similar to: Compiling OCFS 1.0.13 on kernel 2.6.8?

Sorry for cross posting, but I somehow came to think that this question might possibly be more suitable in this mailinglist. I am currently fiddeling around with Fedora Core 2. Does anyone of you have any pointers on where to start reading to compile OCFS 1.0.13 on a 2.6.8 kernel? Is it at all possible? Best, //magnus -----Urspr?ngliche Nachricht----- Von: Magnus Lubeck [mailto:ml@inwork.ch]

Hi all, Sorry to break in, but I find this thread a bit interesting. Jeram: I'm not very familiar with HP storage and cannot find too much info on the EVA 6000 array. Is it related to the EVA 5000 somehow, or is it a NAS array? In any case, how is the array configured. If the algorithm for hartbeat is as described earlier (36 sector reads and one write per second (per host???)) then you

Hola a todos. Ya he escrito sobre esto pero vuelvo a no ser capaz de resolver una cosa Tengo este archivo año   mes      fecha  puerto           barco   origen       arte            2007 enero 2007-01-04 Ribeira  juan        Norte     PAREJA      2007 enero 2007-01-04 Ribeira    luis        -Norte     BETA    2007 enero 2007-01-04 Ribeira  pedro     Norte     PAREJA      2007 enero

Dear R forum Suppose I have a data.frame df = data.frame(id = c(1:6), x = c(15, 21, 14, 21, 14, 38), y = c(36, 38, 55, 11, 5, 18), x.1 = c(15, 21, 14, 21, 14, 38), z = c("D", "B", "A", "F", "H", "P")) > df   id  x  y    x.1 z 1  1 15 36  15 D 2  2 21 38  21 B 3  3 14 55  14 A 4  4 21 11  21 F 5  5 14  5  14 H 6  6 38 18  38 P

Dear R forum I have one stupid question, but I have no other solution to it in sight? Suppose some R process creates graphs etc alongwith main output as data.frame e.g output1 = data.frame(bands = c("A", "B", "C"), results = c(74, 108,  65)) I normally save this output as some csv file. But I need to save this output as some image (I understand this is weird,

Dear R forum I have a data.frame df = data.frame(dates = c("4/15/2013", "4/14/2013", "4/13/2013", "4/12/2013"), values = c(47, 38, 56, 92)) I need to to create a vector by repeating the dates as "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013,  "Current_date", 4/15/2013, 4/14/2013, 4/13/2013, 4/12/2013, Current_date,

Apologies if this has been asked before. I am having trouble understanding the R mailing list never mind R! I am relatively new to R having migrated from Minitab and SPSS. I have managed to do some more complicated statistics such as hierarchical partitioning of variance on an 80,000 record dataset but have to admit that drawing a simple bar plot I could do by hand is proving extremely

Buenos dias a todos. Tengo este Barchart con dos tipos de datos. Desembarcado y Muestreado. Como los datos de Desembarcado son mucho mayores que los de Muestreado, estos ultimos datos apenas si se aprecian en la grafica. Lo que se me ocurre es cambiar la escala de este eje. ¿alguien sabria como hacerlo? O alguna otra sugerencia claro. Muchisimas gracias a todos los que me estan ayudando Jose Luis

Dear R forum, I have a data.frame as defied below - df = data.frame(names = c("C", "A", "A", "B", "C", "B", "A", "B", "C"), dates = c("4/15/2013", "4/13/2013", "4/15/2013", "4/13/2013", "4/13/2013", "4/15/2013", "4/14/2013",

Dear R forum I have a data.frame df = data.frame(currency_type = c("EURO_o_n", "EURO_o_n", "EURO_1w", "EURO_1w", "USD_o_n", "USD_o_n", "USD_1w", "USD_1w"), rates = c(0.47, 0.475, 0.461, 0.464, 1.21, 1.19, 1.41, 1.43))   currency_type     rates 1      EURO_o_n   0.470 2      EURO_o_n   0.475 3       EURO_1w   0.461

Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the

Dear Forum, I have a data frame as  mydat = data.frame(basel_asset_class = c(2, 8, 8 ,8), defa_frequency = c(0.15, 0.07, 0.03, 0.001)) > mydat   basel_asset_class defa_frequency 1                 2          0.150 2                 8          0.070 3                 8          0.030 4                 8          0.001 I need to get the subset of this data.frame where no of records for the

Dear R forum I have a following vector of random no.s x = runif(100, 0.01, 0.99)  [1] 0.47212037 0.77867992 0.33947474 0.93369035   [5] 0.03720073 0.79307831 0.81801835 0.92710688 ................................................. I need to count the random no. falling in the range (0 - 0.10), (0.10 - 0.20), (0.20 - 0.30)..upto (0.90 - 1) Thus, I need to have a data frame as

Dear R forum, (Pl note this is not a finance problem) I have two data.frames as currency_df = data.frame(current_date = c("3/4/2013", "3/4/2013", "3/4/2013", "3/4/2013"), issue_date = c("27/11/2012", "9/12/2012", "14/01/2013", "28/02/2013"), maturity_date = c("27/04/2013", "3/5/2013",

Dear R forum I have a vector say as given below df = c("F", "C", "F", "B", "D", "A", "D", "D", "A", "F", "D", "F", "B",    "C") I need to find (1) how many times each element occurs? e.g. in above vector F occurs 4 times, C occurs 2 times etc. (2)

Dear R forum, The example below is just an indicative one and I have constructed it. My real life data and conditions are different. I have a data.frame as given below mydat = data.frame(A = c(19, 20, 19, 19, 19, 18, 16, 18, 19, 20), B = c(19, 20, 20, 19, 20, 18, 19, 18, 17, 16)) if (length(mydat$A) > 10) { stop("A has length more than 10") }else if (max(mydat$B) > 18) {

Buenos dias a todos quisiera meter dos o mas "dotplot" dentro de la misma gráfica. Lo intento con par(mfrow=c(2,2)), pero no me lo permite. Sí puedo hacerlo en cambio con los Boxplot. Es posible hacerlo pero me falta algun detalle, o simplemente no se puede?? Muchas gracias Jose Luis [[alternative HTML version deleted]]

Hi I am testing Ruby 1.9.2 and Rails 3. Has anybody encountered this error: web katz$ gem install rspec-rails ************************************************** Thank you for installing rspec-rails-1.3.2 If you are upgrading, do this in each of your rails apps that you want to upgrade: $ ruby script/generate rspec Please be sure to read History.rdoc and Upgrade.rdoc for useful

Hi, I have a good grasp of grep() and gsub() for finding and extracting character strings. However, I cannot figure out how to use a search term that is stored in a variable when the search string is more complex. #Say I have a string, and want to know whether the last name "Jannings" is in the string. This is done by names=c("Emil Jannings") grep("Emil",names)

I am trying to draw a bar chart with standard error bars for two groups. I was struggling in R so have now managed to get rcmdr up and running on my mac (although the help frequently crashes, everything else seems fine, if a bit sluggish; wouldn't use it for stats). This has allowed me to very easily create a plot of the means and standard errors BUT-does anyone know if it is