Displaying 20 results from an estimated 400 matches similar to: "habtm "AND" find conditions"
2006 Mar 19
3
Table belongs_to either of two other tables?
Suppose I have a site about books and authors, and users can leave
comments on either a book or an author.
I''d want to have a table called "comments", which could belong to either
an author OR a book.
In my structure I wouldn''t be sure whether to include an "author_id" or
a "book_id", or both.
What would be the best way to handle this
2005 Mar 08
19
find_by_sql ON STEROID possible?
find_by_sql BREAKS THE OOP BEAUTY and perhaps we can solve that.
NAMING CONVENTIONS can perhaps make find_by_sql much more clever.
lets imagine that relation:
publishers <- books <-> authors_books <-> authors -> universities (can''t find
something else than university for that last association :) )
imagine we want to fetch every book and every associated
2005 Dec 29
3
Verification problems
Hello,
Hope this isn''t a newbie question - but I don''t seem to be able to find
relevent information elsewhere.
I am having trouble getting the following to work:
Schema
======
ActiveRecord::Schema.define(:version => 1) do
create_table "authors", :force => true do |t|
t.column "name", :string
end
create_table "books", :force =>
2015 Apr 14
5
[LLVMdev] [cfe-dev] A problem with names that can not be demangled.
Adding llvm-dev as that might be a more suitable audience for this
discussion.
(& I know Lang's been playing around with the same problem in the Orc JIT,
so adding him too)
Is there any basis/reason to believe that the .X suffix is a better, more
principled one than straight X? Is that documented somewhere as a thing the
demangling tools will ignore?
On Tue, Apr 14, 2015 at 12:06 PM,
2013 Mar 11
2
how to convert a data.frame to tree structure object such as dendrogram
I have a data.frame object like:
> data.frame(x=c('A','A','B','B'), y=c('Ab','Ac','Ba','Bd'))
x y
1 A Ab
2 A Ac
3 B Ba
4 B Bd
how could I create a tree structure object like this:
|---Ab
A---|
_| |---Ac
|
| |---Ba
B---|
|---Bb
Thanks,
Zech
[[alternative HTML version deleted]]
2006 Jun 26
2
How can I sort options in a select box?
Pretty much a newbie here, looking for help on select boxes in forms....
Is there any way in the view to sort the options of a drop-down select
box?
My current code (within a larger _form.rhtml file) is:
<div class="form-element">
<label for="asset_location_id">Location</label>
<%= select ''asset'', ''location_id'',
2009 May 24
6
belongs_to not saving foreign key
Under Rails 2.3.2 using a completely brand new project, I have 2
models:
class Author < ActiveRecord::Base
# name:string
end
class Book < ActiveRecord::Base
# title:string
belongs_to :author # author_id
end
And a simple test where i create a Book with an Author using the
belongs_to and then update the foreign key directly:
require ''test_helper''
class BookTest
2006 Aug 02
2
many-to-one relationship, do I need a second table?
Ok, to keep things short. Im wondering if I need a secondary
relationship table to handle my many-to-one relationships. Here is an
example of what I''ve written down. For instance say I want to find all
of the people in a given location.
class Location < AR:Base
has_many :people
end
class Person < AR:Base
belongs_to :location
end
My SQL tables look like:
CREATE TABLE
2006 Mar 31
2
A.R. Associations problem
Hello,
I''m learning A.R Associations by creating a simple forum that consists
of 3 tables: ahuthors, topics and posts. This is the schema:
class AddAuthorAndTopicAndPostTables < ActiveRecord::Migration
def self.up
create_table :authors do |t|
t.column :username, :string
t.column :email, :string
t.column :created_on, :datetime
end
create_table
2005 Apr 20
4
Error in tutorial or sintax changed?
Hi,
In this tutorial
http://wiki.rubyonrails.com/rails/show/HowtoUseJoinsWithFindAll
it sad:
sql =<<SQL
SELECT articles.*, authors.name AS author_name
FROM articles
LEFT JOIN authors ON author_id = authors.id
SQL
and this return
*app/controllers/media_controller.rb:366: can''t find string "SQL"
anywhere before EOF*
what is wrong? the tutorial or ruby changed?
please,
2006 Mar 16
4
Table Relationships Problems.
