Displaying 20 results from an estimated 11000 matches similar to: "models and views"
2007 Jul 25
3
aggregate.ts
Consider the following scrap of code:
> x<- ts(1:50,start=c(1,11),freq=12)
> y <- aggregate(x,nfreq=4)
> c(y)
[1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141
> y
Error in rep.int("", start.pad) : invalid number of copies in rep.int()
> tsp(y)
[1] 1.833333 5.583333 4.000000
So we can aggregate into quarters, but we cannot print it using
2007 Jul 25
3
aggregate.ts
Consider the following scrap of code:
> x<- ts(1:50,start=c(1,11),freq=12)
> y <- aggregate(x,nfreq=4)
> c(y)
[1] 6 15 24 33 42 51 60 69 78 87 96 105 114 123 132 141
> y
Error in rep.int("", start.pad) : invalid number of copies in rep.int()
> tsp(y)
[1] 1.833333 5.583333 4.000000
So we can aggregate into quarters, but we cannot print it using
2008 Aug 18
1
Converting monthly data to quarterly data
Dear R users,
I have a dataframe where column is has countries, column 2 is dates
(monthly) for each countrly, the next 10 columns are my factors where I have
measurements for each country and for each date. I have attached a sample
of the data in csv format with the data for 3 countries.
I would like to convert my monthly data into quarterly data, finding the
mean over 3 month periods for
2006 Jun 30
2
Subscription Payment Model
Ok, I''m new to the world of actually charging for software, and it''s
taken me a full month to decide how to charge in a way that doesn''t make
me sleep with difficulty at nights. :) If someone can look at this and
verify I''m on the right track or give any hints/tips, I''d greatly
appreciate it.
Basically, I want each user to be able to apply
2004 Jul 01
2
[gently off topic] arima seasonal question
Hello R People:
When using the arima function with the seasonal option, are the seasonal
options only good for monthly and quarterly data, please?
Also, I believe that weekly and daily data are not appropriate for seasonal
parm estimation via arima.
Is that correct, please?
Thanks,
Sincerely,
Laura Holt
mailto: lauraholt_983 at hotmail.com
download!
2008 May 31
1
Representing 'Date' as 'Year - Quarter'
I have financial data on a a set of firms, with a quarterly period
(fundamental data). The data spans 10 years, and four quarters per
year. The present file (.csv) reads the Date columns as "200706" for
the second quarter of 2007; "199809" for the third quarter of 1997.
Is there a way I can convert it to something like "2007 Q2", "1998 Q3"?
I am aware of
2012 Nov 09
2
Creating yyyymm regexp strings on the fly for aggregation.
Folks,
This question is somewhat related to a previous posting of mine.
I just can't seem to create a generic solution.
Here is a function that I found searching around the internet:
splitIt <- function(x, n) {split(x, sort(rank(x) %% n))}
I use it like so:
> splitIt(1:12, 2)
$`0`
[1] 1 2 3 4 5 6
$`1`
[1] 7 8 9 10 11 12
Or
> splitIt(1:12, 4)
$`0`
[1] 1 2 3
$`1`
[1] 4 5 6
2005 Feb 02
4
(no subject)
can you recommend a good manual for R that starts with a data set and gives
demonstrations on what can be done using R? I downloadedR Langauage
definition and An introduction to R but haven't found them overly useful.
I'd really like to be able to follow some tutorials using a dataset or many
datasets. The datasets I have available on R are
Data sets in package 'datasets':
2013 Oct 07
2
Android App for Icecast Administration
Hi Thomas,
> In addition to that you can extract additional mount point related
> information (also in XML format!) from other virtual files in /admin/ as
> mentioned in the documentation.
I had a look at
http://www.icecast.org/docs/icecast-2.3.3/icecast2_stats.html - is it
possible to get the aggregate time of listener connections from the
admin interface, or only by parsing the
2017 Oct 06
2
Time series: xts/zoo object at annual (yearly) frequency
Hi,
I'd like to make a time series at an annual frequency.
