similar to: Development Project.

Sorry for the second post. I just wanted to clarify location. I would prefer someone local (1-2 hours away maybe) to the Toronto, Canada area. I don't mind hearing from other areas as I haven't completely ruled out a 100% remote team-up if I can't find the local help or can be convinced tools for colaboration work well. Job Type: Contract Location: Toronto, ON, CANADA; Job

Any and all attempts to connect to our samba server, packaged in the redhat RPM found on samba.org, have failed. The allow statement is set to localhost, x.y.z. where x.y.z is our class C(ended with a period, as per the online help in SWAT.) Local connections via smbclient work beautifully, but connections from any other machine fails. I've followed the troubleshooting procedure to the

Dear all -- I want to compute weighted.mean() for grouped rows. Data frame extract is just below. For each Key, I want the mean of IAC weighted by Wt. DP0[1:20,] Key IAC Wt 2 C3-PD030020050.PD030020050.3.12.3.0 0.765 0.8590000 3 C3-PD030020050.PD030020050.3.12.3.0 0.764 0.8449651 4 C3-PD030020050.PD030020050.3.12.3.0

Dear all -- I have a data frame containing data related to heat gain through windows. The general form is ... Key ProfA IAC <many other numeric columns> AAA 0 .7 AAA 10 .6 AAA 0 .66 AAA 20 .45 (more AAA rows) (then AAB rows) 'Key' identifies the physical configuration ... rows with a given Key contain data for same window under various

Hi All! I am interested in testing whether the means for the data I am investigating are equal to a specific value - let's say 0.01. I have already run a one-way ANOVA and know that the differences in the means are not significant, so now I want to know what values the means take on. "otestme" is the data I am working with (it would be hard for me to get into a form that would be

I am trying to use the friedman.test() on a data frame, d, but I am receiving the following error message: > d AW HS IAC WA 1 6 8 3 5 2 2 2 3 6 3 7 7 8 3 4 8 5 4 5 .... 20 2 5 2 7 21 7 7 6 7 22 7 8 6 8 23 6 8 4 5 24 5 7 5 2 > friedman.test(d) Error in any(is.na(groups)) : argument "groups" is missing, with no default I think I

Ugh. With MAKE_KERBEROS5=yes, on a recent STABLE, I get the following trying to use Kerberized telnet: # telnet -l test big.x.kientzle.com Trying 66.166.149.54... Connected to big.x.kientzle.com. Escape character is '^]'. [ Trying mutual KERBEROS5 (host/big.x.kientzle.com@X.KIENTZLE.COM)... ] Bus error (core dumped) Fortunately, it's pretty easy to track down: (gdb) up #2

This is a Contract or PERM role here in Charlotte. You can work from the office in Boca Raton, FL but on-site is required. Email me at seth.hildebrand-/OJdjVubIPyZEO45NX+DXRZCeNDtXRbv@public.gmane.org if you are interested in the role. Rails Developer Core Duties and Responsibilities: Maintain and extend our social networking platform Work with designer to implement web UI with CSS and

Hi All! I have been messing around with this problem for about a week but to no avail! The following data has been cut down in order to make my question reproducible. The alldat data frame includes 2 columns: 1 date column and 1 factor column (equity names)).

Hi everybody, I'm working on the very messy data, I have tried to clean it up in SAS and SAS/IML but there is not enough info on how to handle certain things in SAS so I have turned to R. The thing itself should be rather simple, so i was wondering if someone could help me out. The original .csv has ([1] 7138 6338 ) dimensions with funds with the corresponding dates and observations for each

Hi everyone, My name is Jennifer Turliuk. I''m currently in Santiago, Chile for the next 6 months as part of the Startup Chile program. I think you may be able to help me out. We are looking to bring on a developer ASAP (see description below). We''d love to hear from you. Or, if you know of anyone that may be interested, we''d be very grateful if you would pass this

Dear list, I encounter an error when I try to use ddply to generate means as follows: fun3<-structure(list(sector = structure(list(gics_sector_name = c("Financials", "Financials", "Materials", "Materials")), .Names = "gics_sector_name", row.names = structure(c("UBSN VX Equity", "LLOY LN Equity", "AI FP Equity",

Am 02.07.23 um 18:01 schrieb Duncan Murdoch: > This SO post: https://stackoverflow.com/q/76583828 describes a strange R > CMD check error. Depending on the contents of a comment in one of the > examples sections of a help page, an error like this could be triggered: > > > base::assign(".dptime", (proc.time() - get(".ptime", pos = >

Hi John: Thanks! Below is the data using your suggestion. I used "ggplot" to make a graph. I am not too happy with it. I am looking for something simpler and cleaner. Plot is attached. I also tried "lattice" package, but nothing got plotted with "xyplot" command, because it is looking for a numeric variable on x-axis. ggplot(TrialData4, aes(x=Income, y=Percent,

Btw, I think "lattice" graphics will provide a better solution than "ggplot", because it puts appropriate (space saving) markers on the axes and does axes labels well. However, I cannot figure out how to do it in "lattice". On Thu, 6 Jul 2023 at 15:11, Anupam Tyagi <anuptyagi at gmail.com> wrote: > Hi John: > > Thanks! Below is the data using your

Basic question but still learning .... How do I plot two lines (f$equity and f$bh.equity) on one of the three graphs under mfrow ? I tried putting brackets around the first plot and lines command but that didn't work. par(mfrow=c(3,1)) {plot(f$Date,f$equity, col="blue", type="l", main="equity") lines(f$bh.equity, col="gray")} plot(f$Date,f$indicator,

Dear R-ers, My aggregation saga continues. Using the following sequence, I can calculate any statistic for row groups and merge the result back to all associated rows ... > WM = by( D60, D60[ "KeyProfA"], FUN=function(x) weighted.mean( x$IAC, x$Wt)) > D60$IAC.WM = as.numeric( WM[ D60$KeyProfA]) > class( WM) [1] "by" Questions ... 1) Is this a reasonable way

Hallo Anupam I do not see much difference in ggplot or lattice, they seems to me provide almost identical results when removing theme part from ggplot. library(ggplot2) library(lattice) ggplot(TrialData4, aes(x=Income, y=Percent, group=Measure)) + geom_point() + geom_line() + facet_wrap(~Measure) xyplot(Percent ~ Income | Measure, TrialData4, type = "o", pch = 16, as.table =

Hi, I am downloading Bloomberg data from R. This data will be stored in a zoo object by default. The command is dat<-blpGetData(con,c("NOK1V FH Equity","AUA AV Equity"),"PX_OPEN",start=as.chron(as.Date("12/1/2006", "%m/%d/%Y")),end=as.chron(as.Date("12/28/2006", "%m/%d/%Y"))) Here I am downloading the data for two

Thanks! You are correct, the graphs look very similar, except ggplot is scaling the text font to make it more readable. Is there a way to scale down the x-axis labels, so they are readable? On Fri, 7 Jul 2023 at 12:02, PIKAL Petr <petr.pikal at precheza.cz> wrote: > Hallo Anupam > > I do not see much difference in ggplot or lattice, they seems to me > provide almost identical