I have the following tables setup:
locations
:id
:name
systemmessages
:id
:name
systemmessage_validtimes
:id
:name
:systemmessage_id
:location_id
:start
:end
The systemmessage_validtimes has a ''has_many'' relationship with
systemmessages, meaning that there could be many valid times for each
system message.
@systemMessage = Systemmessage.find(1)
E.g. I
2006 Jun 13
6
Dead horse: validates_associated
Regarding validates_associated...
Let''s say I have:
article belongs_to author
But for whatever reason, I want an article to also be written
anonymously and therefore not require an author. Then I have:
Article:
belongs_to :author
validates_associated :author
But I DON''T have validates_presence_of. What I want to do is validate
that an author is valid --if it is
2006 Mar 04
10
Help setting up relationships needed
This is a bit of a long question, but to those of you with some
experience, it should be fairly simple I think.
I have a notes page that should list all notes the user has entered for
all books chronologically like this.
Book One: This is the note.
Book Four: This is the note.
Book One: A different note, entered later.
Right now my models are:
User
has_many :books
Book
has_many
2006 Jan 22
11
ActiveRecord find
Suppose I have three tables - authors, posts and topics.
Every post have a topic and every topic has an author, so I have
posts.topic_id and topic.author_id. When the author is guest (not
registered), author_id is nil.
I need to find all the posts (in one query) where every post have all
the information of the topic and the auther, so if p is one of those
posts I could get the name of the
2008 Jan 10
2
Getting results matching with an array?
I have an array authors=[1,3,7] and I want to get all the posts that
match with any or all of these results.
something like...
posts = Post.find(:all, [:conditions => ''''author_id = ?'', authors])
of course this wont work but I need something like it that works..
thanks
--
Posted via http://www.ruby-forum.com/.
--~--~---------~--~----~------------~-------~--~----~
2010 Dec 14
5
Build associated model confusion
I''m new to Rails3, and I''m just trying to get one last thing to work
before I call it a night. The situation is the following (please if
the code is horrible, just let me know, still learning):
I want to log a dive. I might have a new location on that dive at
which point I have to create a new Location, and then create the dive.
A dive has_one location. A location has_many
2010 Jun 29
3
belongs_to. Association methods don't pass data to DB
Hi.
I have a problem with the association methods which passed to a model
through a belongs_to declaration. Here''s an illustration of the issue:
GIVEN:
# migration
class CreateArticlesAndAuthorsTables < ActiveRecord::Migration
def self.up
create_table :articles do |t|
t.text :title
t.integer :author_id
end
create_table :authors do |t|
t.text
2006 Apr 09
6
Write/Display AR query as Grouped Results?
I''ve got a publications table that contains an author_id foreign key and
a pubrole_id foreign key. What I want to do is query the DB using AR so
that I can get a list of all publications that belong_to a particular
author, and group the results by the pubrole.role_name (Author, Joint
Author, Editor, etc.) so that the results look something like:
Author
book1 info
book2 info
etc.
2006 Jan 18
2
categories/recipes & books/descriptions - has_many vs has_one => id question
People,
In the cookbook eg, categories has_many recipes but in a book eg, book
has_one description - doesn''t that mean that the id of the description
should be the same as the id of the book (instead of having it''s own
"description_id" in the book table?
Thanks,
Phil.
--
Philip Rhoades
Pricom Pty Limited (ACN 003 252 275 ABN 91 003 252 275)
GPO Box 3411
Sydney
2007 Jun 02
7
I''m really bad at controllers, help please.
Hey,
Sorry for so many questions - I''m really bad at this right now.
I''m trying to cover the following code w/ rspec
def index
if params[:user_id]
@user = User.find(params[:user_id])
@messages = @user.messages
end
end
So basically what I''m doing is listing all the messages for a user,
provided there is an id parameter.
describe