on a scaffold that i would like to use without the whole thing. is it better to generate one and then cut it down to only what you''ll use? are all of the things in a scaffold available to just build by hand? for instance, i have a scaffold for my users. in the list action, it has @user_pages, so that you can put @user_pages.current.next or something like that -

I am attempting to generate scaffolds on legacy tables that have underscores in the name. Scaffold does not see the underscore. I have tried a backslash escape but it no work. I have looked around but i cannot find a way to make it work. It''s like this: c:\railroad>ruby script/generate scaffold FOO_BAR exists app/controllers/ exists app/helpers/ create

I know the scaffold generator is really only useful for beginners and/or very the preliminary state of a project, but I find that I use it a lot (especially, since I am still a beginner). There are a couple of things I find myself tweaking (or wanting to tweak, but never getting around to tweaking) each time I generate a new scaffold: 1) Change the layout from blah.html.erb to

How do I get scaffold to generate code for a table whos name is not plural of the modelname I give to it. I.E., If I have an existing database, and wish to generate scaffold code for existing tables, is this possible??? _______________________________________________ Rails mailing list Rails-1W37MKcQCpIf0INCOvqR/iCwEArCW2h5@public.gmane.org http://lists.rubyonrails.org/mailman/listinfo/rails

Would anybody know why I get this error from this bit of code: class LocationsController < ApplicationController def index scaffold :locations end end This is the way that is demonstrated in the screencast for creating a quick scaffold. I have done this before. However, I come back to working with Ruby after about a month on something else and now it gives this error. Any

I am trying to make a barebones login system based on this example (which in turn is just standard RoR login) but when I enter a user name and password, it says the login is unsuccessful every time. I am not sure where I am going wrong. Here is all relevent information CREATE TABLE `users` ( `id` int(6) unsigned NOT NULL auto_increment, `login` varchar(20) NOT NULL default

I''m doing very well with the Hibbs Rolling on Rails tutorial. I have an easy question for my personal notes. I''m coming up with a simple framework of steps for creating a basic database. It includes the following maxims to make original app creation easy: app_name = MySQL database name SQL_tablename = model_name model_name = controller-name Is this going to work for getting

Is there any reason that foreign key fields do not show in any of the scaffold views ? project table: id serial primary key, category_id integer, user_id integer, name varchar, morestuff varchar foreign key (category_id) references categories(id), foreign key (user_id) references users(id) scaffold generated views only show name, morestuff fields