> a<-xts(x=c(2,4,5), order.by=c("1991","1992","1993"))
Error in xts(x = c(2, 4, 5), order.by = c("1991", "1992", "1993")) :
order.by requires an appropriate time-based object
> a<-xts(x=c(2,4,5), order.by=1991:1993)
Error in xts(x = c(2, 4, 5), order.by =
2005 Jul 25
1
Convert quarterly data to monthly data
Hi,
I am new to use R, but can anyone tell me how to
tranform quarterly data to monthly data? I know SAS
has this procedure, so may I assume it is also
available in R?
Thanks a lot!
Ed
2013 Feb 20
1
To convert a quarterly data to a monthly data.
Hello,
I have a data set has
2001Q1 100
2001Q2 101
2001Q3 120
2001Q4 103
...
And would like to convert it to a monthly data. i.e.
200101 XXX
200102 XXX
200103 XXX
2011 Apr 16
1
Matching Problem: Want to match to data.frame with inexact matching identifier (one identifier has to be in the range of the other).
Hello R-Community,
I have the following matching problem: I have two data.frames, one
with an observation every month (per company ID), and one with an
observation every quarter (per company ID; note that quarter means
fiscal quarter; therefore 1Q = Jan, Feb, Mar is not necessarily
correct and also, a fiscal quarter is not necessarily 3 month long).
For every month and company, I want to get the
2013 Oct 07
2
Android App for Icecast Administration
Hi Thomas,
> As this is historical data I don't see any reason why you'd try to get
> this through the web interface.
The use case is when there is an Icecast service, but there might not be
shell access to that server. So we have a stats interface in Airtime
that only needs the admin password to create a listener count graph
against time.
> Chances are, that there you'd
2008 Jun 29
1
Calculating quarterly statistics for time series object
I have time series observation on daily frequencies :
library(zoo)
SD=1
date1 = seq(as.Date("01/01/01", format = "%m/%d/%y"), as.Date("12/31/02", format = "%m/%d/%y"), by = 1)
len1 = length(date1); data1 = zoo(matrix(rnorm(len1, mean=0, sd=SD*0.5), nrow = len1), date1)
plot(data1)
Now I want to calculate 1. Quarterly statistics like mean, variance etc
2009 Jul 10
1
row data manipulation in data frame
R users,
I am a beginner in R. I have a time series data on various macro variables
like GDP, unemployment rate, consumer spending, imports, exports etc. I am
interested in calculating year over year growth rate for each of those
variables. Is there any simple function in R for carrying out such repeated
operations.
I would like to carry out growth rate between two consecutive yearly row
data
2008 Jan 06
1
aggregate.ts help
Hi,
I have a ts object with a frequency of 4, i.e., quarterly data, and I would
like to calculate the mean for each quarter. So for example:
> ts.data=ts(1:20,start=c(1984,2),frequency=4)
> ts.data
Qtr1 Qtr2 Qtr3 Qtr4
1984 1 2 3
1985 4 5 6 7
1986 8 9 10 11
1987 12 13 14 15
1988 16 17 18 19
1989 20
If I do this manually, the mean
2012 Feb 21
1
Questions on Data reading using zoo package
Hello,
I try to handle the data using read.csv , zoo and aggregate functions.
The data contains NA values. After aggregating monthly data into quarterly
data, all data become NA. Is it because I don't properly aggregate the data
in the presence of NAs? What can I do?
Another problem is that the date in month is presented in Chinese (My OS
is in Chinese.) How can I set the default
2008 Aug 19
0
Converting monthly data to quarterly dataMonday, August 18, 2008 11:38 AM
Dear Gavin,
This is really great, thank you! I created some long loops to get rid of
extra months at the beginning and the end of my data but your code is great
for putting it then together quarterly.
thanks again,
Denise
On Mon, 2008-08-18 at 14:31 +0100, Denise Xifara wrote:
> Thank you very much Stephen, but how will aggregate deal with months that
> fall outside annual quarters? eg,
2004 Jul 07
1
Daily time series
Hi,
I'm dealing with time series with 1 observaton for day
(data sampled daily). I will create a ts object using
that time series and the function ts().
In ts() help is written:
The value of argument 'frequency' is used when the
series is sampled an integral number of times in each
unit time interval. For example, one could use a value
of '7' for 'frequency' when